A field-manual for railroad engineers

Survival, Water, Medical Field Manuals

Military Manuals

Nagle, J. C. (James C.), 1865 1927

Document text

REESE   LIBRARY 


UNIVERSITY  OF  CALIFORNIA, 


FIELD-MANUAL 

FOR 

RAILROAD  ENGINEERS 


BY 

J.  C.  NAGLE,  M.A.,  M.C.E., 

Professor  of  Civil  Engineering  in  the  Agricultural 
and  Mechanical  College  of  Texas. 


FIRST    EDITION. 
FIRST    THOUSAND 


NEW  YORK 

JOHN  WILEY   &   SONS. 
LONDON:    CHAPMAN  &  HALL,   LIMITED, 

1897. 


Copyright,  189? 

BY 

J.   C.   ^AGLE. 


ROBERT    DKUMMOND,    ELKCTROTYPER   AND    PRINTER,    NEW   YORK. 


PREFACE. 


EASE  of  reference  and  uniformity  of  notation  are  essential  in  a 
book  that  is  to  be  consulted  in  the  field.  With  this  in  mind  an 
effort  has  been  made  in  the  following  pages  to  secure  a  systematic 
arrangement  of  the  subject-matter  and  uniformity  of  terms  and 
notation.  Except  for  a  few  cases  Greek  letters  have  been  avoided 
and  a  single  letter  is  used  to  designate  an  angle.  In  so  far  as 
practicable  each  figure  is  intended  to  be  self-explanatory,  so  that 
the  explanations  necessary  in  connection  with  the  problems  have 
been  reduced  to  a  minimum.  Algebraic  equations  stand  each  in 
a  distinct  line,  thus  rendering  them,  more  easily  read. 

A. knowledge  of  the  elements  of  geometry  and  trigonometry  has 
been  assumed,  and  only  in  the  derivation  of  a  few  formulas  in 
connection  with  the  theory  of  transition-curves  will  any  higher 
mathematics  be  needed.  But  these  formulas  may  be  accepted  by 
the  reader  who  is  unfamiliar  with  the  calculus  without  in  any 
way  affecting  his  ability  to  understand  their  applications  or  to 
follow  subsequent  reasoning. 

One  can  most  readily  turn  to  what  he  wants  in  a  book  after  hav- 
ing become  familiar  with  its  contents  in  the  classroom.  Keeping 
this  in  mind  this  book  has  been  written  so  that  it  may  be  used  as 
a  text  as  well  as  for  reference  in  the  field.  Wherever  practicable 
solutions  to  problems  have  been  given  in  a  rigid,  general  form, 
followed  by  illustrative  examples,  so  that  the  student  need  not 
lose  sight  of  the  principle  involved  while  following  the  solution 
for  a  particular  case.  Wherever  approximate  solutions  seemed 
preferable  they  have  also  been  given  and  their  limitations  pointed 
out. 

Free  use  has  been  made  of  the  Table  of  Functions  of  a  One- 
degree  Curve,  thus  reducing  the  labor  of  field  computations.  By 
defining  the  degree  of  curve  with  reference  to  short  chords  for 


IV  PREFACE, 

sharp  curves- -and,  with  tables  of  Radii,  Long  Chords,  :\Iid 
ordinates,  etc.,  based  on  appropriate  equations — the  errors  result- 
ing from  assuming  the  radius  to  vary  inversely  with  the  degree 
of  curve  will  generally  be  found  to  be  quite  small. 

Chapter  I  gives  briefly  the  general  method  of  making  Re- 
connoissance;  Chapter  II  treats  of  Preliminary  Surveys;  while 
Chapter  III  relates  to  Location. 

Chapter  IV,  on  Transition-curves,  follows  the  method  adopted 
by  Professor  Crandall,  and  enables  one  to  locate  the  transition- 
curve  with  rigid  accuracy  where  such  is  necessary.  Approximate 
methods  are  also  given  by  means  of  which  the  curve  may  be  as 
easily  located  as  any  of  the  more  limited  easement  curves  ordi- 
narily met  with. 

Chapter  V,  on  Frogs  and  Switches,  contains  all  that  is  necessary 
for  their  location.  The  formulas  have  been  arranged  to  give  the 
desired  quantities  in  terms  of  the  frog  number  whenever  the  re- 
sulting equations  would  be  easier  of  application  than  the  trigono- 
metric ones  usually  given.  The  turnout  tables  are  unusually  full 
and  give  not  only  the  theoretical  lead  but  the  stub  lead  as  well, 
from  which  the  practical  lead  can  be  at  once  found  when  the 
length  of  switch-rail  is  known. 

Chapter  VI,  on  Construction,  tells  how  to  set  slope-stakes,  and 
gives  simple  methods  for  computing  areas  and  volumes  either 
directly  or  by  the  use  of  tables.  A  short  table  of  prismoidal 
corrections  is  given  for  end  sections  level,  and  also  a  formula  for 
three-level  sections,  by  means  of  which  a  suitable  table  may  be 
computed  if  desired. 

The  tables  at  the  end  of  this  book  have  been  arranged  with  a 
view  to  ease  of  reference,  for,  whatever  the  character  of  the  text, 
the  chief  value  of  a  field-book  must  depend  upon  the  ease  with 
which  the  tables  may  be  consulted  and  upon  their  extent  and 
accuracy.  Table  IX— Functions  of  a  One-degree  Curve  — sepa- 
rates the  logarithmic  functions  on  the  one  side  from  the  natural 
functions  on  the  other  and  will  be  of  assistance  in  locating  these 
tables.  Table  XVI — Transition-curve  Table — reading  lengthwise 
of  the  page,  likewise  serves  to  separate  the  trigonometric  tables 
from  the  miscellaneous  tables  that  follow. 

Some  engineers  object  to  the  use  of  logarithmic  tables  in  the 
field,  but  for  them  the  natural  functions  are  at  hand;  while  for 
those  who  prefer  logarithms  the  five-place  tables  of  logarithmic 
sines,  cosines,  etc.,  will  be  found  easy  to  consult  and  interpolate 
between, 


PREFACE.  V 

All  trigonometric  tables  are  five-place,  and  others  were  carried 
to  as  many  decimal  places  as  their  character  demanded. 

Tables  I,  III,  IV,  and  V  have  been  computed  to  agree  ^vith 
the  definition  of  the  degree  of  curve  requiring  curves  sharper 
than  7°  to  be  run  with  chords  less  than  100  feet  in  length,  as 
described  in  the  text.  Tables  XVII  and  XVIII  were  also  com- 
puted expressly  for  this  book. 

Tables  VI  and  XXVII  are  from  electrotypes  from  Cavhart's 
Field  Book  for  Civil  Engineers  and  were  furnished  by  Ginn  &  Co. 
Electrotypes  of  Tables  II,  X,  XII,  XIII,  XIX,  XX,  XXIV,  XXV, 
XXVI,  and  also  XVI  —  this  last  being  from  Crandall's  book, 
The  Transition  Curve — were  furnished  by  John  Wiley  &  Sons. 

Of  the  others,  some  were  arranged  from  standard  tables  and 
others  adapted  in  part  and  extended  to  increase  their  usefulness. 

It  will  be  noticed  that  vertical  lines  have  been  omitted  wher- 
ever practicable,  thus  rendering  it  easier  to  refer  to  the  tables. 

Acknowledgments  are  due  my  associate,  Professor  D.  W. 
Spence,  for  aid  in  making  the  tabular  computations  and  in  reading 
proof. 

J.  C.  NAGLE. 

COLLEGE  STATION,  TEXAS,  May,  1897. 


CONTENTS. 


CHAPTER  I. 

RECONNOISSANCE.       ^^g^lFORH^ 
ARTICLE  1.    OBJECTS  OF  RECONNOISSANCE— How  MADE. 

SECTION  PAGE 

1.  Relative  Importance  of  the  Work  of  Reconnoissance  and  Location..  1 

2.  Object  of  Reconnoissance 2 

3.  The  Instruments 2 

4.  Use  of  Maps 4 

5.  Making  the  Reconnoissauce ....   4 

CHAPTER  II. 

PRELIMINARY   SURVEYS. 

ARTICLE  2.    OBJECTS;  THE  FIELD  CORPS;  DUTIES  OF  THE  CHIEF. 

6.  Objects  of  Preliminar}-  Surveys  6 

7.  The  Exploration-line 6 

8.  Data  Sought  in  Making  Preliminary  Surveys 7 

9.  The  Field  Corps 7 

10.  The  Chief  of  Party,  Duties  of 7 

ARTICLE  3.    THE  TRANSIT  PARTY. 
A.    DUTIES  OF  THE  MEMBERS. 

11.  Composition  of  the  Transit  Party 8 

12.  The  Transitman 8 

13-17.  Other  Members  of  the  Party £ 

18.  Instruments 9 

B.     TRANSIT  ADJUSTMENTS— THE  VERNIER. 

19.  Kind  of  Transit 9 

20.  To  Adjust  the  Plate  Levels  1C 

21.  Parallax 1C 

22.  To  Adjust  the  Line  of  Collimation 1C 

23.  To  Adjust  the  Standards 11 

vii 


VI 11  CONTENTS. 


SECTION  PAGE 

24.  To  Adjust  the  Level  on  Telescope 12 

25    Direct  and  Retrograde  Verniers  . .    13 

26.  The  Least  Count  of  a  Vernier  „ Id 

27.  To  Read  a  Vernier  14 

C.  ACCESSORIES. 

(1°)  The  Gradienter. 

28.  Description  and  Method  of  Using  Gradienter 14 

(2°)  The  Stadia,  or  Telemeter. 

29.  Principle  of  the  Stadia 15 

30.  Formula  for  Line  of  Sight  Horizontal 15 

31.  Formulas  for  Line  of  Sight  Inclined 1C 

32.  The  Instrumental  Constant,  To  Find 17 

33.  Reducing  the  Notes 17 

D.  FIELD-WORK. 

34.  Station  Numbers 18 

35.  Hubs  or  Plugs 18 

36.  Reference-points    ..'..'.' 18 

37.  Alignment 18 

38.  Form  of  Transit  Notes  19 

39.  Stadia  Methods  for  Preliminary  Surveys 19 

E.      OBSTACLES  IN  TANGENT. 

41.  To  Pass  an  Obstacle  by  Means  of  Parallel  Lines 20 

42.  To  Pass  an  Obstacle  by  Angular  Deflections 20 

43.  To  Measure  across  a  River 21 

ARTICLE  4.     THE  LEVEL  PARTY. 

44.  Make-up  and  Instruments 23 

45.  Work  of  the  Leveler  23 

46.  Work  of  the  Rodman 23 

ADJUSTMENTS  OF  THE  LEVEL. 

47.  To  Adjust  the  Line  of  Collimation 23 

48.  To  Adjust  Che  Level-bubble 24 

49.  To  Adjust  the  Wyes 25 

B.      THEORY  OF  LEVELING. 

50.  True  and  Atmarent  Level 25 

51.  The  Error  Due  to  Curvature 25 

52.  The  Difference  of  Elevation  of  Two  Points 26 

C.      FIELD-WORK. 

53.  The  Datum 27 

54  Bench-marks 27 

55  Work  in  the  Field .  28 


CONTENTS.  ix 


SECTION  PAGE 

56.  The  Level  Notes 28 

57.  Precautions  when  Using  Level  29 

58.  The  Rod 29 

ARTICLE  5.    THE  TOPOGRAPHIC  PARTY. 

59.  Instruments  Used;  Area  to  be  Mapped 30 

60.  Methods  of  Recording  Data 30 

61.  Topographers'  Field-sheets 31 

62.  Use  of  the  Slope-level . .   31 

63.  Cross  section  Rods 3-J 

64.  The  Transit  and  Stadia  in  Topographical  Surveying  32 

ARTICLE  6.    PRELIMINARY  ESTIMATES.  . 

66.  Map  of  Preliminary  Lines  .   32 

67.  The  Profile     33 

68.  Preliminary  Estimates  of  Quantities 33 

G9.  Report  of  the  Locating  Engineer 34 


CHAPTER  III. 

LOCATION. 

• 

ARTICLE  7.    PROJECTING  LOCATION. 

70.  Problems  Involved  in  the  Paper  Location 35 

71.  Hints  Regarding  Methods  of  Projecting  the  Line  35 

72.  The  Curve-protractor 36 

?3.  Work  in  the  Field 37 

ARTICLE  8.    SIMPLE  CURVES. 

A.    DEFINITIONS  AND  FORMULAS. 

74.  Definitions 38 

75.  To  Find  the  Radius  R,  the  Degree  of  Curve  Being  Known 40 

76.  To  Find  the  Length  of  Curve 42 

77.  The  Functions  of  a  One-degree  Curve 42 

79.  To  Find  D,  R  and  C  Being  Known 43 

80.  To  Find  the  Tangent  Distance  T,  /  and  R  Being  Known 43 

81.  To  Find  R,  Given  I  and  T 44 

82.  Given  7  and  D,  to  Find  the  Long  Chord  L  C 44 

83.  Ordinates  from  Chord 45 

84-86.  To  Find  the  External  E 48 

87.  To  Find  R,  E  and  1  Given 49 

88.  To  Find  T,  E  and  1  Given 49 

89.  To  Find  the  Deflection  Offset  from  Chord  Produced 49 

90.  To  Find  the  Tangent  Deflection  Offset 50 

91 .  The  Sub-tangential  Deflection  Offset 51 

92.  To  Find  the  Tangent  Offset  z 52 

93.  Difference  in  Length  of  Arc  and  Long  Chord  , 53 


CONTENTS. 


E       LOCATING  SIMPLK  CURVES. 
SECTION  PAGE 

94.  To  Locate  a  Curve  with  the  Chain  by  Offsets  from  Chords  Produced  55 

St.x  To  Locate  a  Curve  by  Offsets  from  Tangent 57 

96.  To  Locate  a  Curve  by  Offsets  from  a  Long  Chord 58 

97.  To  Locate  a  Curve  with  Transit  and  Chain 59 

98.  The  Index-angle GO 

99.  Subdeflection-angles : 60 

100-101.  Transit  Notes 61 

C.      OBSTACLES. 

102.  To  Pass  an  Obstacle  on  a  Curve 63 

103.  To  Locate  a  Curve  when  the  P.  C.  is  Inaccessible 64 

104.  To  Pass  to  Tangent  when  the  P.T.  is  Inaccessible C7 

105-107.  To  Pass  a  Curve  through  a  Given  Point 69 

308.  To  Locate  a  Tangent  to  a  Curve  from  an  Outside  Point .  71 

109.  To  Run  a  Tangent  to  Two  Curves  of  Contrary  Flexure 72 

D.      CHANGE  OF  LOCATION. 

110.  To  Locate  a  Curve  Parallel  to  a  Given  Curve 73 

111.  To  Change  P.O.  in  Order  to  Make  P.T.  Fall  in  a  Parallel  Tangent. .      74 

112.  To  Change  R  and  P.O.  to  make  P.T.  Fall  in  Parallel  Tangent,  on 

Same  Radial  Line 75 

113  To  Find  Change  in  P.O.  or  R  for  a  Given  Change  in  / 76 

114.  Required  the  Change  in  P.O.  and  R  for  a  Given  Change  in  /.  the 

P.T7.  Unchanged  .  . . . ..  77 

115  To  Find  New  Radius  for  a  Given  Change  in  T 77 

116.  To  Find  New  R  to  Connect  P.  C.  with  a  Parallel  Tangent 78 

ARTICLE  9.    COMPOUND  CURVES. 
A.    LOCATION  PROBLEMS. 

117.  Given  Both  Tangents  and  One  Radius,  to  Find  the  Other  Radius  ...    80 

118.  Given  One  Radius,  the  Long  Chord  and  the  Angles  it  Makes  with 

Tangents,  to  Find  the  Other  Radius  and  Central  Angles. ...     82 

119.  Given  the  Radii  and  Central  Angles,  to  Find  the  Tangents,  the  Long 

Chord .  and  the  Angles  it  Makes  with  Tangents 80 

120.  Given  the  Long  Chord  and  Angles  Made  with  Tangents,  to  Find 

Both  Radii  when  Common  Tangent  is  Parallel  to  Long  Chord 83 

B.      OBSTACLES. 

121.  To  Locate  Second  Branch  when  P.  C.  is  Inaccessible 84 

C.     CHANGE  OF  LOCATION. 

122.  To  Compound  a  Simple  Curve  so  P.T.  shall  Fall  in  a  Parallel  Tan- 

gent      85 

123.  To    Find  Change  in  P.C.C.  Necessary  to  Make  P.T.  Fall  in  a  Par- 

allel  Tangent  86 

124.  To  Change  P.C.C.  and  Second  Radius  so  P.T.  shall  Fall  in  a  Par- 

allel Tangent,  on  Same  Radial  Line 89 


CONTENTS.  XI 


SECTION  PAGE 

125.  To  Change  P.C.C.  and  Second  Radius  to  Cause  P.T.  to  Fall  at  a 

New  Point  in  Same  Tangent 9 ! 

120.  To  Substitute  a  Three-centered  Compound  Curve  for  a  Simple  One.  94 

127.  To  Substitute  a  Curve  for  a  Tangent  Uniting  Two  Curves 95 

ARTICLE  10.    TRACK  PROBLEMS. 

128.  Reversed  Curves,  Where  to  Use 9G 

129.  To  Connect  a  Located  Curve  with  an  Intersecting  Tangent 97 

130   To  Locate  a  Y 100 

131 .  A  Reversed  Curve  between  Parallel  Tangents  102 

132.  A  Crossover  between  Parallel  Tracks  when  a  Fixed  Length  of  Tan 

gent  is  Inserted 105 

133.  A  Reversed  Curve  with  Unequal  Angles 106 

134.  A  Reversed  Curve  between  Fixed  Points 106 

135.  To  Connect  Two  Divergent  Tangents  by  a  Reversed  Curve . . . .  107 

136.  To  Change  P.R.C  so  P.T.  shall  Fall  in  a  Parallel  Tangent 108 

137   To  Find  the  Radius  of  a  Curved  Track    .  . .  109 


CHAPTER  IV. 

TRANSITION-CURVES. 

ARTICLE  11.    THEORY  OF  THE  TRANSITION-CURVE. 

138.  Elevation  of  Outer  Rail  on  Curves 110 

139    Requirements  of  the  True  Transition-curve Ill 

1-10.  Notation  Employed ill 

141.  Equation  of  Transition-curve  .....  112 

142.  Transition-curve  Angle,  / , .    .  114 

143.  Coordinates  of  Points 114 

144.  Deflection-angles 115 

145.  Explanation  of  Transition-curve  Tables.  118 

146   To   Unite  the  Branches  of  a  Compound  Curve  by  a  Transition- 
curve , . . . .  119 

147.  Length  of  Transition-curve  to  be  Taken 121 

ARTICLE  12.    FIELD- WORK. 

A.      FIELD    FORMULAS. 

148.  When  to  Use  the  Simplified  Formulas    122 

149.  Simplified  Formulas  for  Transition-curves 122 

150.  Offsets 124 

151.  Compound  Curves 125 

B.      SETTING  OUT  TRANSITION-CURVES. 

153.  Location  by  Offsets 125 

154.  Location  by  Deflection -angles  ...    126 

155.  Form  of  Transit  Notes  for  Transition  curves. .  128 


Xll  CONTENTS. 


ARTICLE  13.    TRANSITION  CURVE  PROBLEMS. 
SECTION  PAGE 

156.  Tangent  Distances  and  External  for  Equal  Offsets 109 

157.  Tangent  Distances,  Offsets  Unequal 130 

158.  Transition-curves  Inserted  without  Changing  the  Vertex  of  Cir 

cular  Curve ...  131 

159.  Transition-curves  Inserted  with  Least  Deviation  from  Old  Track... .  133 

160.  Transition-curves  Inserted   at  Ends  of  Long  Circular  Curve,  Cen- 

tral Portion  Undisturbed  133 

161.  Transition-curve  Inserted  at  P.C.C.  by  Changing  Radius  of  Second 

Branch   136 

162.  To  Insert  Transition-curves  at  the  Ends  of  Two  Circular  Curves 

United  by  a  Common  Tangent 138 

163.  To  Unite  a  Tangent  and  Circular  Curve  when  the  Offset  Cannot  be 

Directly  Measured  139 

164.  Inserting  Transition-curves  in  Old  Track 140 

165.  Remarks  on  Tabular  Interpolations  140 


CHAPTER  V. 

FROGS  AND  SWITCHES. 

ARTICLE  14.    TURNOUTS. 

A.    TURNOUTS  FROM  STRAIGHT  LINES.^ 

166.  Definitions 143 

167.  To  Find  the  Lead,  Z,  and  Radius,  R,  in  Terms  of  the  Frog  Number, 

N,  and  Gauge,  g 144 

168.  Given  R  and  g,  to  Find  N,  J,  and  Frog-angle,  F 146 

169.  To  Find  Theoretic  Length  of  Switch-rail 146 

170.  To  Fiud  Lead  and  Number  of  Crotch-frog  for  a  Double  Turnout  to 

Opposite  Sides  of  Main  Track 147 

171.  To  Find  Turnout  Radius  and   Lead  of  Crotch -frog  in  Terms  of 

Crotch-frog  Number 148 

172.  To  Find  Radius  of  Curve  from  Point  of  Middle  Frog  to  Point  of 

Main  Frog,  Given  _ZV,,  N.  and  N' 148 

173.  Double  Turnout  to  Same  Side  of  Main  Track 150 

174.  To  Find  Radius  of  Curve  between  Frog-points  for  a  Double  Turn- 

out to  Same  Side  of  Main  Track .  151 

175.  To  Unite  Main  Track  with  Siding.  Reversing  Point  Opposite  Frog  . .  152 

176.  To  Lay  Out  a  Ladder-track  153 

B.      TURNOUTS  FROM  CURVES. 

177.  To  Find  Lead  and  Radius  for  Turnout  to  Concave  Side  of  Main 

Line       .  ir>l 

178.  To  Find  Lead  and  Radius  Turnout  to  Convex  Side 157 

179.  To  Find  Theoretic  Length  of  Switch-rail !.r>S 

180.  To  Unite  Main  Track  with  a.  Concentric  Siding    .   .  160 


CONTENTS.  Xlll 

C.      THE   riTUB   LEAD. 
SECTION  PAGE 

181.  Definitions 1W 

18-2.  Given  N,  t,  and  g,  to  Find  the  Stub  Lead 162 

183.  Turnout  Table  and  Explanation , . .   163 

184.  To  Stake  Out  a  Turnout 16o 

185.  Curving  Rails 165 

ARTICLE  15.    CROSSOVERS. 

186.  Crossover  between  Parallel  Straight  Tracks,  a  Tangent  between 

Frog-points 166 

187.  A  Crossover  in  the  Form  of  a  Reversed  Curve 168 

188.  A  Crossover  with  Fixed  Length  of  Intermediate  Tangent 168 

189.  A  Crossover  between  Curved  Main  Tracks 168 

ARTICLE  16.    CROSSING-FROGS  AND  CROSSING-SLIPS. 

A.  CROSSING-FROGS. 

191.  Length  of  Rail   Intercepted   between    Two  Intersecting   Straight 

Tracks.     -. 170 

192.  Angles  of  a  Set  of  Crossing  frogs,  One  Track  Curved 170 

193.  Angles  of  a  Set  of  Crossing-frogs,  Both  Tracks  Curved 171 

B.  CROSSING-SLIPS. 

195.  Length  and  Radii  of  Slip-rails,  Both  Tracks  Straight 172 

106.  Length  and  Radii  of  Slip-rails,  One  Track  Curved  172 

197.  Length  and  Radii  of  Slip-rails,  Both  Tracks  Curved 173 


CHAPTER  VI. 

CONSTRUCTION. 

ARTICLE  17.    DEFINITIONS  :  GENERAL  CONSIDERATIONS  ;  VERTICAL 
CURVES  ;  ELEVATION  OF  OUTER  RAIL. 

199.  The  Division  Engineer 176 

200.  The  Resident  Engineer 176 

201  -204.  Definitions 177 

205.  To  Find  che  Grade-point,  Longitudinal  Slope  Uniform 178 

206   Vertical  Curves 178 

207.  Elevation  of  Outer  Rail  on  Curves 182 

208.  Easing  Grade  on  Curves , 183 

ARTICLE  18.    EARTH-WORK. 
A.    SETTING  SLOPE-STAKES. 

209.  The  Distance  Out  for  Level  Sections I8a 

210.  To  Find  Position  of  Slope-stakes  for  Surface  Inclined 184 

211.  Cross -section  Notes 186 

212.  Irregular  Sections 187 

U3.  Staking  Out  Openings - 187 


XIV  CONTESTS. 


SECTION  PAGE 

214.  Manuer  of  Marking  Stakes is? 

215.  Shrinkage— Growth j,-7 

216.  Borrow-pits,  Drainage  of ,  etc 188 

B.      AREAS  OF  SECTIONS. 

218.  Area  of  Three-level  Section 188 

219.  Area  of  Five-level  Section 189 

220.  General  Formula  for  Areas 190 

221.  Explanation  of  Table  of  Areas  of  Level  Sections  and  the  Three- 

level  Correction 191 

C.      VOLUME  OF  EARTHWORK. 

222.  Where  Cross-sections  should  be  Taken 193 

228.  Volume  by  Averaging  End  Areas. . .  19i> 

224.  The  Prismoidal  Formula . .   J93 

225.  Form  of  Record 195 

226.  The  Prismoidal  Correction 195 

227.  Computation  of  Volumes  when  Passing  from  Cut  to  Fill      198 

228.  Use  of  Tables  of  Volumes  in  Making  Preliminary  Estimates 199 

229    Side  Ditches 199 

230.  Earthwork  on  Curves 199 

231.  Overhaul '. 201 

ARTICLE  19.    GRADE  AND  BALLAST  STAKES,  CULVERTS,  BRIDGES, 
AND  TUNNELS. 

232.  Grade  and  Center  Stakes 202 

233.  Ballast-stakes 202 

235.  Openings  of,  for  Culverts,  Trestles,  etc 202 

236.  Bridge  Piers  and  Abutments .203 

237.  Tunnels 204 

ARTICLE  20.    MONTHLY  AND  FINAL  ESTIMATES. 

238.  Monthly  Estimates 205 

239.  Measurements  for  Earthwork 206 

240.  Classification  of  Earthwork 206 

211.  The  Progress  Profile 207 

242.  Masonry  Estimates 207 

243.  Bridge  Estimates 207 

244.  Track  Material 207 

245.  Blank  Estimate  Sheets 208 

246.  Monthly  Payments 208 

247.  Extras 208 

248.  Final  Estimate 208 

249.  Acceptance 209 

TABLES. 

Table  Showing  Length  of  Transition-curve  to  be  Taken  12i 

Table  of  Values  of  g  -  Vgi  for  Stub  Lead 163 

Turnout  Table 164 

Table  of  Corrections  for  Vertical  Curves 181 


CONTENTS.  XV 


PAG  E 

Table  of  Elevation  of  Outer  Rail  on  Curves  182 

Table  of  Prlsmoidal  Corrections  for  Level  Sections 196 

I.  Radii  of  Curves 212 

II.  Minutes  in  Decimals  of  a  Degree 215 

III.  Tangential  Offsets  216 

IV.  Long  Chords  and  Actual  A-rcs 217 

V.  Mid-ordinates  to  Long  Chords 218 

VI.  Logarithms  of  Numbers , 220 

VII.  Logarithmic  Sines  and  Cosines. 838 

VIII.  Logarithmic  Tangents  and  Cotangents 253 

IX.  Functions  of  a  One-degree  Curve 268 

X.  Natural  Sines  and  Cosines  298 

XI.  Natural  Secants  and  Cosecants 307 

XII.  Natural  Tangents  and  Cotangents 320 

XIII.  Natural  Versines  and  Exsecants 332 

XIV.  Coordinates  for  Transition-curves 355 

XV    Deflection-angles  for  Transition-curves 356 

XVI.  Transition-curve  Table 358 

XVII.  Areas  of  Level  Sections 371 

XVIII.  Corrections  for  Three-level  Ground 375 

XIX.  Cubic  Yards  per  100  ft.  in  Terms  of  Center  Height 376 

XX.  Cubic  Yards  per  100  ft.  in  Terms  of  Sectional  Area. ...  382 

XXI.  Rise  per  Mile  of  Various  Grades 386 

XXII.  Slopes  for  Topography 387 

XXIII.  Material  Required  for  One  Mile  of  Track . .  387 

KXIV.  Mutual  Conversion  of  Feet  and  Inches  into  Meters  and  Centi- 
meters   388 

XXV.  Mutual  Conversion  of  Miles  and  Kilometers 389 

XXVI.  Length  of  1'  Arc  of  Latitude  and  Longitude 389 

XXVII.  Trigonometric  and  Miscellaneous  Formulas  390 


A    FIELD-MANUAL    FOE    RAILROAD 
ENGINEERS. 


CHAPTER  I. 

RECONN01SSANCE. 

ARTICLE  1.     OBJECTS  OF  RECONNOISSANCE — How  MADE. 

1.  THE  question  of  the  selection  of  the  proper  route  for  a  line 
of  railway  is  essentially  an  economic  one.  involving  not  only  the 
cost  of  construction,*  but  of  maintenance  and  operation,  and  a 
consideration  of  the  immediate  and  future  traffic  likely  to  pass 
over  the  completed  road. 

The  engineer  upon  whom  devolves  the  duty  of  making  the 
surveys  for  a  railroad  is  not  often  called  upon  to  determine 
whether  it  should  or  should  not  be  built,  though  his  preliminary 
estimate  may  decide  those  whose  duty  it  is  to  do  so  :  the  problem 
confronting  him  is  liow  to  secure  the  best  line,  answering  a  given 
purpose,  for  the  least  cost.  Keeping  in  mind  the  proper  working 
of  the  completed  road,  the  problem  may  be  divided  into  two  gen- 
eral parts  : 

First.  The  selection  of  the  general  route  between  terminal 
points,  and  in  some  cases  the  selection  of  the  terminals  them- 
selves. 

Second.  The  fitting  of  the  line  to  the  ground  in  such  a  manner 
as  will  render  the  cost  of  constructing  and  operating  the  road  a 
minimum. 

The  first  is  by  far  the  more  important  and  difficult  operation, 
requiring  the  highest  grade  of  engineering  skill — a  fact  too  sel- 
dom recognized  by  those  selecting  engineers  for  this  work.  The 
acquirement  of  the  necessary  skill  can  result  only  from  long 
practice  and  close  observation,  coupled  with  the  ability  to  fully 


2  A    FIELD-MANUAL   FOR    RAILROAD    KN(JI  N  KEIIS. 

grasp  and  weigh  till  the  complex  features  of  the  question.  A 
passing  reference  only  can  be  made  to  it  in  this  little  volume, 
which  is  intended  to  furnish  hints  and  aids  to  the  better  execution 
of  the  second  part.  For  the  benefit  of  the  beginner  who  has  to 
do  with  the  location  and  construction  a  few  definitions  and  hints 
relating  to  reconuoissance  will  be  given  before  going  on  to  the 
special  problems  arising  in  the  work  of  the  railroad  engineer. 

2.  The  Reconnoissance  is  a  rapid,  general  survey  of  the  area 
through  which  the  proposed  railroad  must  pass,  made  only  with 
such  instruments  as  can  be  easily  carried,  and  which  should  ena- 
ble the  engineer  to  restrict  the  more  accurate  instrumental  work 
that  follows  to  one  or  two  general  lines.     The  time  required  for 
this  part  of  the  work  will  in  general  be  only  a  small  fraction  of 
the  time  consumed  in  location,  involving  the  service  of  very  few 
men;  yet  there  is  no  part  of  the  work  more  rapidly  and    im- 
properly done — not  always  because  the  engineer  in  charge  under- 
estimates its  importance,  but  because  he  is  not  usualty  allowed 
sufficient  time  in  which  to  study  thoroughly  the  area  under  con- 
sideration. 

Properly  the  reconnoissance  includes  the  determination  of  the 
terminal  points  of  the  road,  but  the  locating  engineer  is  usually 
relieved  from  the  necessity  of  selecting  these  points,  and  the 
question  reduces  to  that  of  finding  the  best  available  line  which 
admits  of  being  built,  maintained,  and  operated  at  the  least  cost 
between  two  given  points. 

The  reconnoissance  must  be  made  over  an  area — not  a  line  or 
lines.  Even  what  seems  the  most  unpromising  portion  should 
be  carefully  studied,  for  the  engineer  can  never  be  satisfied  he 
has  selected  the  best  route  until  he  has  convinced  himself  by  care- 
ful study  that  all  others  are  inferior.  Too  much  haste  on  recon- 
noissance means  either  a  poor  line  or  a  much  greater  expenditure 
of  time  and  money  on  the  preliminary.  No  amount  of  notes  or 
topography  can  take  the  place  of  an  intimate  personal  knowledge 
of  the  problems  to  be  encountered,  and  hence  the  reconuoissance 
and  preliminary  survey  should  be  made  by  the  engineer  who  is 
to  locate  the  road. 

3.  The  Instruments  needed  will  rarely  be  more  than  a  pocket- 
compass,  hand-level,  aneroid  barometer,  field-glasses,  and  some- 
times a  pedometer  or  an  odometer. 

(a)  The  Pocket-compass  is  used  to  obtain  the  magnetic  bear- 
ings of  lines  and  the  angles  they  make  with  each  other. 


RECONNAISSANCE.  3 

(6)  The  Hand-level  enables  one  to  obtain  differences  of  ele- 
vation between  points  not  fur  apart. 

(c)  The  Aneroid  Barometer  gives  approximate  heights  of  the 
mercury  column,  and  serves  to  roughly  determine  the  difference 
of  elevation  of  given  points.  In  addition  to  the  scale  giving 
readings  in  inches,  it  should  have  also  a  scale  graduated  to  give 
readings  in  feet.  If  two  aneroids,  which  have  been  previously 
compared,  are  read  simultaneously,  one  at  each  of  the  points 
whose  difference  of  elevation  is  desired,  or  if  the  same  aneroid  is 
read  at  each  successively  at  a  short  interval  of  time,  during  which 
the  atmospheric  pressure  has  not  sensibly  altered,  we  may  find 
the  difference  of  elevation  by  the  formula* 


d  =  60000  (log  H-  log  h)l  +  9     .     .    (1) 

in  which  d  is  the.  difference  of  altitude  in  feet,  H  and  h  the 
barometric  readings  in  inches  —  the  logarithms  being  of  the  com- 
mon or  Briggs  kind,  I7  and  t  the  temperatures  of  the  two  stations 
in  Fahrenheit  degrees. 

If  the  sum  of  the  temperatures,  T  -\-  1,  is  taken  as  105°,  formula 
(1)  reduces  to 

d-  63000  (log  H-  log  A)  ......     (!') 

EXAMPLE.  —  The  reading  of  the  barometer  at  the  foot  of  a 
mountain  is  28.8  inches,  and  at  the  top  26.7  inches.  Required 
the  height  of  the  mountain. 

By  (!').  d  =  63000  (log  28.7  -  log  26.7)  =  2071  feet. 

The  effect  of  temperature  on  the  metal  of  the  instrument 
should  be  considered  in  the  barometric  formula  when  very  pre- 
cise work  is  to  be  done  ;  but  this  correction,  being  small,  may  be 
neglected  in  the  rough  work  of  reconnoissance,  particularly  since 
the  makers  of  the  instrument  construct  it  in  such  a  way  as  to 
compensate,  as  closely  as  possible,  for  such  changes  of  tem- 
perature. 

(d)  The  Pedometer  is  an  instrument  which  automatically 
counts  the  number  of  steps  made  by  a  person  when  the  instru- 
ment is  attached  to  his  belt  ;  then,  knowing  the  average  length 
of  step,  the  distance  passed  over  can  be  readily  computed. 

The  Odometer  registers  the  number  of  revolutions  of  a  wheel 
to  which  it  is  attached,  and  the  number  of  revolutions  multiplied 
by  the  circumference  of  the  wheel  gives  the  space  passed  over. 

*  See  Plymtou's  Aneroid  Barometer,  p.  38,  for  formula  (1). 


4  A   FlELr-ilANUAL    FOR   RAILROAD    ENGINEERS. 

4.  The  Map. — Before  beginning  the  reconnoissance  the  engi- 
neer should  provide  himself  with  the  best  available  map  of  the 
region  to  be  traversed  ;  if  this  is  a  topographic  one,  he  can  at 
once  determine  from  it  the  lines  that  are  likely  to  justify  an 
examination  ;  and  even  if  it  is  only  a  sketch-map,  he  can  get 
material  assistance  by  observing  the  courses  of  the  streams  and 
remembering  that  their  positions  indicate  the  relative  elevations 
of  the  portion  of  the  region  through  which  they  flow.  Thus  the 
large  streams  follow  the  lines  of  least  elevation,  and  the  manner 
in  which  the  lateral  streams  unite  with  the  principal  one  indi- 
cates the  general  trend  of  the  terrain.  Two  streams  flowing 
nearly  parallel  approach  or  recede  from  each  other  according  us 
the  intervening  land  diminishes  or  increases  in  altitude.  Two 
streams  flowing  away  from  each  other  on  opposite  sides  of  a 
divide,  and  having  their  source  therein,  approach  each  other 
closest  at  the  point  of  least  elevation,  and  indicate  the  position  of 
a  pass  or  the  lowest  point  of  the  dividing  ridge.  The  study  of 
any  good  contour  map  covering  sufficient  area  will  illustrate  the 
laws  governing  the  courses  followed  by  streams. 

The  elevations  of  a  few  correctly  mapped  points,  when  obtain- 
able, from  the  map  or  otherwise,  serve  as  a  guide  in  tentatively 
fixing  on  the  maximum  gradient  to  be  employed  and  the  amount 
of  development  needed. 

A  skillful  engineer  will  thus  be  enabled  to  project  his  lines 
with  sufficient  accuracy  to  enable  him  to  select  on  the  ground  the 
most  feasible  route  or  routes  for  his  preliminaries  in  the  least 
possible  time.  He  should  guard  against  the  conviction,  however, 
that  it  is  unnecessary  for  him  to  look  elsewhere  than  along  the 
projected  routes  ;  for  the  inaccuracies  of  the  map,  local  peculiari- 
ties, the  nature  of  the  excavation  and  embankment,  the  number 
and  cost  of  bridges  and  other  mechanical  structures, — all  these 
may  conspire  to  make  the  most  promising  map-line  inferior  to 
some  other  whose  advantages  have  to  be  sought  for  on  the 
ground. 

6.  Having  tentatively  decided  on  the  limiting  grades  and  cur- 
vature to  be  employed,  the  engineer  goes  carefully  over  the 
ground,  examining  the  entire  area  that  seems  likely  to  afford 
passage,  in  order  to  determine  whether  a  suitable  line  may  be 
secured  for  the  grades  and  curves  previously  assumed.  With  his 
pocket-compass  he  takes  the  bearings  of  lines,  and  by  means  of 
the  hand-level  and  aneroid  determines  differences  of  elevation.- 


RECONNOISSANCE.  5 

Distances  are  estimated  by  the  eye,  paced,  and  the  count  taken 
from  the  pedometer,  or,  if  the  country  admits  of  the  use  of  a 
vehicle,  taken  from  the  odometer  readings.  If  a  well-gaited 
saddle-horse  is  used,  very  good  results  may  be  gotten  by  timing 
him,  or  by  the  use  of  the  pedometer  if  his  stride  is  uniform. 

But  in  all  cases  much  dependence  must  be  placed  on  the  ability 
to  estimate  with  the  eye  differences  of  elevation  and  distances. 
The  ability  to  do  this  with  even  reasonable  accuracy  comes  only 
from  long  practice  and  careful  observation,  even  to  the  most 
gifted  in  this  respect.  New  and  unexpected  conditions  some- 
times deceive  even  the  most  practiced  eye,  but  under  ordinary 
conditions  almost  any  one  can  train  his  eye  to  estimate  horizontal 
distances  fairly  well.  Vertical  heights  are  more  deceptive,  pos- 
sibly because  we  have  less  practice  in  this  line,  and  the  mind 
seems  naturally  to  exaggerate  the  vertical  as  compared  with  the 
horizontal  ;  practice,  however,  will  enable  us  to  make  allowance 
for  the  natural  tendency  to  overestimate  heights  and  slopes. 

The  ground  should  be  gone  over  in  both  directions,  for  the  ap- 
pearance may  be  quite  different  when  approached  from  different 
quarters.  Ruling  points,  such  as  a  pass  in  the  mountains,  the 
crossing  of  a  large  stream,  or  a  town  or  city  through  which  the 
road  must  be  built,  serve  to  reduce  the  problem  to  a  number  of 
special  ones,  each  having  its  own  solution. 

In  a  mountainous  region  offering  a  limited  number  of  possible 
routes,  but  heavy  construction  work,  it  may  often  happen  that 
the  location  of  a  line  is  a  much  less  difficult  operation  than  in  an 
open,  rolling  country  offering  a  score  of  possible  lines,  between 
which  the  engineer  making  the  reconnoissance  must  decide, 
selecting  only  those  that  in  his  judgment  seem  to  justify  an 
accurate  instrumental  survey. 

The  engineer  must  keep  constantly  in  mind  all  the  factors  of 
the  general  problem  of  economic  location  and  maintenance,  and 
successful  operation  of  trains.  One  line  may  cost  more  for  con- 
struction and  maintenance  than  another,  but  less  for  operation, 
or  may  invite  less  traffic.  In  all  cases,  however,  the  question 
of  grades,  curvature,  length  of  line,  earthwork,  and  mechanical 
structures  are  the  controlling  elements  to  be  considered. 

Having  decided  upon  the  route  or  routes  over  which  to  run 
preliminaries,  these  are  marked  on  the  map,  and  the  engineering 
party  organized  and  put  in  the  field,  with  all  the  necessary 
instruments. 


CHAPTER  II. 

PRELIMINARY  SURVEYS. 

ARTICLE  2.    OBJECTS;  THE  FIELD  CORPS  ;  DUTIES  OF  THE  CHIEF. 

6.  The  Objects  of  the  preliminary  surveys  are  to  secure  all  the 
data  necessary  to  determine  which  one  of  the  routes  selected  on 
reconnoissance  is  the  most  feasible,  all  things  considered,  and  the 
approximate  cost  of  construction.     In  rough  country  it  will  be 
economical  to  make  two,  or  even  three,  surveys  over  the  route  se- 
lected for  location  before  beginning  to  place  the  line  in  the  position 
it  is  finally  to  occupy.     The  first  of  these  is  often  omitted,  and  is 
called  an  "exploration-line  "  ;  it  will  frequently  save  the  making 
of  the  more  expensive  "preliminary"  over  one  or  more  of  the 
routes. 

7.  The  Exploration-line  may  be  made  with  either  transit  or 
compass,  and  consists  of  a  rapidly  ran  line,  made  for  the  purpose 
of  determining  the  maximum  curvature  and  gradients  with  which 
to  project  the  preliminary.     It  will  not  be  necessary  to  make  a 
detailed  study  of  the  region  at  this  time,  the  distances  and  eleva- 
tions, with  such  sketch  topography  as  may  be  easily  taken,  being 
all  that  is  needed.     The  magnetic  bearing  of  lines  is  taken  by 
the  cornpassman,  and  the  chainmen  align  each  other  with  the  flag 
set  by  the  flagman.     As  the  progress  of  the  level  party  will  be 
slower  than  that  of  the  compass  party,  it  will  be  economical  to  add 
an  extra  rodman,  and  sometimes  a  recorder.     The  compassman 
may  sketch  in  the  features  adjacent  to  the  line  while  waiting  for 
his  chainmen,  who  may  be  either  in  front   of  or  behind  the  com- 
pass. 

The  stadia  method  of  surveying — to  be  spoken  of  later — would 
seem  to  offer  exceptional  advantages  for  this  work — only  three  or 
four  men  being  needed  in  addition  to  the  chief.  With  it,  by  sct^ 
ting  the  transit  over  alternate  stations,  very  rapid  progress  may  be 
made,  and  obstacles  avoided  with  as  much  or  greater  ease  than 
with  the  compass. 

The  exploration-line  will  more  than  pay  for  itself  in  showing 

6 


PRELIMINARY   SURVEYS.  V 

what  routes  it  will  be  unnecessary  to  make  preliminaries  over, 
and  in  indicating  the  most  feasible  one.  It  should  be  run  over  all 
the  routes  selected  on  reconnoissance. 

8.  The  Preliminary  Survey  follows  the  exploration,  or,  when 
this  is  omitted,  comes  next  after  the  reconnoissance.     It  may,  with 
advantage,  be  made  in  two  parts — first  and  second  preliminary. 
It  is  made  with  such  instrumental  accuracy  as   the  nature  of  the 
case  may  demand,  sufficient  data  being  obtained  to  determine  the 
best  line  on  which  to  locate  and  the  approximate  cost  of  construc- 
tion.    The  rapidity  with  which  this  work  can  be  done  will'depend 
on  the  care  with  which  the  reconnoissance  was  made.     The  pre- 
liminary line  should  approximate,  as  closely  as  the  eye  can  deter- 
mine, to  the  position  the  located  line  should  occupy,  and  forms  the 
base  on  which  the  topographic  work  rests.     In  reasonably  easy 
country,  where  exploration-lines  have  been  run,  one  preliminary 
should  suffice  for  each  route,  but  in  difficult  regions  it  will  be  best 
to  run  a  second  preliminary.     If  portions  of  the  route  are  easy,  fol- 
lowed by  difficult  parts,  it  will  often  be  sufficient  to  "  back  up  " 
and  re-run  the  difficult  portion  until  a  reasonably  satisfactory  line 
has  been  obtained. 

9.  The  Field  Corps  consists  of  a  chief  of  party,  transitman, 
leveler,    rodman,   two   chainrnen,    rear   rodman  or   "back-flag," 
stakeman,  and  two  or  more  axemen.     If  a  topographic  party  is 
added,  as  it  should  be  in  any  but  the  easiest  country,  there  will  be 
also  a   topographer  with  two  or  more   assistants.     A. cook  and 
teamster  will  be  needed  with  the  camp  outfit. 

The  corps  is  usually  divided  into  the  following  parties  : 

(a)  THE  TRANSIT  PARTY. 

(6)  THE  LEVEL  PARTY. 

(c)  THE  TOPOGRAPHIC  PARTY. 

10.  The  Chief  of  Party  receives  his  orders  from  the  chief  en- 
gineer, or  such  other  officer  as  may  be  in  charge,  directs  the  mo- 
tions of  the  surveying  corps,  and  is  responsible  for  their  conduct 
and  progress.    He  provides  accommodations  and  supplies,  pays  all 
expenses,  taking  receipts  or  vouchers  for  all  outlays — in  dupli- 
cate when  required.     In  the  less  thickly  populated  sections  he 
must  provide  tents,  wagons,  cook,  and  all  necessary  camping  outfit 
and  supplies.     He  must  direct  the  field  operations  in  person,  keep- 
ing in  advance  of  the  transit,  establish  turning-points  or  hubs, 
and  direct  the  transitman  in  the  proper  course.     He  should  keep 


8          A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

a  record — or  direct  the  transitman  and  topographer  to  do  so — of 
the  character  of  earthwork  likely  to  be  encountered,  the  places 
where  drains,  culverts,  bridges,  cattle-guards,  etc.,  are  needed; 
the  nature  of  material  for  embankment,  piling,  etc.,  adjacent  to 
the  line  ;  the  probable  amount  of  clearing  and  grubbing,  and  all 
other  features  likely  to  affect  the  cost  of  construction.  He  should 
see  that  the  names  of  property  owners  and  residents  along  the 
line  and  the  positions  and  bearings  of  property  lines,  when 
possible,  are  noted. 

He  should  have  authority  to  discharge  assistants — except  transit- 
man, leveler,  and  topographer — whose  services  are  unsatisfactory, 
and  in  many  cases  it  will  be  best  for  him  to  have  entire  control, 
engaging  or  discharging  any  member  of  the  corps  as  circumstances 
may  require. 

ARTICLE  3.     THE  TRANSIT  PARTY. 
A.  Duties  of  the  Members. 

11.  The  Transit  Party  should  consist  of  a  transitman,  head 
chainman,  rear  chaininan,  rear  flagman,  stakeman,  and  as  many 
axemen  as  may  be  required — rarely  less  than  two  even  for  open 
country. 

12.  The  Transitman  cares  for  his  instrument,  keeping  it  in  ad- 
justment; directs  the  chainmen  into  line;  notes  the  angle  between 
successive  tangents  as  read  on  plates;  notes  also  the  bearings  of 
tangents,  of  highways,  streams,  and  property  lines  (on  location), 
with  the  plus  at  which  the  line  crosses  them.     If  there  is  no 
topographic  party  he  must  make  sketches,  on  the  right-hand  page 
of  note-book,  of   the  surface  features  adjacent  to  the  line;   the 
red  line  down  the  middle  of   page   represents   the   transit   line, 
whether  straight,   broken,  or  curved,  to  which  the  sketches  are 
adjusted.     He  must  see  that  the  axemen  keep  in  line,  in  order 
that  no  unnecessary  chopping  may  be  done.     Large  trees  need 
rarely  be  felled  on  preliminary,  even  when  a  given  general  course 
has  to  be  followed,  for  small  angles  may  be  turned  to  avoid  them, 
the  deflections  to  right  being  made  to  approximately  balance  those 
to  left. 

When  the  chief  of  party  is  absent  the  transitman  is  ranking 
man,  and  will  take  temporary  charge. 

13.  The  Head  Chainman  carries  a  range-pole  or  "  flag,"  and 
drags  the  chain,  which  he  must  see  is  straight  and  horizontal 


PRELIMINARY    SURVEYS.  9 

when  setting  a  point  for  a  stake.  He  directs  the  stakeman  where 
to  drive  his  stake,  calling  out  the  number  after  the  rear  chainman 
has  read  and  called  out  the  number  on  his  stake;  he  keeps  the 
axemen  in  line  by  setting  his  flag  and  going  ahead,  directing  them 
where  to  cut  by  keeping  them  in  line  with  the  flag  and  transit. 
The  speed  of  the  party  is  dependent  on  the  rapidity  and  accuracy 
with  which  he  can  set  his  flag  in  position,  by  ranging  with  stakes 
already  set  between  him  and  transit,  and  in  seeing  that  the 
axemen  make  all  their  work  count. 

14.  The  Rear  Chainman  must  be  careful  to  hold  his  end  of 
the  chain  in  the  proper  place,  and  that  it  is  kept  straight  and  taut 
when  the  head  chainman  is  setting  a  stake.     He  must  give  all 
pluses,  note  the  number  on  each  stake  as  he  comes  up  to  it,  and 
see  that  the  stakeman  has  marked  it  correctly;  he  must  make  a 
note  of  pluses  for  roads,  fences,  streams,  etc.,  to  be  given  to  the 
transitman  later  on. 

15.  The   Stakeman  must  keep  himself   supplied  with   stakes 
about  li"  X  2"  X  24",  marking  the  number  on  them  plainly,  and 
driving  them  as  directed  by  the  head  chainman. 

If  sawed  stakes  are  not  provided,  he  must  cut  the  stakes  and 
face  them  for  the  numbers.  He  must  keep  on  hand  a  number  of 
plugs  or  "hubs,"  to  be  driven  flush  with  the  ground  and  having 
the  point  where  flag  rested  marked  with  a  tack.  About  ten  or 
twelve  inches  to  the  left  of  and  facing  the  hub  a  guard  stake  is 
driven,  on  which  is  marked  the  station  number,  and  which  enables 
one  to  find  the  hub  at  any  time. 

16.  The  Axemen  do  all  necessary  clearing  and  chopping  in 
order  that  the  transit  and  level  parties  may  have  a  clear  sightway, 
and  yet  restrict  the  work  of  clearing  to  a  minimum.     One  of  them 
may  be  detailed  to  keep  the  stakeman  supplied  with  stakes. 

17.  The  Rear  Flagman  holds  his   flag  on  the   last  turning- 
point  for  the  transitman  to  use  in  back-sighting. 

18.  The  Instruments   used   by  the   party  are  the  transit   (or 
compass),  one-hundred-foot  chain  or  tape,  range-poles,  and  the 
necessary  axes  and  hatchet  for  axemen  and  stakeman. 

B.    Transit  Adjustments — The  Vernier. 

19.  For  railroad  work  the  transit  is  usually  plain,   but  it  is 
often  convenient  to  have  a  clamp  and  tangent  movement  to  tele- 


10        A   FIELD-MANUAL   FOR   RAILROAD   ENGINEERS. 

scope,  a  vertical  circle,  a  level  on  telescope,  stadia  wires,  and  a 
gradienter;  the  solar  attachment  will  rarely  be  needed. 

20.  To  Adjust  the  Plate  Levels.— The  axis  of  the  instrument 
is  set  at  right  angles  to  the  plates  by  the  manufacturer,  so  that 
when  the  axis  is  made  vertical  the  plates  will  be  horizontal. 

In  making  adjustments  remember  that  a  complete  reversal 
always  doubles  any  existing  error. 

Place  the  bubble-tube  parallel  to  a  diagonal  pair  of  leveling- 
screws,  and  bring  Ihe  bubble  to  the  centre  of  its  run.  Revolve 
the  instrument  180°  on  the  vertical  axis,  and  the  level- tube  will 
be  parallel  to  the  same  pair  of  leveling-screws  as  before,  but 
reversed.  If  the  bubble  has  moved  from  its  central  position 
bring  it  half-\v&y  back  by  means  of  the  capstan-headed  screws  at 
the  ends  of  the  tube.  Relevel  and  repeat  until  the  bubble  remains 
at  the  centre  after  reversal.  Do  the  same  for  the  other  bubble. 
Both  bubbles  should  remain  at  the  centres  of  their  tubes  during  a 
complete  reversal. 

21.  Parallax  is  an  apparent  movement  of  the  cross- wires  with 
respect  to  the  object  sighted  when  the  eye  is  moved  from  side  to 
side  of  the  eyepiece,  and  shows  that  the  image  does  not  fall  in  the 
plane  of  the  cross-wires.     In  precise  measurements  it  should  be 
removed  before  making  an  observation  with  the  telescope.     To  do 
this,  first  bring  the  cross-wires  clearly  into  view  when  the  object- 
glass  is  turned  towards  the  sky,  then,  when  sighting  an  object, 
note  if  there  is  any  relative  movement  of  cross-wires  and  image 
when  the  eye  is  moved  from  side  to  side  at  the  eyepiece  ;  if  there 
is,  refocus  the  object-glass  until  this  movement  disappears. 

22.  To  Adjust  the  Line  of  Collimaiion  is  to  make  the  line 
joining  the  intersection  of  cross-wires  and  optical  center  of  objec- 
tive describe  a  plane  perpendicular  to  the  horizontal  axis  of  instru- 
ment. 

FIRST  METHOD. — Level  the  instrument  and  clamp  the  move- 
ments on  vertical  axis.  Sight  some  well-defined  object  distant 
about  the  length  of  an  average  sight,  and  in  the  same  horizontal 
plane  as  telescope.  Reverse  the  telescope  on  its  horizontal  axis, 
and  fix  a  point  about  as  far  from  instrument  as  first  point,  and  in 
the  same  horizontal  plane.  Revolve  the  instrument  on  its  vertical 
axis  and  sight  the  first  point;  then  reverse  the  telescope  and  note 
if  line  of  sight  cuts  the  second  point.  If  not,  loosen  the  capstan- 
headed  screws  holding  cross- wire  ring  and  move  the  vertical  wire 


PRELIMINARY    SURVEYS.  11 

over  one  fourth  the  apparent  error — since  tliere  were  two  reversals 
— remembering  that  the  image  of  the  cross-wires  is  inverted,  while 
that  of  the  object  appears  in  its  true  position.  Test  by  repetition. 

SECOND  METHOD.— If  the  limb  graduations  can  be  relied  on 
they  may  be  used  in  adjusting  the  vertical  wire.  With  the  instru- 
ment level  sight  a  well-defined  point,  then  revolve  180°  by  vernier- 
plate,  reading  both  verniers;  reverse  telescope,  and  note  if  line  of 
sight  cuts  the  point.  If  not,  correct  one  half  the  apparent  error  by 
moving  diaphragm  ;  then  test  by  repetition. 

The  manufacturers  adjust  the  object-glass  slide  so  that  the  ob- 
jective travels  in  the  telescope  axis,  and  this  adjustment  is  not 
liable  to  serious  derangement.  It  is  well,  however,  to  sometimes 
test  by  adjusting  the  line  of  collimation  for  both  near  and  distant 
objects.  If  not  correct  for  both,  move  the  ring  which  guides  the 
rear  end  of  object-glass  slide  until  the  adjustment  is  correct  for 
both  positions. 

Next  make  the  vertical  wire  vertical  by  noting  if  it  coincides 
throughout  its  length  with  a  plumb-line,  or  by  observing  if  it  de- 
viates from  a  point,  on  which  the  intersection  has  been  fixed,  when 
the  telescope  is  elevated  or  depressed.  Any  error  is  corrected  by 
turning  the  ring  after  slightly  loosening  the  screws  holding  it. 

The  horizontal  wire  should  also  be  adjusted  so  that  the  inter- 
section of  the  cross-wires  will  be  in  the  axis  of  the  telescope  ;  if 
the  transit  is  to  be  used  as  a  leveling  instrument  this  adjustment 
is  essential. 

Drive  a  stake  close  to  the  instrument,  and  with  the  telescope 
clamped  as  nearly  horizontal  as  can  be  conveniently  done  read  a 
rod  held  on  top  of  the  stake  ;  about  800  feet  distant,  and  in  line 
with  first  stake  and  instrument,  drive  a  second  stake  and  read  the 
rod  on  it.  Revolve  180°  on  vertical  axis,  reverse  the  telescope  and 
bring  the  horizontal  wire  to  the  former  reading  when  the  rod  is 
held  on  first  stake  ;  if  the  reading  on  the  second  stake  is  not  the 
same  as  before,  correct  one  half  the  apparent  error  by  moving  the 
cross-wire  ring.  Repeat  as  a  test.  The  vertical  wi,re  should  again 
lie  tested  lest  the  movement  of  the  ring  may  have  caused  it  to 
change. 

23.  To  Adjust  the  Standards  is  to  make  the  plane  described 
by  the  line  of  collimation  vertical.  Set  up  the  transit  about  as  far 
in  front  of  some  high  building,  or  other  tall  object,  as  the  highest 
point  that  can  be  sighted  is  above  the  base.  Level  the  instrument 
and  fix  the  intersection  of  the  cross-wires  on  the  highest  point  that 


12        A   FIELD-MANUAL   FOR  RAILROAD   ENGINEERS. 

can  be  easily  sighted.  Depress  the  telescope  and  fix  a  point  near 
the  base  of  the  building  at  about  the  height  of  the  telescope.  Un- 
clamp  and  revolve  on  the  vertical  axis  until  the  telescope  reversed 
cuts  the  lower  point.  Clamp  the  plates  and  raise  the  telescope 
until  the  cross-wires  are  at  the  height  of  the  upper  point.  If  they 
cut  it  the  standards  are  in  adjustment.  If  they  do  not,  bring 
them  half-way  back  by  means  of  the  adjustable  screws  at  the  top 
of  one  of  the  standards.  Repeat  as  a  test. 

24.  To  Adjust  the  Level  on  Telescope  is  to  make  the  bubble 
stand  at  the  center  of  its  run  when  the  line  of  sight  is  horizontal. 
Bring  the  telescope  as  nearly  horizontal  as  maybe  convenient,  and 
take  readings  on  the  tops  of  two  pegs  in  the  same  vertical  plane 
with,  and  equidistant  from,  the  instrument — say  300  feet.  The 
difference  of  readings  will  equal  the  difference  of  elevation  of  the 
pegs;  this  difference  may  be  obtained  with  the  wye-level  if  pre- 
ferred. 

Move  the  instrument  to  a  point  beyond  one  of  the  pegs  and  in 
line  with  both.  Set  up  as  close  to  nearer  peg  as  convenient,  but 
not  so  close  that  the  rod  cannot  be  easily  read.  Bring  the  tele- 
scope as  nearly  horizontal  as  possible,  and  read  on  both  pegs.  If 
the  difference  of  readings  equals  their  difference  of  elevation  the 
line  of  sight  is  horizontal,  and  the  bubble  may  be  brought  to  the 
center  by  means  of  the  adjustable  screws  attaching  the  level-tube 
to  the  telescope.  If  this  is  not  the  case,  we  must  set  the  telescope 
so  the  reading  on  second  peg  equals  the  reading  on  first  peg  plus 
the  difference  of  elevation  ;  then  read  again  on  first  peg  and  pro- 
ceed as  before  until  the  condition  is  satisfied.  Or  we  may  proceed 
as  follows : 

In  Fig.  1  let  the  transit  be  at  0,  and  A  and  B  be  the  pegs.  AC 
is  a  horizontal  through  A,  so  that  CB  is  the  difference  of  elevation 


of  A  and  B.     Suppose  line  of  sight  to  cut  the  rods  at  7?  and  D, 
we  must  find  DO  so  that  the  target  may  be  set  at  the  proper  read- 


PRELIMINARY    SURVEYS.  13 

ing  to  make  the  line  of  sight  horizontal.     Let  OF=  a,  FG  =  b, 
EA  =  r,  DB  =  r,  CD  —  k.     Draw  DH  parallel  to  CA  and  OG; 
then  ER=  r  -\-k-r'. 
From  similar  triangles 


Set  the  target  at  a  reading  GB  =  GD  +  ?•',  sight  to  G,  and  the 
line  of  sight  will  be  horizontal.  Bring  the  bubble  to  the  center  of 
its  run  while  the  telescope  is  in  this  position,  and  the  adjust- 
ment is  complete. 

If  desired,  a  correction  for  the  curvature  of  the  earth  and  re- 
fraction may  be  introduced,  but  for  short  sights  this  is  a  useless 
refinement. 

25.  The  Vernier  is  an  auxiliary  scale  for  measuring  smaller 
divisions   than   those   graduated   on   the   limb.     There   are   two 
classes,  the  direct-reading  and  the  retrograde,  according  as  the 
fractional  parts  of  limb  readings  are  taken  on  that  side  of  the 
zero  of  vernier  scale  towards  which  the  vernier  has  moved  with 
respect  to  the  limb,  or  the  reverse.     On  the  direct  vernier  a  cer- 
tain number  of  divisions  on  the  vernier  equals  the  same  number 
of  divisions  on  the  limb,  less  one  ;  on  the  retrograde  there  is  one 
more  division  on  limb  than  on  vernier  when  the  same  space  is 
covered  by  both. 

26.  The  Least  Count  of  a  vernier  is  the  smallest  subdivision  of 
limb  graduation  that  can  be  read  by  it,  and  equals  the  difference 
of  one  space  on  limb  and  one  on  vernier. 

Let  I  =  value  of  one  space  on  limb  ; 

v  =  value  of  one  space  on  vernier  ; 

n  =  number  of  spaces  on  vernier. 
Then  for  the  direct  vernier 

nv  =  (n  —  1)1  ; 
from  which  we  get  the  least  count, 


For  the  retrograde  vernier 

nv  =  (n  -f-  IX, 


14        A    FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 

from  which  the  least  count  is 

,-l=L, 

n 

the  same  result  as  found  for  the  direct  vernier. 

So,  to  find  the  least  count :  Divide  the  value  of  one  limb  space  "by 
the  number  of  spaces  on  the  vernier. 

For  example  :  If  the  limb  of  a  transit  is  divided  to  half-degrees 
and  the  number  of  spaces  on  the  vernier  is  30,  the  least  count 
will  be  ^  divided  by  30,  or  ^  of  a  degree — that  is,  1  minute. 

27.  To  Read  a  Vernier,  take  the  number  of  the  last  division  on 
limb  back  of  the  vernier  zero,  then  look  along  the  vernier  until  a 
line  is  found  to  coincide  with  a  line  on  the  limb  ;  add  the  number 
of  this  vernier  line,  multiplied  by  the  least  count,  to  the  scale 
reading,  and  the  result  will  be  the  required  reading. 

C,   Accessories. 

(1°)  The  Oradienter. 

28.  The   Gradienter  consists     of   a  tangent-screw  having   a 
micrometer-head,  attached  to  one  of  the  standards  of  the  transit 
and  capable  of  being  clamped  to  the  horizontal  axis  of  the  tele- 
scope.    It  is  used — as  its  name  indicates — in  running  grades,  and 
it  accurately  measures  a  small  vertical  angle  in  terms  of  its  tan- 
gent.    The  screw  is  so  cut  that  one  revolution  moves  the  tele- 
scope through  an  angle  whose  tangent  at  one  hundred  feet  from 
the  instrument  has  a  certain  value,  usually  one  foot.     The  grad- 
uated head  is  divided  into  100  parts,  so  that  one  division  corre- 
sponds to  0.01  ft.  at  100  feet  from  instrument. 

To  run  a  given  gradient,  bring  the  telescope  level  and  read  the 
micrometer-head  of  screw;  then  turn  the  screw  as  many  divisions 
as  there  are  hundredths  of  a  foot  rise  or  fall  in  100  feet,  and  with 
a  target  set  at  the  height  of  the  horizontal  axis,  points  on  the 
surface,  corresponding  to  the  given  grade  can  be  found. 

For  example  :  To  run  a  0.75  per  cent  grade,  move  the  microm- 
eter milled  head  75  graduations  from  the  horizontal. 

When  used  as  a  Telemeter,  we  may  either  measure  the  space 
on  the  rod  moved  over  by  the  line  of  sight  for  a  given  number  of 
revolutions  of  the  screw,  or  we  may  note  the  number  of  revolu- 
tions required  to  move  the  line  of  sight  over  a  certain  space  on 
rod.  The  second  method  is  the  more  accurate,  particularly  for 
long  sights. 


PRELIMINARY    SURVEYS. 


15 


(2°)  The  Stadia,  or  Telemeter. 

29.  The  Stadia  is  an  instrument  for  determining  the  distance 
of  a  point  from  the  observer  by  noting  the  space  intercepted  on  a 
rod  by  a  given  visual  angle,  as  determined  by  two  auxiliary  wires 
parallel  to,  and  equidistant  from,  the  horizontal  wire  of  the  transit 
telescope.     When  used  with  an  ordinary  leveling-rod  the  wires 
should  be  adjustable ;  if  they  are  fixed  (which  for  some  reasons 
is   preferable),   the   rod   must   be   graduated  to   correspond.     In 
addition  to  the  distance  of  a  point  from  the  instrument,  the  differ- 
ence of  elevation  is  determined  by  observing  the  angle  made  by 
line  of  sight  with  the  horizontal  when  the  middle  horizontal  wire 
cuts  a  point  on  the  rod  as  high  above  the  ground  as  is  the  centre 
of  the  telescope. 

The  horizontal  position  of  the  point  is  determined  from  its 
magnetic  bearing,  or  the  azimuth  of  line  of  sight  with  reference 
to  some  fixed  line,  usually  the  north-south  line. 

30.  Line  of  Sight  Horizontal.— In  Fig.  2  let  a  and  b  be  the 

stadia  wires,  AB  the  intercept  on  the  rod.     The  secondary  axes 

A 


Fro.  2. 


aA  and  bB  pass   through   the   optical   center  0.     Let   h  =  ab, 
r  =  AB,  d  =  distance  of  cross-wires  from  objective,  D  ~  distance 
of  rod  from  objective. 
From  similar  triangles, 


From  optics, 

l  +  i  =  L 

d  ^  D      f 

in  which/  is  the  focal  length  of  objective. 
Eliminating  d  from  these  two  equations, 


D  -. 


16        A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 


Let  c  be  the  mean  distance  of  objective  from  center  of  instru- 
ment. Adding  this  to  D  gives,  for  the  distance  of  the  rod  from 
the  center  of  the  instrument, 


-  may  be  made  constant,  when  (2)  becomes 


(2) 


(2') 


31.  Line  of  Sight  Inclined. — When  the  line  of  sight  is  not 
level  it  is  difficult  to  hold  the  rod  perpendicular  thereto  ;  hence 
the  rod  is  held  vertical,  the  angle  of  inclination  measured,  and  a 
correction  applied.  In  Fig.  3 

Q. 
F, 


FIG.  3. 

let  r  =  CD  be  the  reading  on  rod  held  vertical ; 

r'  =  FE,  the  reading  perpendicular  to  line  of  sight  ; 
H  =  AG,  the  horizontal  distance  from  A  to  B  ; 
V=  BO,  the  difference  of  elevation  between  A  and  B ; 
n  =  BAG,  the  angle  of  inclination  of  line  of  sight. 

Assume  angles  AFB  and  AEB  =  90°,  from  which  they  rarely 
differ  more  than  15'  to  17'.     Then,  since  FBC  =  n, 

r'  —  r  cos  n. 


PRELIMINARY    SURVEYS.  17 

By  (2').  AB  =  a  +  kr'. 

Hence  AB  =  a  -f  kr  cos  n. 

From  triangle  ABG 

H  =  AB  cos  n 

.-.  H  =  a  cos  w  -f-  kr  cos2  ?i (3) 

V=  AB  sin  T&; 

.*.  V  =  a  sin  n  -j-  A;?'  sin  n  cos  n. 
But  2  sin  n  cos  TZ.  =  sin  2n. 
Hence  V  =  a  sin  n  -j-  ^Ar  sin  2tt (4) 

32.  The  Instrumental  Constant  a  [—  c  +  /  of  (2)]   may  be 
found  by  measuring   the  distance  from  center  of  instrument  to 
mean  position  of  objective,  which  equals  c  ;  then  focusing  on  a 
very  distant  object,  preferably  a  star,  and  measuring  from  center 
of  objective  to  plane  of  cross-wires,  which  equals/.     The  sum  of 
these  distances  is  a  in  formulas  (3)  and  (4). 

If  the  stadia  wires  are  fixed,  k  may  be  found  by  measuring  for- 
ward on  level  ground  the  distance  a  from  plumb-line,  and  from 
this  point  a  further  distance  b  ;  then  note  carefully  the  stadia 
reading  r  when  the  telescope  is  level.  Then,  remembering  (2)', 

a  -\-  b  =  a  -{-  kr. 

.'.  k  —  — ,  a  constant  ratio. 
r 

If  the  stadia  wires  are  adjustable,  we  may  so  adjust  k  that  any 
desired  reading  may  be  had  for  a  given  length  of  base.  A  con- 
venient value  of  k  is  100,  which  corresponds  to  an  intercept  of 
1  foot  on  the  rod  at  100  feet  from  a  point  a  feet  in  front  of  the 
instrument,  2  feet  at  200  feet  in  front,  etc. 

33.  A  Stadia  Table  based  on  formulas  (3)  and  (4)  is  published 
by  the  D.  Van  Nostrand  Company  in  Winslovv's  Stadia  Surveying, 
and  can  be  used  more  rapidly  than  the  formulas.     Johnson's  Re- 
duction Diagram,  by  John  Wiley  &  Sons,  gives  values  of  //and  V 
graphically.     Colby's   Slide-rule,   manufactured  by  Mahn  &  Co., 
St.  Louis,  gives  values  of  V  for  distances  in  feet,  yards,  or  meters 
to  tenth:  of  a  foot,  and  can  be  used  with  great  rapidity. 


18        A   FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 


•    D.   Field-work. 

34.  Station  Numbers  should  begin  with  zero  for  the  initial 
stake,  and  are  marked  on  rear  side  of  stake,  from  the  top  down- 
ward, the  number  of  the  preliminary,  A,  B,  G,  stc.,  being  marked 
on  the  forward  side.     The  marking  should  be  with  kiel,  or  crayon 
that  will  withstand  the  action  of  sun  and  rain.     Stakes  may  be 
set  every  hundred  feet  or  only  at  even  stations,  as  preferred. 

35.  Hubs,  or  Plugs,  are  transit  turning-points,  and  are  short, 
flat-topped  stakes  driven  into  the  ground  flush  with  the  surface. 
The  flag  is  held  on  the  top  and  carefully  aligned,  the  position  of 
the  point  being  marked  by  a  tack.      A  special  tack  with  concave 
head  offers  a  foothold  for  point  of  flag  when  used  in  backsight- 
ing.*     About  10  inches  to  the  left  of  and  with  numbered  side 
facing  the  hub  is  driven  a  guard-stake  to  mark  its  position. 

36.  Reference-points  are  two  or  more  hubs,  with  guard-stakes, 
in  each   of   two  lines  making  a  good  intersection  angle  at  the 
point  whose  position  they  serve  to  locate.     They  should  be  driven 
beyond  reach  of  disturbance,   and  are  used  in  replacing  a  dis- 
located hub. 

These  need  rarely  be  used  on  preliminary. 

37.  Alignment. — It  is  not  intended  that  the  preliminary  and 
location  lines  occupy  exactly  the  same  position  ;  hence  consider- 
able  latitude   is   allowable   in   the   size   and   number  of  angles 
turned,  care  being  taken,  however,  that  the  maximum  curvature 
need  not  be  exceeded  on  location.     Large  trees  and  other  obstruc- 
tions may  be  avoided  by  turning  a  small  angle  until  the  obstacle 
has  been  passed,  then  making  a  deflection  in  the  opposite  sense. 
Bearings  of  tangents  are  taken  with  the  needle,  to  serve  as  a 
check  on  the  angle  read  on  the  plates. 

In  easy  country  not  requiring  a  topographic  party  large  angles 
should  not  be  turned,  a  succession  of  small  ones  with  short  inter- 
vening tangents  being  substituted  in  order  to  make  the  prelimi- 
nary profile  approximate  more  closely  to  the  location  profile. 
These  short  tangents  may  conveniently  be  the  long  chords  of  the 
curve  that  is  to  follow. 

*  Such  a  tack  is  manufactured  by  the  A.  S.  Aloe  Co.,  St.  Louis. 


PRELIMINARY    SURVEYS. 


19 


38.  The  Transit  Notes  may  be  kept  in  the  form  below,  which 
shows  both  pages  of  the  note  book.  Tfee  notes  run  from  the 
bottom  up,  the  right-hand  page  being  reserved  for  sketches  ;  the 
red  line  up  the  middle  of  the  page  represents  the  transit  line, 
whether  straight  or  broken,  to  which  the  sketches  must  be 
adjusted. 


Sta. 

Angle. 

Calculated 
Course. 

Magnetic 
Course. 

Remarks  and  Sketches. 

68 
670 
66 
65 
64 
630 

20°  0'  L. 
6°2'R. 

N.  1°  48'  W. 

N.  18°  12'  E. 

N.  1°  45'  W. 

N.  18°  15'  E. 

( 

c 

) 

61 

39.  Stadia  Methods  for  Preliminary  Surveys. — Preliminary 
lines  are  usually  run  with  the  transit,  but  the  compass  will 
answer  nearly  as  well  in  most  cases,  besides  admitting  of  more 
rapid  work.  The  transit  and  stadia  method  might  well  be  em- 
ployed, and  would  effect  considerable  saving  in  the  cost  of  pre- 
liminary surveys.  For  some  reason  railroad  engineers  have  not 
regarded  it  with  favor,  though  it  is  extensively  employed  in 
topographic  surveying  where  the  map  is  to  be  used  for  work  that 
is  often  more  precise  than  needed  for  railroad  preliminaries. 

Particularly  is  this  method  applicable  to  exploration  lines. 
With  the  transit  and  stadia  the  entire  surveying  corps  need  not 
exceed  five  or  six  men,  the  instrument  man  acting  as  transitman, 
leveler,  and  topographer  all  in  one.  The  only  objection  would 
seem  to  be  in  the  amount  of  reduction  the  notes  would  need ; 
however,  with  tables  and  slide-rule  (see  33)  this  work  may  be 
very  rapidly  done.  For  vertical  angles  of  less  than  one  degree 
the  horizontal  reduction  can  be  neglected,  and  with  side  readings 
for  topography  the  angle  may  be  5  or  10  degrees  without  necessi- 
tating the  correction.  Vertical  heights  are  found  by  the  slide- 
rule  or  by  charts. 

This  method  would  really  necessitate  the  making  of  a  topo- 
graphic map  along  a  narrow  strip  of  country,  from  which  the 
profile  could  readily  be  taken.  With  a  skilled  observer  and  two 
to  four  rodmen  the  progress  may  be  more  rapid,  and  fully  as 
good  for  the  purpose  intended  as  the  more  expensive  method 
usually  employed, 


20        A   FIELD-MANUAL   FOR    RAILROAD    p:\OINEKRS. 

The  transit  need  only  be  set  at  alternate  stations  (which  may  be 
any  length  within  the  reading  limits  of  the  wires),  the  bearings  to 
other  stations  and  points  off  the  line  being  taken  with  the  needle. 
The  horizontal  angle  should  also  be  read  on  the  plates  for  points 
on  stadia  line,  as  a  check  on  the  bearings. 

E.  Obstacles  in  Tangent. 

40.  Obstructions  to  vision  and  measurement  in  tangent  may  be 
avoided  in  a  number  of  ways,  a  few  of  which  are  given  in  the 
following  problems.     Other  methods  of  avoiding  them  will  sug- 
gest themselves  in  special  cases. 

The  same  devices  may  be  used  on  location,  but  it  is  more  im- 
portant to  maintain  a  clear  sightvvay  then  ;  so0  when  possible,  we 
should  remove  the  obstruction. 

41.  To  Pass   an  Obstacle  by  Means  of  Parallel  Lines. — In 
Fig.  4,  0  is  the  obstruction,  AB  the  obstructed  line.     At  B  set 


FIG.  4. 

transit  ;  turn  90°  and  measure  BF  long  enough  to  clear  obstruc- 
tion. Set  transit  at  F,  make  BFG  —  90°,  and  measure  FG. 
Move  to  G  and  backsight  to  F,  making  FGC  =  90°.  Measure 
GC  —  FB,  and  move  to  C,  where  the  angle  GCD  is  made  equal 
to  90°.  CD  is  the  desired  line,  and  EC  =  FG. 

Otherwise,  at  A  and  B  erect  perpendiculars;  take  BF=AE; 
produce  EF,  and  at  G  and  II,  beyond  0,  erect  perpendiculars  mak- 
ing GG  =  HD  —  FB.  CD  will  be  the  desired  line,  and  BC  =  FG. 

42.  To  Pass  an  Obstacle  by  Angular  Deflections. 

GENERAL  CASE.     Angle  anything  less  than  90°. 

At  B  (Fig.  5)  on  the  obstructed  line  deflect  an  angle  a  to  one 
side  and  measure  BC,  taking  C  so  that  after  deflecting  2a  to  the 
other  side  CD  will  clear  the  obstruction.  Make  CD  =  BC  and 
deflect  an  angle  a  to  the  same  side  as  at  B;  DE  will  lie  in  AB 
produced.  Draw  CH  perpendicular  to  BD;  then 

cos  a (5) 


PRELIMINARY   SURVEYS. 


21 


&__ 


FIG.  5. 

EXAMPLE.— Suppose  a  =  14°  10',  BC=CD  =  520  ft. 
BD  =  2  X  520  X  0.96959  =  1008.37  feet. 
SPECIAL  CASE.     Angle  60  degrees. 

In  this  case  the  triangle  BDF(Fig.  6)  is  equilateral  and  BF  = 
BD  =  DF. 

Should  it  be  inconvenient  to  run  to  D  we  may  stop  at  C,  having 
measured  BC.     At  C  deflect  60°  and  measure  CE;  at  E  again  de- 


FIG.  6. 

fleet  60°  and  make  EF=  BC.     At  F  a  final  deflection  of  60°  in  the 
opposite  sense  will  put  the  telescope  in  the  desired  line,  FG,  and 
BF=BC+CE.     ......     (5a) 

43.  To  Pass  an  Obstruction,  such  as  a  River,  when  the  Pre- 
ceding Methods  are  Inapplicable. 
FIRST  CASE.     Point  beyond  obstruction 
In  Fig.  7  let  BC  be  required. 

.i.     c       , 


FIG.  7. 

At  7?  erect  and  measure  the  perpendicular  BD  ;  set  instrument 
at  D  and  measure  angle  BDC  =  a  ;  then 

BC=BDta,na (6) 


22        A    FIELD-MANUAL   FOR    RAILROAD   ENGINEERS. 

Or,  if  a  trigonometric  table  is  not  at  hand,  make  CDE  —  90°  and 
fix  the  point  E  where  DE  intersects  AB  ;  measuring  EB  there 
results,  from  similar  triangles, 

CB_BD 
BD  ~  EB' 

B2)'2 
whence  CB  =-f^-  ........     (6«) 

hih  v 

Otherwise,  if  a  right  angle  at  B  is   not  convenient,   measure 
angles  CBD  =  b,  BDC  =  a,  and  side  BD.    Then  c  =  180°-  (a+6). 
From  triangle  BDC, 

BC  =  BD^  ......     (66) 

sin  c 

EXAMPLE.—  a  =  56°,  b  =  70°,  £Z>  -  400  feet. 

sin  5fi° 

By  (66),  J5C  =  400  ^T    ^  =  409.8  feet. 

sin  54 


SECOND  CASE.     Poiw^  beyond  obstruction  invisible. 
At  B  (Fig.  8)  measure  angle  &  and   line  BE;  move  to  E  and 
measure  angle  y,  and  set  hubs  on  line  EG  so  the  line  BC  will  pass 


FIG.  8. 

between  them.     Angle  z  =  ECB  =  180  -  (b  -f  y\    Then  from  tri- 
angle BEG 

sin  z  ' 

Produce  EB  to  D,  where  DC  will  be  sure  to  clear  obstruction ; 
measure  BD. 

From  triangle  BDC, 

tan  \(a  -  x)  _  BC  -  BD 


But  «  +  «  =  &,  hence 

tan  \(a  -  *)  =  •  tan  tf .        ...     (8) 


PRELIMINARY    SURVEYS.  23 

The  sum  and  difference  of  a  and  x  are  now  known,  so  both  may 
be  readily  found. 

At  D  set  off  the  angle  a  with  the  transit,  and  have  the  chaiumen 
stretch  a  cord  between  the  hubs  set  on  line  EC  at  C.  Now  signal 
the  flagman  to  move  his  rod  along  this  cord  until  the  vertical  wire 
cuts  it  at  C.  Set  a  hub  here  and  place  the  transit  over  it.  Sight 
to  D  or  E,  reverse  telescope  and  deflect  into  CH. 

ARTICLE  4. — THE  LEVEL  PARTY. 

44.  The  Level  Party  consists  generally  of  two  members,  the 
leveler  and  a  rodman ;  sometimes  an  axeman  is  added  to  keep  the 
rod  man  supplied  with  pegs  for  turning-points  and  in  clearing  the 
line  of  sight  for  the  level.     As  the  party  follows  the  transit  little 
or  no  clearing  will. be  needed.     The  instruments  used  are  a  level, 
a  rod,  and  a  hand-axe  or  hatchet. 

45.  The  Leveler  makes  all   necessary  observations  with  his 
instrument,  keeping  a  neat,  accurate  record  of  readings  and  ele- 
vations ;  also  the  positions  and  elevations  of  benches  and  turning- 
points.     He  should  work  out  elevations  of  stations  while  the  rod- 
man is  going  from  one  station  to  the  next ;  he  must  see  that  the 
rodman  gives  him  readings  at  points  where  the  longitudinal  slope 
changes  suddenly,  recording  the  plus.     He  must  plot  his  profile 
at  night,  or  at  such  times  as  the  chief  of  party  is  likely  to  need  it. 
The  rodman 's  readings  at  turning-points  should  be  checked. 

46.  The  Rodman  holds  his  rod  at  each  station,  calling  out  the 
number.    If  stakes  are  set  only  at  even  stations,  he  must  hold  his 
rod  midway  between  stakes,  the  point  being  found  by  pacing  the 
distance.     Target-readings  need  only  be  taken  at  turning-points 
and  benches,  and  the  rodman  should  keep  a  record  of  these  in 
his  "peg-book,"  checking  the  calculations  of  leveler  for  heights 
of  instrument  and  elevations  of  turning-points.     At  any  marked 
surface  change  he  will  hold  his  rod,  calling  out  the  plus  to  leveler. 
He  must  assist  the  leveler  in  plotting  up  the  notes. 

A.  Adjustments  of  the  Level. 

47.  To  Adjust  the  Line  of  Collimation  is  to  bring  the  inter- 
section of  the  cross-wires  into  the  optical  axis  of  the  telescope. 

Set  up  and  level  the  instrument,  then  bring  the  vertical  wire 
into  coincidence  with  a  plumb  line  or  vertical  edge  of  a  building, 


24        A   FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 

at  the  mean  length  of  sight,  and  note  if  the  vertical  wire  is  truly 
parallel  thereto.  If  it  is  not,  loosen  the  capstan-headed  screws 
holding  cross-wire  ring  and  turn  slightly  so  that  the  wire  is 
parallel  to  the  vertical  line. 

Loosen  the  wye-clips  and  bring  the  vertical  wire  into  coin- 
cidence with  the  line  and  clamp  the  instrument.  Rotate  the 
telescope  in  the  wyes  180°  and  note  if  the  wire  coincides  with  the 
line.  If  not,  correct  one  half  the  error  by  loosening  one  and 
tightening  the  opposite,  of  the  capstan -headed  screws  that  hold 
the  cross-wire  ring  in  place,  remembering  that  the  image  of 
the  cross  wires  is  inverted  by  the  eyepiece. 

Turn  the  telescope  until  the  horizontal  wire  is  parallel  to  the 
plumb-line  or  edge  of  building,  and  make  the  same  test  and 
correction.  Repeat  for  both  wires.  The  horizontal  wire  is  the 
one  on  which  the  accuracy  of  leveling  depends,  but  it  is  wise  to 
have  both  adjusted.  Their  intersection  should  remain  on  a  point 
during  a  complete  rotation  of  the  telescope  in  the  wyes. 

48.  To  Adjust  the  Level-bubble  is  to  bring  the  axis  of  tho 
level-tube  into  the  same  vertical  plane  with  the  line  of  collimation, 
and  to  make  the  bubble  stand  at  the  center  when  the  line  of  sight 
is  horizontal. 

Since  the  axis  of  the  telescope  coincides  with  the  line  joining 
the  center  of  the  wye-rings  (which  requires  these  to  be  of  the 
same  size),  it  is  sufficient  to  make  the  axis  of  the  bubble  parallel 
to  this  line. 

(a)  With  the  telescope  over   one  diagonal   pair  of  leveling- 
screws  and  the  clips  loosened,  bring  the  bubble  to  the  center  of 
its  run  ;  then  turn  the  telescope,  in  the  wyes,  a  little  to  either  side 
of  the  vertical  plane  through  the  telescope  and  note  if  the  bubble 
remains  at  the  center.     If  not,  correct  the  error  by  means  of  the 
screw  at  end  of  the  level-tube  case  arranged  for  lateral  movement. 
Repeat  until  the  tube  may  be  rotated  half  an  inch  or  more  to 
either  side  of  vertical  without  movement  of  the  bubble.     This 
adjustment  is  made  merely  to  prevent  error  from  failure  to  set 
level-tube  vertically  beneath  telescope. 

(b)  With  the  wye-clips  opened  well  out,  again  bring  the  bubble 
to  the  center  of  its  run  ;  remove  the  telescope  from  wyes  and 
turn  it  end  for  end,  then  carefully  replace  it  in  the  wyes.    Should 
the  bubble  fail  to  remain  at  the  center,  bring  it  half-way  back  by 
raising  the  lower  or  depressing  the  higher  end  of  tube   at    ilic 
points  of  attachment  to  telescope.     Relevel  and  repeat  as  a  lest. 


PRELIMINARY   SURVEYS. 


49.  To  Adjust  the  Wyes  is  to  make  the  axis  of  the  telescope 
perpendicular  to  the  vertical  axis.      With   the  wye-clips  closed 
place  the  telescope  over  one  pair  of  leveling-screws  and  bring  the 
bubble  to  the  center  of  its  run  ;  then  turn  the  telescope  half-way 
round  on  its  vertical  axis,  so  that  its  ends  have  changed  places. 
If  there  is  any  error,  correct  by  bringing  the  bubble  half -way  back 
to  center  by  means  of  the  screws  connecting  wyes  with  level-bar. 
Repeat  until  the  bubble  remains  in  the  center  during  a  complete 
revolution. 

B.    Theory  of  Leveling. 

50.  When  the  level  has  been  adjusted  the  line  of  collimation 
will  describe  a  plane  parallel  to  the  horizontal  plane  tangent  to 
the  earth's  surface  at  the  point  where  the  instrument  is  placed. 
A  level  surface,  such  as  the  surface  of  still  water,  will  coincide 
with  this  plane  only  at  the  point  of  taugeucy,  and  will  depart 
farther  and  farther  therefrom  as  the  point    considered  recedes 
from  the  instrument.     For  short  sights  this  difference  may  be 
neglected  in  railroad  work,  as  will  presently  be  shown,  but  for 
long  sights  a  correction  must  be  applied. 

The  effect  of  curvature  is  to  make  objects  appear  lower  than 
they  really  are,  while  the  refraction  of  a  beam  of  light,  due  to 
the  greater  density  of  the  layers  of  air  nearest  the  earth's  surface, 
has  a  contrary  effect.  Experience  shows  the  average  error  due 
to  refraction  to  be  about  one  seventh  of  that  due  to  curvature. 

51.  The  Error  due  to  Curvature  at  any  point  is  the  deviation 

of  a  tangent  line  from  true  level,  as  -j^ t  p 

the  point  recedes  from  the  point  of 

tangency. 

Let  0  be  the  center  of  the  earth,  T 
the  point  of  taugeucy,  and  j^the  point 
where  the  error  due  to  curvature  is 
desired.  Let  the  notation  be  as  shown 
in  Fig.  9.  From  the  right  triangle 
OTP,  we  have 

(R  +  c)2  =  IP  +  t*. 

From  which 

t* 

=  2M  f  e  ' 

Now,  since  c  is  always  very  small  compared  with  27?,  the 
quotient  resulting  from  the  division  of  t-  by  27?  will  not  differ 


FIG.  9. 


26        A   FIELD-MANUAL   FOR   RAILROAD   ENGINEERS. 

sensibly  from  that  obtained  by  dividing  by  2J?  +  c.     Therefore 
we  write 


c  = 


(9) 


For  t  =  1  mile,   H  =  3963  miles,    c  =  about  8  inches.      Hence 
for  any  other  distance  in  miles  we  have,  for  c, 

c  =  S  X  t*  inches (9«) 

The    correction   for  refraction  is  about   -^c,  hence  we  have, 

from  (9), 

n  1         6         3  <2 

C^c--c  =  -c=-- 

or,  closely  enough, 

G  =  .85c (10) 

EXAMPLE.— What  is  the  correction  for  a  half-mile  sight? 
For  one  eighth  of  a  mile? 

By  (9«),        c  =  8  X  (£)9  =  2"  for  first  case, 
and  c  =  S  X  (I)2  =  0".125  for  second  case. 

By  (10)  the  final  correction  is 

c  =  0.85  X  2  =  1".7  for  first  case, 

c  =  0.85  X  0.125  =  0.106"  for  second  case. 

52.  The  Difference  of  Elevation  between  two  points  not  so 
far  apart  but  that  a  rod  may  be  read  on  each  from  some  inter- 
mediate point  may  be  readily  found  from  these  rod-readings. 

In  Fig.  10  let  the  instrument  be  at  1,  A  and  B  the  points 
whose  difference  of  elevation  is  desired.  Let  r  =  AD,  r'  =  BC. 
Since  the  line  of  sight,  DO,  is  horizontal,  the  difference  of 

C 


FIG.  10. 

elevation  will  evidently  be  if  —  r.  When  the  distance  from 
/  to  A  equals  that  from  I  to  £  the  errors  due  to  curvature 
evidently  balance. 


PRELIMINARY   SURVEYS.  £7 

When  the  points  are  so  situated  that  the  rod  cannot  be  read 
on  both  from  one   intermediate   position  of  the  instrument,  an 


FIG.  11. 

auxiliary  point  or  points  must  be  used  and  readings  taken  on 
these  points  in  pairs.  Thus  in  Fig.  11  suppose  the  difference 
of  elevation  of  A  and  B  required  : 

With  the  instrument  "at  /  read  on  A  and  some  intermediate 
point  E.  Considering  the  backsights  as  plus  and  foresights  as 
minus,  the  difference  of  elevation  of  A  and  E  is  AD  —  FE. 

Again,  with  the  instrument  at  /'  the  difference  of  elevation  of  E 
and  B  is  OE—  CB.  The  sum  of  these  differences  equals  the  dif- 
ference of  elevation  of  A  and  B,  and  may  be  written  (AD  -\-  GE) 
—  (EF  -{-  CB),  or,  in  general,  the  sum  of  the  backsights  less  the  sum 
of  the  foresights  equals  the  difference  of  elevation. 

C.  Field-work. 

53.  A  Datum  is  a  level  surface  so  taken  that  it  shall  lie  below 
the  lowest  point  likely  to  be  reached  by  the  profile,  to  which  the 
surface  elevations  are  referred.     It   is   often   spoken   of  as  the 
datum-line  or  datum-plane,  and  is  the  zero  of  elevations. 

54.  A  Bench-mark  is  a  permanent  mark,  such  as  a  copper  or 
other  bolt  let  into  the  top  of  a  solidly  fixed  stone,  whose  height 
above  the  datum  is  known;  it  may  be  simply  a  mark  on  a  stone, 
or  a  tack  driven  into  the  projecting  root  of  a  tree,  upon  which 
the  rod  may  be  read.     In  any  case  it  must  be  so  situated  that  it 
cannot  change  its  elevation  nor  is  likely  to  be  disturbed  within 
the  time  for  which  it  is  intended  to  be  used  as  a  standard  of 
reference. 

The  elevation  should  be  marked  on  some  object  adjacent  to 
the  bench,  with  the  letters  B.  M.  indicating  the  nature  of  the 
point. 


28        A    FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

55.  The  Field-work   consists  in  finding  the  elevation  of  a 
number  of  points  on  the  line  established  by  transit  party  suffi- 
cient to  give,  when  plotted,  a  fairly  correct  outline  of  the  surface 
as  seen  in  profile. 

A  bench-mark  is  taken  at  the  beginning  of  the  line,  and  its  dis- 
tance above  mean  sea-level  or  other  datum  is  known  or  assumed. 
The  level  is  set  with  one  pair  of  leveling  screws  in  the  line  to  be 
run  (in  order  that  any  change  in  the  position  of  the  bubble  may 
be  easily  corrected),  and  the  rod  is  read  on  the  bench.  This  read- 
ing plus  the  elevation  of  bench  gives  the  height  of  instrument 
(//.  /.)  above  the  datum. 

Readings  are  taken  at  every  hundred  feet  along  the  line,  or 
oftener  if  the  surface  changes  greatly,  until  a  point  is  reached 
beyond  which  it  is  desired  to  move  the  level.  A  peg  is  driven 
firmly  into  the  ground  and  the  rod  read  on  this ;  the  height  of 
instrument  less  the  rod  reading  will  give  its  elevation,  as  it  will 
for  the  intermediate  points.  This  point  is  a  temporary  bench 
and  is  called  a  turning-point.  It  should  be  marked  by  a  guard- 
stake  if  it  is  desired  to  use  it  again.  The  instrument  is  now  car- 
ried beyond  the  turning-point,  set  up,  and  the  whole  process 
repeated.  Benches  and  turning-points  should  be  read  to  hun- 
dredths  or  thousandths  of  a  foot,  intermediate  points  to  tenths. 
Turning-points  are  marked  0  or  T.  P.  in  the  notes,  and  their 
positions,  as  also  the  bench-marks,  noted  by  both  leveler  and 
rodman  in  their  note-books. 

56.  The  Level  Notes  may  be  kept  in  any  convenient  form 
that  is  easily  understood.     The  following  is  used  more  exten- 
sively, perhaps,  than  any  other: 


Sta. 

B.  S. 

H.I. 

F.  S. 

Elev. 

Remarks. 

B.M. 

5.613 

205.613 

.... 

200.0 

j  B.  M.  on  root  of  L.  O.  tree  60'  to 
1  right  of  line. 

0 

.... 

2.3 

203.3 

1 

0.8 

204.8 

2 

5.7 

199.9 

3 

7.8 

197.8 

4 

9.9 

195.7 

© 
5 

1.120 

196.310 

10.423 
6.3 

195.190 
190.0 

1  On  peg  at  4  -f  30'  -  20'  to  left  of  line, 
J  by  small  P.  O.  tree. 

6 

4.5 

191.8 

Here  the  elevation  of  the  datum  was  taken  200.  00  feet  below 
the  first  bench-mark.     The  instrument  was  set  up  near  Station  2, 


PRELIMINARY    SURVEYS.  29 

and  a  reading  of  5.613  taken  on  the  bencb;  this  was  written  in 
the  B.  S.  column,  and  when  added  to  the  elevation  of  the  bench 
gives  the  height  of  instrument,  205.613.  A  reading  of  2.3  was 
taken  on  Sta.  0,  recorded  in  the  F.S.  column,  and  when  sub- 
tracted from  the  H.I.  yields  an  elevation  of  203.3.  The  eleva- 
tions of  other  points  were  determined  in  the  same  way.  A  little 
beyond  Station  4  the  rod  man  drove  a  peg  and  held  the  rod  on  it, 
yielding  a  reading  of  10.423  and  an  elevation  of  195.190.  The 
instrument  was  then  moved  to  a  point  near  Station  7  and  a  read- 
ing of  1.120  taken  on  the  peg;  this  added  to  195.190  made  the 
new  II.  I.  196.310,  and  the  process  continued  with  this  H.  I. 

In  most  cases  it  will  be  sufficient  to  read  benches  and  turning- 
points  to  hundredths  and  intermediate  points  to  tenths. 

It  will  be  seen  from  the  notes  that  any  error  in  a  turning-point 
causes  the  same  error  in  all  succeeding  points.  To  guard  against 
this  the  roclman  is  required  to  keep  a  "  peg-book,"  in  which  the 
heights  of  instrument  and  elevations  of  turning-points  are  re- 
corded, and  which  must  check  with  the  leveler's  record. 

57.  Wind  and  sunshine  affect  the  accuracy  of  the  work  with 
the  level,  as  is  also  the  case  with  the  transit.  For  very  great 
accuracy  a  calm,  cloudy  day  is  the  best,  but  the  railroad  engineer 
cannot  always  choose  the  best  times  for  his  work,  and  must  take 
such  precautions  as  may  be  possible  while  he  exercises  the  great- 
est care  to  prevent  and  detect  errors.  The  adjustments  should 
be  tested  at  least  once  a  week,  even  when  the  greatest  care  has 
been  taken,  for  unequal  expansion  and  other  causes  may  con- 
spire to  cause  them  to  change. 

By  making  foresights  and  backsights  to  turning-points  about 
equal  the  error  due  to  curvature  will  be  eliminated;  the  readings 
of  rodman  at  these  points  should  also  be  checked.  The  roclman 
should  hold  his  rod  vertical,  which  is  sometimes  accomplished 
by  means  of  a  level  attached  to  rod;  or  the  leveler  can  tell  by  his 
vertical  wire  when  the  rod  is  in  the  same  vertical  plane  with  the 
instrument,  and  by  causing  the  rodman  to  wave  his  rod  back  and 
forth  slowly,  after  clamping  the  target,  he  can  tell  if  the  hori- 
zontal wire  just  bisects  the  target  at  its  highest  position. 

58.  The  Rod  should  be  graduated  to  feet  and  tenths,  reading 
by  target  at  turning-points  and  benches;  intermediate  readings 
are  made  by  the  leveler  at  his  instrument.  Strength  and  dura- 
bility are  essential  qualities.  The  Philadelphia  rod  seems  to 


30        A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 

answer  the  purpose  as  well  as  any  other  now  manufactured;  the 
Troy  rod  may  be  used  in  the  same  manner  as  the  Philadelphia 
rod,  but  is  lighter  and  less  able  to  stand  rough  usage. 

ARTICLE  5.  THE  TOPOGRAPHIC  PARTY. 

59.  The  Topographic  Party  follows  the  level  and  secures  all 
the  data  necessary  for  making  an  accurate  contour-map  of  a  strip 
of  country  extending  as  far  each  side  of  the  preliminary  as  may 
be   needed   for   the   intelligent   projection   of  the   location-line. 
This  distance  may  vary  from  50  to  300  or  400  feet,  its  width  de- 
pending on  the  difficulties  to  be  encountered  and  the  degree  of 
precision  with  which  the  preliminary  approximates  to  the  final 
location-line.      The  lateral  slope  of  surface  is  obtained  at  the 
stations  of  preliminary  by  means  of  the  hand-level  and  tape,  by 
the  slope-level  or   clinometer,  by  cross  section   rods,  or   by  the 
transit  and  stadia.     Strictly  speaking  the  topography  includes  all 
the  surface  features,  but  for  railroad  work  the  surface  elevations, 
streams,  and  nature  of  surface  are  the  most  important;  it  may 
be  necessary  to  note  the  positions  of  roads,  buildings,  etc.,  and 
should  always  be  done  when  practicable  without  undue  loss  of 
time.     A  pocket-compass  will  be  of  use  in  observing  the  bear- 
ings of  lines. 

60.  There  are  two  methods  of  recording  the  data  obtained; 
one  by  means  of  notes  and  sketches  in  a  book,    the  other  by 
drawing  the  contours  directly  on  the  field-sheet  as  the  data  are 
obtained.   Station  elevations  can  be  taken  direct  from  the  leveler'g 
notes,  and  constitute  the  base  on  which  the  contour  elevations 
rest. 

Suppose  the  hand-level  to  be  used  and  the  notes  kept  in  a  book, 
to  be  afterwards  transferred  to  the  map.  Starting  with  the 
known  center  elevation,  the  topographer  notes  the  height  of  his 
eye  above  the  ground  and  calculates  the  height  of  center  above 
or  below  the  next  contour;  from  this  the  reading  of  the  rod  when 
held  on  this  contour  is  found,  being  the  height  of  station  above 
contour  plus  the  height  of  eye.  He  directs  the  slopeman  in  or 
out  on  a  line  at  right  angles  to  preliminary  until  this  reading  is 
given  by  the  hand-level;  the  distance  out  is  then  measured  and 
recorded,  just  as  in  setting  slope-stakes,  and  the  slopeman  di- 
rected into  position  on  the  next  contour,  in  the  same  manner. 

Thus  if  5-foot  contour-intervals  are  employed,  and  the  station 


PRELIMINARY 


UNIVERSITY 

RVEY33= 


31 


elevation  is  321.  6  feet  und  the  height  of  eye  5.3  feet,  we  shall  have 
for  the  reading  at  the  320-foot  contour  5.3  +  (321.6  —  320)=  6.9. 
Motion  the  slopeman  down  the  slope  until  his  rod  reads  6.9  and 
measure  the  distance  out,  suppose  21  feet.  The  315-foot  contour 
will  be  5  feet  lower,  giving  a  reading  of  11.9,  which  may  be 
found  in  like  manner  at,  say,  80  feet  out.  As  the  rod  reads  only 
to  about  12  feet  the  topographer  must  move  out  to  this  last  point, 
and  with  the  reading  5.3  -f-  5=  10.3  find  the  310-foot  contour  in 
the  same  way.  On  the  up-hill  side  the  325-foot  contour  will  be 
found  with  a  reading  of  5.3  -  (325  -  321.6)  =  1.9  feet,  and  other 
contours  in  like  manner. 

The  notes  may  be  written  thus 


Sta. 

Left. 

Center  Elev. 

Right. 

824 

305   310   315   320 
T93'  125'   80'   2l 

321.6 

325  330   335   340 
27  '  "56"'  "80"'  112 

The  number  above  the  line  is  the  contour  elevation,  the  num- 
ber below  its  distance  out  from  center. 

If  preferred  the  elevation  can  be  taken  at  regular  distances  out 
and  recorded  as  above;  the  position  of  the  contour  will  then  be 
fouud  by  interpolation  when  mapping  the  work. 

61.  If  the  topography  is  to  be  plotted  in  as  the  work  progresses 
the  topographer  must  have  a  light  drawing-board  with  a  pocket 
and  flap  on  back  for  holding  the  sheets  on  which  the  transit-line 
has  been  plotted  the  night  before  ;  the  station  elevations  are 
marked  on  the  line  and  the  contour  positions  spotted  in  as  ob- 
tained by  slopemen,  after  which  the  contours  are  sketched  in. 
Points  where  contours  cross  transit-line  are  found  in  the  same 
manner  as  side  points.  The  size  of  the  sheets  will  depend  on  the 
taste  of  topographer  and  size  of  drawing-board;  17x24  to  19x28 
inches  are  good  sizes. 

The  topographer  will  soon  learn  to  guess  at  the  position  his 
contours  will  occupy  at  the  next  station  ahead,  and  will  sketch 
them  in  lightly,  to  be  erased  and  corrected  when  necessary.  It  is 
often  sufficient  to  take  lateral  readings  at  every  second  or  third 
station. 


62,  If  the  Slope  level  is  used,  the  inclination  of  the  surface  is 
obtained;  then   by  the  use  of  a  scale  constructed  to  show  the 


32        A    FIELD-MANUAL   FOR   RAILROAD    ENGINEERS.  * 

horizontal  distance  apart  of  contours,  for  the  given  contour-in- 
terval, for  slopes  varying  from  1°  to  20°,  the  position  of  contours 
can  at  once  be  spotted  on  the  map.  Wellington  recommends  the 
use  of  the  altazimuth  as  permitting  the  employment  of  either 
method  at  will — the  altazimuth  being  merely  a  hand-level  with 
a  clinometer  attached. 

63.  Cross-section  Rods  are  measuring- rods  10  or  12  feet  long 
'carrying  a   level-bubble.     By   placing  one  end  at   the   center, 

bringing  the  rod  horizontal,  and  noting  the  height  of  the  end  of 
rod  on  the  down-hill  side,  the  slope  may  readily  be  obtained  and 
the  contours  worked  in  as  before.  For  very  rough,  broken 
ground  this  method  may  be  preferable  to  either  of  the  others. 

64.  If  the  Transit  and  Stadia  are  employed,  very  elaborate 
topography  may  be  taken  with  very  little  field-work,  but  the  ob- 
servations require  considerable  reduction.     With  a  suitable  topo 
graphic  protractor  and  the  slide-rule  mentioned  in  33,  the  large 
number  of  points  that  may  be  obtained  from  each  setting  of  the 
transit  may  be  readily  plotted  and  their  elevations  marked  on  the 
plot,  after  which  the  contour-lines  can  be  worked  in,  and  other 
features  mapped.     For  small  vertical  angles  no  horizontal  reduc- 
tion is  needed. 

While  not  generally  favored  by  railroad  engineers  in  the  past, 
this  method  is  probably  the  most  rapid  and  economical  of  any  so 
far  employed  in  topographic  work. 

ARTICLE  6.  PRELIMINARY  ESTIMATES. 

65.  After  completing  the  field-work  of  the  preliminary  survey 
the  party  is  usually  disbanded,  only  the  transitman,  leveler,  and 
topographer  being  retained  to  assist  the  chief  of  party  to  complete 
the  map,  profile,  and  estimate  of  cost. 

66.  The  Map  may  be  drawn  to  any  suitable  scale,  but  less  than 
400  feet  to  the  inch  is  not  to  be  recommended  where  it  must  be 
used  in  projecting  location.     The  transit-line  is  laid  down  first 
and  the  topography  worked  in  afterwards  from  the  field-map  or 
topographer's  notes.     If  it  is  wanted  on  a  continuous  sheet,  the 
transit-line  must  first  be  drawn  on  a  succession  of  small  sheets, 
which  are  added  as  the  plotting  progresses,  a  new  sheet  being 
slipped  under  the  edge  of  the  preceding  and  tacked  down  when 


PRELIMINARY    SURVEYS.  33 

required.  The  overlapping  edge  is  marked  by  a  number  of  short 
Hues  extending  over  onto  the  sheet  beneath,  to  enable  one  to  re- 
place in  the  proper  position.  When  the  line  has  been  plotted  the 
sheets  are  pasted  together  and  the  whole  shifted  so  as  to  bring  the 
transit-line  over  the  continuous  sheet.  Angular  points  are  then 
pricked  through  and  the  line  drawn  on  the  continuous  sheet. 
Ordinarily  it  will  answer  to  have  the  map  drawn  on  a  succession 
of  small  sheets,  to  be  joined  together  as  required. 

The  plotting  had  best  be  done  by  bearings,  though  it  may  be 
done  from  the  deflection  angles,  provided  care  is  used  to  check 
frequently  by  bearings.  Otherwise  an  error  in  one  angle  wilL 
throw  all  the  remaining  portion  of  the  line  out  of  position. 

If  more  than  one  preliminary  was  run,  they  should  all  be  shown 
on  the  same  sheet  whenever  possible. 

67.  The  Profile  will  be  drawn  by  the  leveler  on  profile-paper, 
and  shows  a  developed  vertical  projection  of  the  line.     The  scale 
will  depend  on  the  paper  used.     There  are  three  scales  in  general 
use,    styled   respectively  Plates  "A,"  "B,"  and  "  C."    There  is 
also  a  metric  profile-paper.     Plate  "  A  "  has  the  vertical  exagger- 
ated 20  to  1  as  compared  with  the  horizontal  and  is  the  best  to 
use  where  much  rockwork  is  expected.     The  vertical  exaggera- 
tion of  Plate  "  B"  is  less  than  of  Plate  "A  ";  this  plate  is  most 
used  for  ordinary  earthwork. 

A  strip  of  color  laid  on  below  the  surface-line,  and  fading  out 
at  the  lower  edge,  adds  greatly  to  the  appearance  of  the  profile. 
The  tentative  grade-line  and  points  of  change  should,  be  drawn  in 
red. 

68.  Preliminary  Estimates  of  quantities  are  made  by  assuming 
a  grade-line  and  drawing  it  on  the  profile;  then  the  cuts  and  fills 
are  taken  from  the  profile,  and  the  corresponding  quantities  ob- 
tained from  Table  XIX  for  the  base  the  road  is  intended  to  have 
when  completed.     The   nature  of  the  work,  whether  ordinary 
earth  or  rock,  can,  of  course,  be  only  roughly  estimated. 

Bridging  is  estimated  from  the  profile  where  piling  or  framed 
bents  may  be  used,  but  where  piers  and  long  spans  are  needed 
special  surveys  with  soundings  are  required,  Culverts,  drains, 
cattle  guards,  cross-ties,  and  rails  for  main  line  and  sidings, 
switch  stands,  buildings,  right  of  way,  clearing,  and  other  factors 
entering  into  the  question  of  cost  must  all  be  considered  aud 
allowed  for  in  making  up  the  estimate. 


34        A   FIELD-MANUAL   FOE   RAILROAD    ENGINEERS. 

Engineering  expenses  and  unforeseen  outlays  that  are  sure  to 
arise  should  have  a  liberal  allowance. 

69.  The  Report  of  the  chief  of  party  should  set  forth  the  ad- 
vantages and  probable  cost  of  each  of  the  several  lines  run 
when  there  is  more  than  one.  On  this  report  frequently  depends 
whether  or  not  the  line  is  to  be  located,  and  it  should  be  clear 
and  exhaustive,  though  plainly  and  concisely  worded.  The  map 
and  profile  form  an  integral  part  of  the  report  and  show  from 
what  data  the  estimates  were  derived. 


CHAPTER  III. 

LOCATION. 

AUTICLE  7.     PROJECTING  LOCATION. 

70.  After  the  preliminary  lias  been  mapped  and  the  topography 
worked  iu,  the  engineer  proceeds  to  make  a  paper  location  for  his 
guidance  in  the  field.     The  solution  of  the  varied  and  complex 
problems  that  confront  him   are  more  or  less  interdependent. 
The  guiding  principle,  applicable  to  all  departments  of  engineer- 
ing, that  the,  best  structure  is  that  which  for  the  least  cost  best  an- 
swers the  purpose  for  which  it  was  intended,  should  control,  even 
though  the  resulting  structure  be  inferior,  in  point  of  scientific 
design,  to  some  other.     The  best  road  as  regards  construction  and 
grades  may  be  a  failure  because  of  excessive  first  cost,  while 
the  cheapest  construction  will  entail  such  heavy  operating  ex- 
penses that  it  may  b'e  equally  unprofitable.     The  alignment  must 
be  as  free  from  curves  as  possible,  while  heavy  grades  are  at  the 
same  time  excluded;  these  two  requirements  conflict  and  must 
be  as  well  adjusted  as  possible.     The  amount  of  earthwork,  of 
bridging  and  other  structures  must  be  kept  down  to  the  lowest 
limits. 

71.  Starting  at  the  summit  of  the  most  difficult  portion  of  the 
route,  assume  a  starting-point  and  elevation;  with  the  dividers  set 
at  such  a  distance  to  the  scale  of  the  map  as  will  give  a  fall  of  one 
contour-space — or  half  space— for  the  assumed  grade,  step  down 
the  slope  in  such  a  way  that  the  dividers  fall  each  time  on  the 
next  lower  contour,  or  half-space,  according  to  the  fall  assumed  in 
setting  dividers.     If  curve  compensation  is  allowed,  the  dividers 
must  be  reset  for  each  curve,  for  the  same  fall,  since  the  grade 
will  be  slackened  on  curves.     The  points  at  which  the  dividers 
fall  are  lightly  spotted  on  the  map  and  connected  by  a  grade 
contour,  which   represents  the  surface-line  having  the  required 
gradient.     This  line  will  be  too  broken  to  be  used  as  a  location- 

35 


36        A    FIELD-MANUAL    FOR   RAILROAD    ENGINEERS. 

line,  so  we  have  then  to  draw  on  the  map  a  succession  of  curves 
aud  tangents  that  will  approximate  sufficiently  close  to  it,  at  the 
same  time  that  a  proper  balance  is  maintained  between  earthwork 
and  curvature. 

Having  lightly  plotted  the  proposed  line,  the  elevations  are 
transferred  to  profile-paper,  thus  giving  a  profile  of  the  line. 
With  a  fine  thread  stretched  along  the  profile,  to  represent  the 
grade-line,  adjust  the  cuts  and  fills  to  suit  the  nature  of  the  work. 
In  general,  fills  are  cheaper  than  cuts  both  in  construction  and 
maintenance;  and  especially  is  this  true  where  a  shallow  surface 
layer  of  earth  is  underlaid  by  rock.  It  may  happen  that  the 
material  from  excavation  must  be  used  in  embankment,  when 
the  cuts  and  fills  must  be  made  to  balance  by  shifting  the  grade- 
line  until  this  appears  to  be  the  case  on  the  profile. 

At  the  stream  crossings  the  grade-line  must  be  kept  safely 
above  high-water  mark,  so  that  sufficient  waterway  is  provided, 
and  allowance  made  therefor. 

After  locating  the  most  difficult  portions  pass  on  to  the  easier 
work,  returning  later  on  to  study  the  effect  this  will  have  on  the 
part  first  located.  It  may  be  necessary  to  go  over  the  projection 
several  times  before  you  can  be  reasonably  sure  that  the  best  loca- 
tion has  been  projected;  even  then  the  study  of  the  liue  in  the 
field  will  cause  many  of  the  details  to  be  altered,  sometimes 
materially. 

Long  grades  are  to  be  preferred  to  short  ones,  but  questions  of 
economy  may  necessitate  the  latter  in  order  to  lighten  work;  care 
must  be  taken  that  the  grades  are  not  so  badly  "  chopped"  that 
they  interfere  with  the  easy  riding  of  the  train. 

In  projecting  the  line  it  will  generally  be  best  to  strike  the 
curves  first  and  draw  the  tangents  afterwards,  though  it  some- 
times happens  that  long  tangents  will  control  the  curves;  when 
this  is  the  case  the  tangents  are  drawn  to  intersection  and  the 
curves  afterwards  put  in. 

When  transition-curves  are  employed,  a  slight  offset  should  be 
made  at  the  beginning  and  end  of  curves  to  allow  for  their  inser- 
tion in  the  field.  These  offsets  will  be  so  small  that  it  is  useless 
to  attempt  to  show  them  to  scale. 

72.  A  Curve-protractor  will  be  of  material  assistance  in  find- 
ing the  degree  of  curve  required  to  unite  two  tangents  that  have 
been  laid  down  on  the  map.  It  consists  of  a  transparent,  semi- 
circular protractor  having  a  series  of  curves  from  30'  up  to  8° 


LOCATION.  37 

plainly  cut  upon  it.  The  curves  are  on  both  sides,  those  on  the 
reverse  side  having  their  concavities  turned  in  an  opposite  sense 
from  those  on  the  face.  The  scale  is  usually  400  feet  to  the  inch, 
and  in  any  case  the  map  and  protractor  must  be  drawn  to  the 
same  scale.  Sometimes  a  set  of  cardboard  or  hard-rubber  curves 
are  used,  but  they  are  inferior  to  the  curve-protractor.  To  use 
it,  simply  prolong  tangents  to  intersection  and  then  place  the 
protractor  so  that  the  curve  admitting  of  the  best  grade  is  tan- 
gent to  the  two  straight  lines.  Mark  the  points  of  taugency, 
which  will  be  the  beginning  and  end  of  curve.  When  the  curve 
is  required  to  pass  through  a  given  point  the  proper  curve  may 
be  immediately  found  by  trial,  whereas  the  calculations  would 
require  some  little  time. 

Reversed  curves  should  never  be  allowed  on  main  lines.  Suffi- 
cient tangent  should  be  interposed  to  allow  space  for  easing  off 
the  superelevation  of  outside  rails,  or  for  the  insertion  of  tran- 
sition-curves when  these  are  to  be  employed. 

73.  The  Field  Corps  is  substantially  that  required  on  the  pre- 
liminary survey,  and  the  methods  of  work  pretty  much  the  same, 
except  that  curves  must  now  be  run  in,  and  this  necessitates  more 
clearing.  If  first  and  second  location-lines  are  to  be  run  (and  it  is 
real  economy  to  run  both),  it  will  not  be  necessary  to  have  the 
stationing  continuous  on  the  first,  so  the  pluses  arising  from 
"  backing  up"  need  only  be  noted  and  eliminated  when  the  final 
location-line  is  run.  If  transition-curves  are  to  be  inserted,  they 
need  not  be  run  the  first  time,  the  proper  offset  being  made  at 
the  P.  T.  or  P.  C.  of  the  circular  curves,  which  latter  are  to  be  run. 

On  the  final  location-line  the  stationing  must  be  continuous, 
beginning  with  zero.  The  stakes  are  marked  as  on  the  pre- 
liminary survey,  and  all  hubs  that  are  likely  to  be  used  again 
must  be  referenced  in,  the  reference-hubs  being  set  well  out  of 
the  way  of  disturbance  by  the  plow  or  scraper. 

The  leveler  should  make  bench-marks  every  1000  or  2000  feet, 
to  be  used  in  running  check-levels  and  in  giving  grades  later  on. 

From  the  paper  location  the  notes  should  be  made  up  in  the 
office,  to  serve  as  a  guide  in  the  field;  however,  no  attempt  should 
be  made  to  adhere  rigidly  to  them,  since  slight  errors  in  the 
mapping  will  affect  the  projected  line,  while  in  the  field  the  line 
may  be  shifted  here  and  there  so  as  to  fit  the  ground  more  snugly 
and  accord  more  closely  with  what  the  nature  of  the  earthwork 
demands. 


B8        A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 

The  highest  skill  of  the  engineer  is  required  to  secure  the  best 
location-line,  and  he  should  have  all  the  time  he  needs.  Undue 
baste  on  location— as  on  reconuoissance  and  preliminary— is 
almost  sure  to  result  in  increased  cost  of  construction. 


ARTICLE  8.    SIMPLE  CURVES. 

A.  Definitions  and  Formulas. 

74.  The  Circular  Curves  that  are  usually  employed  to  unite 
straight  reaches  of  the  railroad  may  be  simple,  compound,  or  re- 
versed. The  use  of  reversed  curves  should,  however,  be  limited 
to  turnouts  and  cross-overs. 

a.  A  Simple  Curve  is  the  arc  of  a  circle. 

b.  A  Compound  Curve  consists  of  two  simple  curves,  of  differ- 
ent radii,  both  on  the  same  side  of  a  common  tangent. 

c.  A  Reversed  Curve  is  made  up  of  two  curves  of  contrary 
flexure  having  the  same  or  different  radii,  and  a  common  tangent. 

d.  The  Point  of  Curve  (P.O.)  is  the  end  of  tangent  and  begin- 
ning of  curve,  as  at  A,  Fig.  12. 


FIG.  12. 

e.  The  Point  of  Tangent  (P.T.)  is  the  end  of  curve  and  be- 
ginning of  tangent,  as  at  B  of  Fig.  12. 

/.  The  Point  of  Intersection  (P.I.)  is  the  point  where  the 
tangent  at  the  P. C.  and  P.T.  intersect  when  produced.  (D  of 
Fig.  12.) 

g.  The  Intersection  Angle  (T\  is  the  angle  at  the  P.I.  be- 
tween the  tangents  meeting  there,  and  equals  the  angle  at  the 
center. 

h.  The  Tangent  Distance  (T)  is  the  length  of  the  produced 
tangent  measured  from  the  P.  C.  or  P.  T.  to  the  P.I.  The  term 


LOCATION. 


39 


tangent  is  applied  to  any  straight  portion  of  the  line,  but  the  letter 
T  will  be  used  to  designate  the  produced  portion  only. 

*".  The  Mid-ordinate  (M)  is  the  portion  of  the  radius  inter- 
cepted between  the  arc  and  chord  when  it  cuts  the  chord  at  its 
middle  point. 

j.  The  External  (E)  is  the  part  of  the  radius  produced  to  the 
P.L,  intercepted  between  curve  and  the  P.I. 

k.  The  Long  Chord  (L.C.)  is  the  chord  joining  the  P.  C.  and 
P.  T.  Frequently  the  term  is  applied  to  any  chord  longer  than 
the  unit  chord. 

I.  The  Radius  will  be  denoted  by  R. 

in.  The  Point  of  Compound  Curve  (P.  G.  C. )  is  the  point  of 
common  tangency  of  the  two  branches  of  a  compound  curve. 
(See  Fig.  13.) 


n.  The  Point  of  Reversed  Curve  (P.R.C.)  is  the  point  of 
common  tangeucy  of  the  two  branches  of  a  reversed  curve. 

o.  The  Degree  of  Curve  (JO)  is  the  angle  at  the  center  sub- 
tended by  the  unit  chord.  In  the  United  States  this  chord  is  100 
feet,  in  England  66  feet,  and  where  the  metric  system  is  em- 
ployed it  is  taken  at  20  meters.  Any  convenient  chord  length 
may  be  taken,  but  for  uniformity  American  engineers  have 
adopted  the  chord  of  100  feet,  and  unless  otherwise  stated  it  is 
always  so  understood  when  we  speak  of  the  degree  of  curve. 

Half  the  degree  of  curve  is  called  the  deflection-angle,  since 
it  is  the  angle  to  be  deflected  from  the  tangent  to  the  chord. 

If  there  were  any  practical  method  of  measuring  around  the 
curve  instead  of  along  the  chord,  an  accurate  and  convenient 
ratio  for  expressing  the  radius  in  terms  of  the  degree  would  be 
hud.  Thus  if  D  is  the  angle  at  the  center  subtended  by  the  arc 
of  unit  length,  we  have,  where  a  is  this  unit  arc, 


40        A   FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 


Hence 


. 


a     360 
'        ' 


When  a  equals  100  ft.  this  becomes 
100    360 


(11) 


(HO 


R  varies  inversely  as  D,  so  that  knowing  the  radius  for  a  1° 
curve,  we  should  have  only  to  divide  this  by  D  to  get  the  radius 
for  a  D°  curve. 

Since  the  chord  is  employed  instead  of  the  arc,  we  determine 
H  by  means  of  the  following  problem 

75.  Given  the  Chord  C,  and  Degree  of  Curve  D,  to  Find  the 
Radius  R. 

In  Fig.  14,  AB  is  the  chord  C,  OE  a  perpendicular  from  the 
center  upon  AB 


From  the  right  triangle  AEO  we  have 
R  sin  \V  =    C. 


Whence 


When  (7  is  100  ft., 


50 


(12) 


=  50  cosec  \D (120 


LOCATION.  41 

Comparing  results  given  by  formula  (12')  with  those  given  by 
(IT),  we  have  for  a  few  curves: 

Degree  of  Curve.  R  by  (12').  -K  by  (IT).  Difference. 

1  ............  5729.65  5729.58  0.07 

2  ............  2864.93  2864.79  0.14 

3  ............  1910.08  1909.86  0.22 

5  ............  1146.28  1145.92  0.36 

7  ............  819.02  818.51  0.51 

10  ............       573.69  572.96  0.73 

14  ............      410.28  409.26  1.02 

20  ............      287.94  286.48  1.46 

The  difference  is  seen  to  be  about  one  half  a  foot  for  a  7° 
curve,  one  foot  for  a  14°  curve,  and  one  and  one-half  feet  for  a 
20°  curve. 

Up  to  a  7°  curve  the  difference  is  inconsiderable,  and  we  may 
stake  out  curves  with  100-  foot  chords.  From  7  to  14  degrees  50- 
foot  chords  may  be  used.  Therefore 


"        =    cosec 


For  curves  from  14°  to  28°  we  should  use  25-foot  chords, 
for  which 


=  12.5  CoSec  ID.  (12'  b) 


Above  28°  shorter  chords—  say  10  feet—  should  be  used,  if  the 
curve  cannot  be  struck  from  the  center.     In  this  case 


Table  I  of  radii  was  computed  by  formulas  (12'),  (12'a),  and 
(12'ft). 

In  practice  it  is  customary  to  take  the  radius  of  a  1°  curve  as 
5730  feet  and  to  assume  the  radii  to  vary  inversely  as  the  degree  ; 
thus  for  a  4°  curve  the  radius  would  be  R=  *J4£  =  1432.5  feet, 
while  by  Table  I  it  is  1432.69  feet—  a  difference  of  only  .19  foot  ; 
for  a  12°  curve  JR  =  ^jp  =  477.5  feet,  while  by  Table  I  it  is 
477.68  feet.  The  effect  of  taking  5730  instead  of  5729.65  for  the 
radius  of  a  1°  curve  is  to  reduce  the  error  resulting  from  the 
assumption  that  11  equals  5730  divided  by  the  degree  of  curve. 


42        A    FIELD-MANUAL    FOR    RAILROAD    ENGINE K US. 

76.  The  Length  of  Curve  (L)  is  found  by  dividing  the  angle 
at  the  center  (which  equals  the  intersection)  angle)  by  the  degree 
of  curve,  the  result  being  in  chains  and  decimals  of  a  chain.    The 
number  of  P.  G.  -j-  L  will  give  the  station  number  of  P.  T. 

EXAMPLE.— The  P.  C.  of  a  4°  curve  having  /  =  26°  30'  is  at  sta. 
104  + 12.5.  Find  L  and  the  number  of  the  P. T.  Here 

no  K 

L=  -^  =  6. 625  chains. 

104.125  -f-  6.625  =  110.75  ;  hence  the  number  of  P.  T.  is 
110  +  75. 

77.  Use  of  the  Table  of  Functions  of  a  One-degree  Curve. — 

In  the  location  of  railway  curves  geometrical  accuracy  will 
frequently  be  of  less  importance  than  rapidity  of  field-work,  so 
long  as  errors  are  kept  within  certain  limits. 

On  tangents  slight  errors  of  alignment  may  readily  be  detected 
by  the  unaided  eye,  but  on  curves  these  are  not  so  apparent. 
Moreover  it  is  not  likely  that  the  trackmen  will  keep  them  up  in 
the  exact  position  of  their  location. 

To  simplify  and  shorten  the  field  computations  engineers  make 
use  of  a  table  of  functions  of  a  1°  curve,  and  assume  these  func- 
tions for  other  curves  to  vary  inversely  as  their  degree,  or  directly 
as  their  radii.  Table  IX  gives  values  of  the  tangent  distances, 
long  chords,  mid-ordinates,  and  externals  for  a  1°  curve,  the 
radius  of  which  is  taken  as  5730  feet.  To  find  these  functions 
for  other  curves,  divide  the  tabular  values  by  the  degree  of  curve. 
The  error  resulting  from  this  assumption  will,  in  any  practical 
case,  amount  to  no  more  than  a  few  tenths  or  huudrcdths  of  a 
foot. 

Table  IX  may  also  be  used  as  a  metric  curve  table,  the  tabular 
values  being  taken  as  meters  instead  of  feet,  If  the  unit  metric 
chord  is  20  meters  long,  this  may  be  taken  as  one  fifth  of  the 
tabular  unit  chord;  so  to  use  the  table  multiply  the  metric  degree 
by  5  and  enter  the  table  with  the  result  as  a  value  of  D. 

For  instance,  a  2°  metric  curve  having  7  =  40°  would  have  a 

Q/i  £\  f* 

mid-ordinate  equal  to  „-— ~  =  34.56  meters. 
£  X  5 

For  the  approximate  radius  of  a  metric  curve  divide  5780  by  5 

57SO 
times  the  degree.     Thus  a  4°  metric  curve  would  have  R=  •£• 


LOCATION.  43 

—  286.5  meters.     For  the  exact,  radius  m.ike  use  of  formula  (12). 
Thus  for  a  4°  curve  having  20-meter  chords  R  =  — — 53  =  286.54 

meters,  a  difference  of  only  .04  meters. 

If  a  metric  curve  is  to  be  retraced  with  a  100-ft.  chain,  we 
convert  the  metric  degree  to  the  degree  referred  to  100-ft.  chords 
by  the  relation  that  a  100-ft.  chain  =  1.524  chains  of  20  meters 
each;  a  20-meter  chain  =  65.618  ft.;  one  foot  =  0.3048  meters; 
one  meter  =  3.2809  ft. 

It  will  sometimes  be  a  sufficiently  close  approximation  to  take 
the  20  meter  chain  as  two  thirds  of  a  100-ft.  chain;  this  will  make 
the  metric  curve  nearly  two  thirds  of  the  degree  the  same  curve 
would  have  when  laid  out  with  a  100-ft.  chain,  and  the  curve  with 
100-ft.  chords  nearly  three  halves  of  the  degree  as  laid  out  with 
the  20-meter  chain.  Thus  a  4°  metric  curve  would  be  equivalent 
to  a  6°  curve  laid  out  with  a  100-ft.  chain. 

In  the  problems  that  follow  two  methods  of  solution  will  be 
given  when  practicable — the  first  being  rigid,  while  the  second 
is  based  on  the  use  of  Table  IX.  To  shorten  the  formulas  the 
subscript  1  will  be  written  after  the  letters  T,  L.  0.,  M,  and  E 
when  these  are  the  functions  of  a  1°  curve.  Thus  Ti  ^  28°  means 
the  tangent  distance  for  a  1°  curve  when  7=28°,  L.C.i  ^  16° 
the  long  chord  for  a  1°  curve  when  /=  16°,  etc. 

78.  Tables  of  Natural  and  Logarithmic  Circular  Functions.  — 
Many  engineers  prefer  to  work  altogether  by  tables  of  natural 
sines,  cosines,  etc.,  and  time  may  often  be  saved  by  their  use. 
Nevertheless  logarithmic  tables  are  of  frequent  advantage,  even  in 
the  field,  and  the  more  important  ones,  such  as  the  logarithmic 
sines,  cosines,  tangents,  and  cotangents,  together  with  the  loga- 
rithms of  numbers,  are  given  in  the  back  of  the  book  along  with 
the  tables  of  natural  functions. 

79.  Given  7?  and  C  to  Find  Z>. 

From  equation  (12), 

sin  \D  =  i? (13) 

80.  Given  7  and  R  (or  D)  to  Find  T. 

If  I)  is  given,  find  R  by  (12');  then  in  Fig.  15  from  triangle 
OAB  we  get 

T  =  K  tan  11. (14) 


44        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

BY  TABLE  IX.     Find  the  tabular  value  of  T  for  the  given 
angle  /;  then 

(Ha) 


EXAMPLE.—  7=  35°  40',  D  =  4°;  required  T. 
By  (14),     T—  1432.69  tau  17°  50'  -  460.91  feet. 


By  (14a),  T=     ~       =  460.85  feet,  a  result  differing  from  the 
value  found  by  the  rigid  method  by  only  0.06  foot. 

81.  Given  /  and  Tto  Find  ft  or  D 

From  (14), 


tan 


=  TcotU.     .....    (15) 


Then  by  Table  I  the  degree  may  be  found. 
BY  TABLE  IX. 


(15a) 


82.   Given  J  and  D  to  Find  the  Long  Chord  L.  C. 
First  find  R  by  (12)  or  (12'),  or  by  Table  I  ;  then  from  the 
triangle  OA  F  of  Fig.  15, 


(16) 


LOCATION. 


45 


BY  TABLE  IX. — Find  the  tabular  L.  (7.  for  the  given  angle  /; 
then 


L.C.= 


D 


83.  Given  the  Radius  R  and  any  Chord  C  to  Find  the 
Ordinate  to  the  Curve  at  any  Point. 

FIRST  METHOD.— In  Fig.  16  let  HE  be  the  chord  C\  UK—  a 
and  KE  —  b,  the  segments  into  which  it  is  divided  by  the  ordi- 


nate  y.     Draw  the  radius  through  K;  call  the  portion  between 
chord  and  curve  y'.     By  geometry, 


from  which 


ab 


But  y'  is  small  compared  with  2J?,  and  hence  we  write 


Now  y  does  not  differ  sensibly  from  y'  in  the  cases  met  with  in 
practice,  so  we  write 

ab 

y   rv  ij \"  / 


46        A    FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 


If  we  write  R  =         ,  formula  (6)  becomes 

abD 


2  X  5730'    ' 

a  b 

— —  =  m,  T— r  =:  n,  and  substitute  in  (c),  giving 
100  10U 


y  = 

or  very  nearly 


y^lmnD (17) 


y  is  given  in  feet  when  m  and  n  are  in  chains  and  decimals  of 
a  chain. 
At  the  rnid-point  F,  m  —  n,  and  y  =  M . 


(18) 


CAUTION. — Formulas  (17)  and  (18),  while  very  convenient  for 
field  use  in  passing  obstructions,  are  liable  to  error  when  very 
long  chords  or  large  values  of  D  are  used,  since  they  give  results 
that  are  too  small. 

If  we  write  the  arcs  HN,  NE  for  a  and  b,  we  shall  get  results 
that  are  too  large,  yet  about  as  near  the  true  values  as  by  taking 
m  and  n  to  be  the  segments  of  the  chord.  To  illustrate  we  will 
find  a  few  values  of  M  and  compare  with  the  true  values  taken 
from  Table  V. 


Degree 
of 
Curve. 

2       .. 

Length 
of 
Arc. 

2  stations. 

Mid-ord. 
1.75 

Mid-ord. 
by 
M=l(HQ)*D. 

1.75 

Mid-ord. 
by 
Table  V. 

1.75 

2  

6 

15.69 

15.75 

15.09 

5 

2       " 

4.37 

4.38 

4.36 

5  

6       " 

38.51 

39.38 

39.06 

8  
8   

2       " 
4       " 

6.96 
27.29 

7.00 
28.00 

6.97 

27.75 

8 

5       " 

42.02 

43.75 

43.20 

8... 

6       " 

59.43 

63.00 

61.93 

From  this  it  appears  we  may  use  formula  (18)— and  (17)  as 
well — taking  either  the  segments  of  the  arc  or  chord  for  curves 
not  exceeding  4°  with  arcs  up  to  600  ft. ;  for  curves  from  4°  to  6° 


LOCATION.  47 

they  may  be  used  up  to  500-ft.  ares,  \vkile  for  curves  between 
6°  and  8°  not  more  than  400  feet  of  arc  may  be  taken. 

SECOND    METHOD.— First    determine    the    uiid-ordiuate.      In 
triangle  OEF, 


OF= 

then 

$G*.    .....     (19) 


To  find  ordinate  AC  distant  d  from  the  mid-point  of  EH,  draw 
OB  =  d  parallel  to  HE;  draw  AB  at  right  angles  to  HE.     Then 


BA  =  \/IP  -  d*. 
Therefore 


CA  =  y=  VJt2  -  d*  -  VR*  -  iC*.    .     .     .     (20) 

THIRD  METHOD.—  If  the  chord  C  is  short,  we  may  regard  the 
arc  as  an  arc  of  a  parabola,  for  which  it  is  known  that  ordi- 
uates  vary  as  the  product  of  the  segments  into  which  they  divide 
the  chord.  The  mid-ordinate  being  known,  we  have 

y          ab 

Ti  = 


From  formula  (b)  we  have  for  y  —  M,  a  =  b  =  \G, 
M_W_C* 

-~zR-m'   ' 

The  mid-ordinate  for  any  other  chord  C'  is 

M-C" 
M'~SR' 

Hence 

&_&*_ 

M~  C'2' 

.-.  ift.«4f(£-7  .........     (23) 

w  / 

If  C"  =  -|(7,  this  gives 

Ml=\M.    .........     (23') 


48        A    FIELD-MANUAL    FOR   RAILROAD    ENGINEERS. 

This  last  relation  affords  an  easy  method  of  staking  out  a  curve 
when  the  mid-ordiuate  of  a  given  chord  has  been  determined. 
First  erect  the  ordinate  M  at  the  mid-point  of  the  chord;  then 
join  the  ends  of  chord  with  the  extremity  of  the  ordinate  just 
measured;  the  lengths  of  these  chords  do  not  differ  much  from 
^C;  at  their  mid-points  erect  ordinates  equal  to  \M,  giving  points 
on  the  curve.  Proceed  in  like  manner  for  other  points  until  a 
sufficient  number  have  been  located. 

84.  Given  R  and  /  to  Find  the  External  E. 


In  Fig.  17  E  =  OB  =  OB  -  OG. 
But  OB-R  sec  £/  and  OG  =  R. 


.-.  E  —  .ft(sec  \1  -  1)  = 

BY  TABLE  IX.—  Find  E  for  a  1° 
angle  /;  then 


ex  sec  \L    .    .    .      (24) 
curve  for  an  intersection 


(24a) 


85.  Given  T  and  /  to  Find  E. 

In  Fig.  17  draw  EG  perpendicular  to  AB,  and  produce  AO  to 

B/ 


FIG.  17. 

intersect  EG  at  C.  BCis  parallel  to  AO,  and  the  triangles  AGO 
and  GBC&TG  similar;  hence  BC=BG  =  E.  In  the  right  triangle 
ABC,  angle  BAG—  \BAF  =  $1.  Therefore 

(25) 


E  =  T  tan  \L   .    . 
EXERCISE.— Derive  equation  (25)  from  (24). 


LOCATION". 


49 


86.  Given  M  and  /  to  Find  E. 

From  trigonometry, 

sec  \I  = 
Insert  this  in  (24)  and  we  get 

'  —  cos 


cos 


n 
=  It 


cos  fl 

But  from  Fig.  17,  M  =  R(\  -  cos 

E_     M  • 
~  cos  \I 

87.  Given  E  and  /to  Find  R. 

From  (24), 

E  E 


Substitute  in  (a)  : 


(a) 


11  =  - 


cos 


sec    /  —  1 


ex  sec 


vers 


88.  Given  /  and  E  to  Find  2. 
From  (25), 

r=  ^r 
tan    / 


(26) 


(27) 


(28 


89.  Given  the  Chord  G  and  Degree  of  Curve  D  to  Find 
the  Chord  Deflection  Offset  d. 
In  Fig.  18  extend  EA  to  H,  making  AH  —  EA  =  AB ;  join 


'0 
FIG.  18. 

JET  and  B  and  draw  ^^T  to  the  mid-point  of  HB.     Then 
HK=  EB= 
.-.  d  =  HB  = 


(29) 


50        A   .FIELD-MANUAL    FOR    KAILUOAD    ENGJNEEKS. 

When  C=  100', 

d  =  200  sin  W  ..........      (29') 

1  Q 

If  we  write  sin  \I>  =  ^  from  (12)  in  formula  (29),  there  results 

d  =  ^  .............       (30) 

For  curves  up  to  7°,  G  —  100';  hence 

10000 
<*=  -g--    -    •  _  .........     (30') 

For  curves  from  7°  to  14°,  G  —  50';  therefore 

(30") 
For  #  write       -,  and  (30'),  for  G  =  100,  becomes 


and  for  G  —  50,  (30")  becomes 

ocjnn  T) 

d  =  ^lYD  =  .4363Z>  =  .873.  5-.     .     .     .      (31') 
57oO  £ 

EXAMPLE.—  Fiud  c^  for  a  6°  curve,  G  —  100  feet. 
By  (29'),          d  =  200  X  0.05234  =  10.47  feet. 


By  (30'),          d  =  =  10.47  feet. 

yOO.  4: 

By  (31),  d  =  1.745  X  6  =  10.47  feet. 

90.  Given  the  Chord  G  and  Degree  of  Curve  D  to  Find  the 
Tangential  Deflection  Offset  t. 

In  Fig.  18  make  EF  (tangent  at  E)  equal  to  EA,  and  join  F 
with  A.  Draw  EG  to  the  mid-point  of  FA.  Angle  AEG  = 
GEF  =  \D\  hence,,  from  the  figure, 


(32) 


LOCATION.  51 

When  G  =  100  feet, 

t  =  200  sin  I D (32') 

Since   \D  is  small,  we   may   write,    without   material   error, 
sin  \D  =  i  sin  \D\  then,  writing  sin  \D  —  -^,  as  in  89,  we  get 

t  =  ^ (33) 

Making  G  —  100  ft.  and  writing  R  =  —~  gives 

(33') 


When  C  =  50  feet,  (33)  yields 

t  =  .218Z>  =  .436  X  ~ (33") 

/w 

EXAMPLE.— Find  t  for  a  6°  curve,  C  =  100  ft. 
By  (32')  t  =  200  sin  1°  30'  =  5.24  ft. 

By  (33'),  =  .873  X  6  =  5.24  ft. 

91.  To  Find  the  Subtangential  Deflection  Offset  t'  for  a 
Subchord  C' 

FIRST  METHOD. — By  formula  (13)  find  the  angle  at  the  center 
subtended  by  the  subchord  C';  call  this  angle  I)'.  From  (32), 

t'  =  2C'  sin  \D' (34) 

SECOND  METHOD.— In  Fig.  19,  with  Ens,  center  strike  the  arcs 
FG  and  AH,  taking  EF  =  C'  and  A 

EA  =  C ;  prolong  EG  to  B.    Now 

assuming  that  the  chords  C'  and  C  %          \t 

are  proportional  to   their  central 
angles   we  have 

AB  _t_ 
G'    ~  C '  ' 

From  the  similar   sectors  EFG  FIG.  19. 

and  EAB,  since  EB  =  C, 

C        C' 


52        A    FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 
Multiplying  (a)  and  (b)  together,  term  by  term, 
Gt       C' 


Whence 


(35) 


EXAMPLE.— Find  t'  for  a  7°  curve  when  C  =  60  ft. 


fiO 
.-7- 

i(JO 


Here  IX  =  .-7-  x  7°  (very  nearly)  =  4°  12'. 


By  (34),          t'  =  2  X  60  X  0.01832  =  2.20  ft. 
By  (32)'          t  =  6.11  ft. 

By  (35), 


t'  =  6.11  X  =  2.20  ft. 

uy 


92.  To  Find  the  Tangent  Offset  z. 

In  Fig.  20,  EB  =  zis  the  required  offset.  Let  AE=  n  chains  = 
lOOrc  feet.  AE=FB,  the  half-chord 
having  the  mid-ordhmte  AF  =  .##; 
hence  we  have,  by  formula  (18), 

z  =  ItfD.     .     .     .     (36) 

In  this  formula  we  may  take  n  to 
be  either  the  length  of  AE  or  the  arc 
AB,  in  chains.  If  taken  equal  to  AE 
the  offsets  will  be  slightly  too  small, 
while  if  taken  equal  to  AB  they  will 
be  a  little  too  large.  The  use  of  the 
formula  is  limited  to  small  values  of 
n  and  D,  as  was  pointed  out  in  83. 
(See  CAUTION.) 
Formula  (36)  is  easy  of  application  and  of  frequent  use  in 

locating  curves  by  offsets  from  the  tangents.     For  curves  up  to 

4°   n  may  be  as  great   as  3,  but  for  sharper  curves  it  should 

be  less. 
EXAMPLE.  —  Find  six  offsets  to  a  4°  curve  at  points  50  ft.  apart, 

measured  around  the  curve. 


FIG.  20. 


LOCATION.  53 

By  successive  applications  of  (36)  we  have 

for  n  =  i  z  =  I  X   -1  X  4  =    0.88  feet 

»  =  1,  «  =  |  X    1X4=    3.50     " 

n  =  f,  2  =  I  X    f  X  4  =    7.88     " 

n  =  2,  s  =  |x4x4  =  14.00     " 

n  =  |,  2  =  |  X  -¥-  X  4  =  21.88    " 

n  =  3,  2  =  £X9X4  =  31.50    " 

The  last  value  of  z  is  in  error  by  about  0.2  ft.,  but  for  setting 
stakes  on  construction  this  difference  is  not  material  so  long  as 
the  alignment  beyond  this  point  does  not  depend  on  it.  In 
setting  track-centers  the  completed  road-bed  is  available  and  the 
stakes  may  be  set  with  the  transit,  in  the  usual  way. 

93.  Difference  in  Length  of  a  Circular  Arc  and  its   Long 
Chord. 
FIRST  METHOD. — Let  the  central  angle  be  a  degrees.     By  (13), 

siu  K  =  A 

Changing  degrees  to  circular  measure,  a  (in  n  meas.)  =  — 

-  JL      The  length  of  arc  is  Ra  =  #^-.     Then 
57. o  o7.o 


Arc  -  chord  =  R-—  -c (37) 

o7.o 

SECOND  METHOD. — An  easy  approximation  may  be  found  as 
follows : 

Referring  to  Fig.  17,  AE  =  c,  GF=  M.     Let  A  O  =  b  ^  £-  -f  x. 

a 

From  the  right  triangle  AFO 


TIT2 

From  which  x  —  (a) 

c  -f  x 


54        A    KrEUKMANUAL   FOR   RAILROAD    ENGINEERS. 

Neglecting  the  x  in  denominator  as  small  compared  with  c 
gives 


2  If  2 

Then  will  2b  -  c  -  2x  =  -—  ......     (38) 

c 

From  Huygcns'  approximation  to  the  length  of  a  circular  arc 

(see  Williamson's  Differential   Calculus,  p.  66),  arc  =  —  -f  -  . 

o 

Therefore 

Arc  -  chord  =  ^5-7  -  c  -  |-(2&  -  c).      .     .       (c) 
o 

Inserting  the  value  of  25  —  c  from  (88)  gives 

Arc  —  chord  =  -^—  ..........      (d) 

oC 

When  the  arc  is  not  very  great  we  may  write  c  =  lOOfti  ,  where 
TO  j  is  the  number  of  chains  contained  in  the  arc  AE.  From  (18), 
remembering  that  HI  =  2n, 

M  =  0.218n,9l>. 
Inserting  these  values  of  c  and  M  in  (d), 


Arc  _  cllor<1  =  I  <»i^  =  _Lm,^,  nca,.ly.  .    (39) 

EXAMPLE.  —  Find  the  difference  in  length  of  arc  and  chord  of 
a  4°  curve  when  HI  —  6  stations. 

The  central  angle  is  4x6  =  24n;  then,  from  Table  IV, 
c  =  595.74. 

By  (37), 

24 
Arc  -  chord  =  1432.7  X  ==-    -  595.74  =  4.34  ft. 

O  i  .o 


By  (39), 
An 

REMARK.— Formula  (38)  is  interesting  as  showing  what  a  com- 


.  6X6X6X4X4 

Arc  -  chord  =  -  =  4.32  ft 

ovU 


LOCATION. 


55 


paratively  small  increase  in  length  of  line  is  caused  by  a  consid- 
erable lateral  deflection  in  alignment.  For  instance,  a  lateral 
deflection  of  2000  feet  is  made  at  the  mid-point  of  a  line  40,000 
feet  long  ;  what  will  be  the  increase  in  length? 


By   (38)  the   increase   is 
increased  length  40,200  feet. 


40,000 


=  200  feet,   giving  for  the 


B.  Locating  Simple  Curves. 

94.  To  Locate   a  Curve  with  the  Chain  by  Offsets   from 
Chords  Produced. 
In  Fig.  21  let  the  P.  C.  fall  at  B.     If  BC  is  a  full  chain,  prolong 


the  tangent  AB  to  //,  making  BII=  BC;  HG  will  equal  t,  which 
may  be  calculated  by  (32')  or  (33').  With  B  as  center,  strike  an 
are  with  radius  BIT,  and  with  II  as  center  and  t  as  radius  strike 
an  arc  ;  at  G,  where  these  arcs  intersect,  set  a  stake.  Produce 
BC  to  K,  making  CK  -  BC  =  CD  ;  strike  the  arc  KD  from  C  as 
center ;  make  the  chord  KD  —  d,  calculated  from  (29'),  (30'),  or 
(31).  Set  a  stake  at  D  and  proceed  in  like  manner  for  the  other 
points  until  the  P.T.  is  reached,  where  FPis  made  equal  to  t. 

Usually  the  P.O.  does  not  fall  at  a  full  station  ;  then  EC  =  t', 
which  may  be  found  by  (34)  or  (35).  Using  this  value  of  t',  we 
locate  C  as  above.  At  B  make  B R  •=  t',  and  prolong  RC  to 
L  ;  make  LD  =  t  and  set  a  stake  at  D.  EM  will  equal  d,  and 
may  be  located  as  before. 

We  may  regard  KD  as  equal  to  KL  -f-  t,  and,  finding,  KL, 


56        A   FIFLD-MANUAL   FOR  RAILROAD   ENGINEERS. 

measure  KD  and  set  D  without  locating  H.     To  do  this  we  have 
the  similar  triangles  BEG  and  CKL,  from  which 

KL  _    t' 
~CK~lBG' 

and  therefore,  since  KG  —  CD, 

—I- 

In  like  manner  at  Five  have 

TfTf 

PN=t^,    and    FP=V 
hence 


Make  EQ  =  </,  prolong  QF,  and  we  have  the  tangent  at  F. 
EXAMPLE.  —  Given  the  P.  (7.  of  a  5°  curve  at  106  +  20  and  the 
angle  of  intersection  22°,  to  locate  the  curve. 

oo 

Here  L  =  —  =  4.4  stations. 

o 

Therefore  the  number  of  the  P.  T.  is 

106.20  +  4.4  =  sta.  110  +  60. 
BG  in  this  case  is  80  ft.,  and  by  (33') 

t  =  0.873  X  5  =  4.37  ft. 


By  (35),         t'  =  4.37  X  =  2.80  ft. 

Set  off  HG  =  2.80  ft.,  and  at  D  make 

100 
KD  =  2.80  X  ~  r  +  4.37  =  7.87  ft. 

oU 

At  E  make  ME  =  d  =  8.72  by  (31).  This  will  be  at  sta.  109  ; 
at  110  set  a  stake  by  offsetting  8.72  ft.  The  last  chord  is  60  long, 
and  hence  the  offset 


NF=  4.37  X         +  4.37  X    —=  2.62  +  1.57  =  4.19  ft. 
Make  EQ  =  1.57  ft.,  and  prolong  QF,  the  terminal  tangent. 


LOCATION. 


57 


95.  To  Locate  a  D  Degree  Curve  by  Offsets  from  Tangent. 

Let  AM,  Fig.  22,  be  tangent  at  A,  and  E,  F,  O,  etc.,  points  on 
the  curve.     The  offsets  BE,   CF,    A  B 

etc.,  may  be  found  from  formula 
(36), 

z  =  lri*D, 

either  by  taking  equal  intervals, 
AB,  BO,  CM  along  the  tangent  or 
by  taking  E,  F,  G,  etc.,  at  regular 
stations  around  the  curve  and 
using  the  arc  length  instead  of 
the  tangent. 

When  the  arc  AG  is  large,  or 
strict  accuracy  is  required,  we 
proceed  to  find  the  offsets  at 
regular  stations  and  the  lengths 
of  AB,  AG,  etc.  First  find  R 
from  (12)  or  (12');  then  from  triangle  OEL, 


FIG.  22. 


BE  —  AL  —  R(l  —  cos  D]  =  R  vers  D, 
AB  =  LE  =  R  sin  D. 
In  like  manner 

CF  =  AH  =  R(l  -  cos  2D)  =  R  vers  2D, 
AC  =  IIF  =  R  sin  2D, 

and  so  on  for  any  number  of  stations. 

Should  .4  fall  at  a  plus  station,  we  first  find  the  angle  A  at  the 
center,  then 

BE  =  R  vers  D,  , 

AB  =  R  sin  £>, , 

CF  =  R  vers  (Z>,  -f  D), 

AC=  R  sin  (Z>i  -f  D\ 

etc.  =  etc. 

The  ordinates  BE,  CF,  etc.,  are  evidently  equal  to  the  mid- 
ordinates  for  long  chords  2LE,  2IIF,  etc.;  hence  we  can,  if 
A,  E,  F,  and  G,  fall  at  full  stations,  take  them  direct  from 
Table  V;  then  take  the  long  chords  from  Table  IV  and  dividing 
these  by  2,  get  the  required  coordinates. 


58      A  FIELD-MANUAL  FOR  RAILROAD  ENGINEERS. 

EXAMPLE. — Locale  three  stations  of  a  4°  curve  by  offsets  every 
50  ft.  on  curve. 

Referring  to  Table  V,  the  required  offsets  arc  0.87,  3.49,  7.85, 
13.94,  21.77,  and  31.31.  By  Table  IV  the  distances  measured 
along  tangent  are  50.0,  99.94,  149.76,  199.39,  248.78,  and  297.87. 
With  these  values  we  can  set  out  the  curve  either  way  from  A. 

Had  we  used  formula  (36)  we  should  have  had  for  the  values 
of  the  offsets  0.87,  3.50,  7.88,  14.00,  21.87,  and  31.50. 

96.  To  Locate  a  Curve  by  Offsets  from  a  given  Long 
Chord. 


Let  FK,  Fig.  23,  be  the  given  chord.     We  may  compute  the 
offsets  yi ,  y^ . .  .  M  by  the  methods  of  83— of  which  formula  (17), 

y  —  \rnnJ), 

is  the  most  convenient,   within  the  limits  of  its  applicability — 
and  setting  off  these  ordinates,  locate  the  curve. 

Or  we  may  set  off  the  rnid-ordinate  M  =  R  Trers  FOA  at  A, 
and  at  C  set  off  #2  —  M  —  JR  vers  D,  making 

AC  =  IIL  =  R  sin  D. 
GE  will  be 

y,  —  N  —  R  vers  2D,     and    AE  =  R  sin  27). 

ANOTHER  METHOD  is  1o  find  ilic  .-ingle  T\OFn.\,  the  center,  and 
by   Table  IX  determine  BA  —  M  ;  then  by  Tables  V   and  IV 


LOCATION".  50 

determine  BL,  BN,  LH,  and  NO.     Then  HO  =  M  -  BL,  which 
set  off  at  G,  and  other  points  in  like  manner. 

EXAMPLE.  —  Given  the  P.O.  of  a  4°  curve  at  station  160  -j-  75, 
the  angle  between  tangent  and  chord  =  9°,  required  the  offsets 
necessary  to  locate  the  curve. 

Here  7=2x9  =  18°. 

1  8 

.-.     L  —  —  =  4.50  stations. 
4 

Hence  the  P.T.  falls  at  160.75  -f  4.50  —  sta.  165  -j-  25.  The 
mid-point  on  curve  B  falls  at  sta.  163.  By  Table  IX, 

J,=  ™=  17.64  ft. 


By  Table  V  the  mid-ordinate  for  two  stations  of  a  4°  curve  is 

BL  =  3.49. 

Hence  I1C  =  17.64  -  3.49  =  14.15. 

By  Table  IV,          HL  =  AC  =  99.94  ft. 

Measure  AC  =  99.94  ft.,  and  set  off  CR  —  14.15  ft.,  and  drive  a 
stake  at  II.  In  like  manner  find 

<3#=3.70    and     .4  tf=  199.39  ft. 

The  points  P  and  Q  are  also  located  by  means  of  the  coordi- 
nates just  determined. 

If  B  had  fallen  at  an  odd  station,  the  curve  could  have  been 
located  in  the  same  manner,  Hand  P  being  100ft.  from  B,  G  and 
q  200,  etc. 

97.  To  Locate  a  Curve  with  Transit  and  Chain  when  the 
Degree  D  or  Radius  72  is  Known. 

If  R  is  given,  determine  D  by  (13);  then,  since  .he  angle  in 
the  circumference  of  a  circle  is  half  the  angle  at  the  center  sub- 
tended by  the  same  chord,  we  may  locate  points  on  the  curve  by 
successive  deflections  from  the  tangent. 

In  Fig.  24  let  the  P.O.  be  at  A,  at  which  point  set  the  transit, 
and  with  the  vernier-plates  clamped  at  zero  place  the  telescope 
in  tangent  either  by  sighting  the  P.I.  or  by  backsightiug  to  some 
point  in  the  tangent  Deflect  from  the  tangent  half  the  angle  at 
the  center  for  the  sub-chord  or  chord,  and  direct  the  head  chain- 
man  into  line  while  the  rear  chainman  holds  his  end  of  the  chain 


GO        A   FIELD-MANUAL   FOR   RAILROAD   ENGINEERS. 

at  the  transit,  the  chain  being  kept  taut.  The  stakemaii  drives  a 
stake  at  the  point  where  the  head  chainman's  flag  rested,  and  the 
rear  chainman  advances  to  this  point.  Deflect  %D  from  the  chord 
AB  just  run,  and  while  the  rear  chaiuman  holds  his  end  of  the 
chain  at  B  direct  the  head  chainman  into  line  at  C.  Other  points 
are  located  by  deflecting  an  additional  \D  for  each  chord  length 
measured,  until  a  point  E  is  reached  to  which  it  is  desirable  to 


Fio.  24. 

move  the  transit.  The  angle  FAE  should  not  exceed  about  15°. 
Move  the  transit  to  E,  backsight  to  A,  and  deflect  FEA  =  EAF, 
when  the  telescope  will  be  in  tangent,  and  the  curve  can  be  con- 
tinued until  it  is  again  necessary  to  move  the  transit.  At  the 
P.  T.  put  the  telescope  in  tangent  by  backsighting  to  the  point 
last  occupied  by  transit  and  deflecting  the  tangential  angle  as  at 
E.  The  line  may  now  be  continued. 

98.  The  Index-angle  is  read  on  the  vernier-plate,  and  is  the 
angle  between  the  tangent  to  the  curve  at  the  P.  C.  and  any  other 
line  passing  through  a  point  on  the  curve  when  the  telescope  is 
directed  along  this  line.     It  is  most  frequently  taken  as  the  angle 
between  the  initial   and   any  subsequent  tangent  to  the  curve. 
Thus  at  E  the  index-angle  equals  EFP  =  2FAE.     At  any  point 
on  the  curve  the  index-reading  in  tangent  may  be  found  by  the 
following  rule,  which  may  be  easily  deduced  from  a  figure: 

From  double  the  index-angle  that  fixed  the  point  subtract  the  index- 
angle  in  tangent  at  the  last  point;  the  remainder  is  the  index-angle 
required, 

99.  Subdeflection-angles   may  be  found   by  (13)   rigidly,  or 
approximately  (and  with  sufficient  accuracy  except  when  D  is  very 
large)  by  assuming  the  central  angles  to  be  proportional  to  their 
chords.     Thus  on  a  4°  curve  the  central  angle  for  a  sub  chord  of 
25  ft.  would  be  1°,  and  the  subdollertion -angle  30'. 


LOCATION.  61 

EXAMPLE.— Locate  a  4°  curve  to  left  when  the  P.O.  is  at  sta. 
81  -I-  25  and  /=  32°  36'. 

Here  L  -  ^  =  8.15  chains. 

Hence  the  P.  T.  will  fall  at  81.25  +  8.15  =  sta.  89  -f-  40.  The 
first  sub-chord  is  75  ft.  long,  and  the  first  deflection-angle  will  be 
found  by  (12). 

nfj    K 

SiD^  =  1-432.7  =  °-02617 

.'.     £<^=-l°    30'. 

By  the  approximate  rule,  since  |D  =  2°, 

id  _  75 
~2    ~I66' 

whence  |S  =  2  X  I  =  1°  30'  as  before. 

With  transit  at  P.O.  deflect  1°  30'  from  tangent,  measure  75 
feet,  and  set  sta.  82.  Then  a  deflection  of  3°  30'  will  determine 
83,  5°  30'  sta.  84,  7°  30'  sta.  85.  Now  remove  transit  to  85,  and 
with  vernier  at  7°  30'  backsight  to  81  +  25.  Reverse  telescope 
and  set  vernier  at  15°  00',  when  the  telescope  will  be  in  tangent. 
An  index  angle  of  17°  will  fix  86,  and  so  on. 

The  last  chord  will  be  oiity  40  feet  long,  for  which  the  sub- 
deflection-angle  is  T4(fy  of  2°,  that  is,  48'.  The  index-angle  fixing 
the  P.T.  is  therefore  23°  48'. 

To  get  in  tangent  at  89  -f  40  backsight  to  sta.  85,  with  vernier 
at  23°  48' ;  then  by  the  rule  of  98  the  index-reading  is  (23°  48')  X 
2  —  15°  =  32°  36'  =  /.  Set  the  vernier  at  this  reading  and  run 
tangent. 

CAUTION.  — It  is  not  good  practice  to  set  more  than  4  or  5  sta- 
tions on  curve  from  any  one  point.  MR.  SHUNK  gives  the  limit- 
ing angle  to  be  deflected  from  tangent  as  20°,  and  says  15°  should 
rarely  be  exceeded.  (Field  Engineer,  p.  82.) 

100.  The  Transit  Notes  may  be  conveniently  kept  in  the  form 
below,  which  shows  the  notes  for  the  last  example. 

When  possible  the  tangents  should  be  run  to  intersection,  the 
angle  1  measured,  and  the  tangent  distance  calculated.  Then 


62        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS 


a 
•2® 

,  be 

c  « 
'2  S 

Is 

*t 

Station. 

%Jp 
|« 

11 

£be 

11 

11 

O 

II 

Remarks. 

90 

-HO 

QP.T. 

0°48' 

23°  48' 

32°  36' 

N27°36'E 

N  27°30'  E 

89 

23°  0' 

88 

21°   0' 

87 

19°  0' 

86 

17°  0' 

85 

O 

7°  30' 

15°  0' 

84 

5°  30' 

83 

2°    0' 

3°  30' 

82 

1°30' 

1°30' 

4°  C.L.;  P.L  set. 

+25 

0P.C.4°C.L. 

0°   0' 

0°  0' 

0°  0' 

/  =  32°  36';     T  - 

418.9  ft. 

81 

N  60°12'  E 

N  60°10'  E 

measure  along  tangents  and  set  P. C.  and  P.T.  from  the  P.L 
When  the  curve  is  run  iu;  the  position  of  the  P.T.  thus  found 
should  agree  with  the  one  set  from  the  P.I.  If  the  error  is 
greater  than  the  circumstances  of  the  case  permit,  the  curve 
must  be  rerun  and  tangents  remeasured. 

101.  Another  Form  of  Notes,  and  in  some  respects  a  better  one 
than  the  above,  is  given  below.  The  index-readings  are  com- 
puted as  though  the  entire  curve  were  run  from  the  P.  C.  The 
notes  for  the  last  example  would  appear  as  below  : 


§<u 

*l? 

—  o5 

•d 

-  w' 

fj 

Station. 

o"5b 

^^ 

~  S 

|| 

o  o 

11 

Remarks. 

r 

H4  y 

5° 

IS 

90 

4-40 

QP.T. 

0°48' 

16°  18' 

32°  36' 

N  27°36'  E 

N  27°30'  E 

89 

15°  30' 

88 

13°  30' 

87 

11°30' 

86 

9°  30' 

85 

O 

7°  30' 

84 

5°3C' 

83 

2°   0' 

3°  30' 

82 

1°30' 

1°30' 

4°  curve  left  ; 

4-25 

0P.CU°C.L. 

0°    0' 

0°  0' 

P.I.  set.  7=32°16'; 
2'  =418.9  ft. 

81 

N60°12'E 

N60°10'N 

The  computations  are  all  made  before  beginning  the  work,  and 
the  notes  have  the  advantage  of  permitting  the  tracing  of  the 
curve  either  way  from  the  instrument  without  additional  compu- 


LOCATION.  63 

tations.  Suppose  the  trausitman  to  have  rim  the  curve  from  the 
P.  C.  to  sta.  85,  to  which  point  he  removes  the  instrument.  He 
there  sets  the  vernier  at  0° — the  angle  on  limb  when  telescope 
was  iu  tangent  at  the  P.  C. — then  sighting  the  P.  C.  he  reverses 
the  telescope  and  deflects  to  9°  30',  which  will  fix  sta.  86.  Had 
the  tangent  at  85  been  desired,  a  reading  of  7°  30' — the  angle  that 
located  that  point — would  have  put  the  telescope  in  the  plane  de- 
sired. A  reading  of  11°  30'  fixes  87,  and  so  on  to  the  P.  T. 
Removing  to  the  P.T.,  the  plates  are  clamped  at  7°  30',  and  a 
backsight  to  sta.  85  taken ;  then  deflecting  to  16°  18',  the  tele- 
scope is  in  tangent  at  the  P.T.  Had  it  been  desirable  to  set  84 
from  85,  a  reading  of  5°  30'  would  fix  that  point ;  others  may 
be  found  in  the  same  manner. 

Any  convenient  form  of  notes,  which  are  intelligible  to  another 
engineer  who  may  have  to  retrace  the  curve,  may  be  used,  but  it 
is  desirable  that  some  general  form  should  be  employed.  Either 
of  the  preceding  forms  seems  to  meet  ordinary  requirements. 

C.  Obstacles. 

102.  To  Pass  an  Obstacle  on  a  Curve. 

FIRST.  Suppose  the  obstacle  to  be  one  obstructing  vision  at  one 
station  only. 

In  Fig.  25  suppose  transit  set  at  A,  and  B  and  C  located  from 
that  point,  but  the  next  full  station,  II,  to  be  invisible  from  A. 


FIG.  25. 


Set  a  plus  station  at  E,  as  near  the  obstruction  as  may  be  conven- 
ient, then  set  F 100  feet  from  E.  Next  make  FG  =  100  -  GE, 
and  locate  O  with  the  corresponding  deflection-angle.  Other 
stakes  may  be  set  beyond  G,  or  the  transit  may  be  removed  to 
that  point  and  the  curve  beyond  traced. 

SECOND.     Suppose  the  line  of  siylit  obscured  for  more  than  one 
station,  as  in  Ft'y,  20. 


64        A    FIELD-MANUAL    FOR   RAILROAD    ENGINEERS. 


If  transit  is  at  A,  deflect  an  angle  HAB  that  will  clear  all  ob 
structious,  aud  at  the  same  time  cause  B  to  fall  at  a  full  station. 
Then  by  Table  IV,  Table  IX,  or  by  formula  (16)  calculate  the 
long  chord  A13  ;  measure  AB  and  move  transit  to  B  ;  then  dellect 


FIG.  26, 

the  angle  ABC=  BAH  when  the  telescope  will  be  in  tangent. 
The  curve  may  now  be  run  both  ways  from  B. 

If  it  happen  that  some  stations,  as  E  and  F  in  the  figure,  are 
still  invisible,  they  may  be  located  by  offsets  from  chord  or  tan- 
gent. 

EXAMPLE. — Let  the  curve  be  a  3°  curve  to  right  -,  angle  NAB 
=  7°  30',  the  deflection-angle  for  5  stations.  By  Table  IV  the 
long  chord  is  498.63  feet,  which  can  now  be  measured  and  a  hub 
set  at  B ;  then  making  angle  CBA  =  7°  30',  the  telescope  will  be 
in  tangent  and  the  curve  can  be  traced  either  way. 

103.  To  Locate  a  Curve  when  the  P.O.  is  Inaccessible. 

In  Fig.  27  let  the  P.  C.  at  B  be  in- 
accessible ;  it,  is  desired  to  reach  a 
point  II  on  accessible  ground. 

FIRST  METHOD.  —  Assume  a 
point// on  the  curve  such  that  a 
line  AH  from  an  accessible  point 
A,  on  tangent,  will  clear  the  ob- 
stacle ;  for  convenience  H  should 
be  at  a  full  station.  The  arc  BI1 
and  central  angle,  which  equals 
HCF,  are  then  known.  Calculate 
BC  =  T  by  (14)  or  (Ua)  ;  then 
since  AB  is  known,  AC,  =  AB -f- 
BC,  is  known. 

Now  in  triangle  A  CH,  from  trig- 
onometry, 

tan  \(h  -  a)  _  A  G-CH 
tan  l(7i  +  a) 


FIG.  27. 


LOCATION.  65 

But  (h  -f-  a)  =  c  •  hence 

A  r1     rtj 

tau«A-a)  =  -^TWtan^  .....  (40> 

Then  \(h  -J-  a)  -f-  |(7i  —  a)  =  h,  the  larger  angle,  and 
|(A  -}-«)  —  |(7i  —  «)  =  a,  the  smaller  angle.  AH  may  be 
found  by  the  law  of  sines,  or  by  drawing  CE  perpendicular 
to  AH,  when 

AH  =  AC  cos  a  +  CHcosh  .....     (41) 

EXAMPLE.—  The  P.  C.  of  a  4°  curve  is  at  sta.  141  -f  25,  and  it 
is  desired  to  reach  the  point  J2"from  sla.  139  on  tangent. 

Suppose  H  be  assumed  to  fall  at  sta.  147  ;  the  curve  length  is 
L  =  147  —  141.25  =  5.75  chains.  Then  angle  c  =  5.75  X  4  = 
23°  0'.  By  Table  IX  the  tangent  distance  for  a  1°  curve  is 
Ti  4  23°  =  1165.8  ft. 


By  (14«),  T  =  =  291.45  ft. 

Now  AC  =  291.45  -f-  225  =  516.45  ft., 

and 

AC+  CH=  516.45  +  291.45  =  807.90, 
while 

AC  -  CH  =  225  ft.  ; 
hence,  by  (40), 

2^)F) 

tan  l(h  -  a)  =  —  —  „-  X  0.20345  =  0.05666  =  tan  3°  15'. 
807.9 

Therefore 

7i  =  11°  30'  +  3°  15'  =  14°  45', 
and 

a  =  11°  30'  -  3°  15'  =    8°  15'. 
By  (41), 

AH=  516.45  x  0.98965  +  291.45  X  0.96705  =  793.0  ft. 

At  A  deflect  8°  15'  from  tangent,  measure  793.0  ft.  and  set  a 
hub  ;  move  to  this  point,  backsight  to  A  and  deflect  14°  45'  into 
tangent,  then  trace  in  the  curve. 


G6        A    FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 

SECOND  METHOD. — If  F,  any  assumed  point  in  tangent,  is 
visible  from  A,  AF  may  be  measured  by  some  indirect  method; 
then  AF —  AB  =  T.  The  tangent  for  a  1°  curve  having  same 
intersection-angle,  KFG,  is  7\  =  Tx  If;  find  this  value  of  Ti  in 
Table  IX  and  take  out  the  corresponding  value  of  L  "With 
transit  at  F  deflect  the  angle  KFG,  measure  FG  =  FB  =  T,  and 
set  hub  at  G.  The  station  number  of  G  is  found  by  dividing  the 
central  angle,  =  KFG,  by  the  degree  of  curve  D.  Move  to  G  and 
trace  the  curve. 

EXAMPLE.— Let  AF  measure  490.5  ft.  from  sta.  139  of  the  last 
example.  Then  AB  =  225  ft.,  and  BF=  490.5  -  225  -.=  265.5  ft. 
265.5  X  4  =  1062  ft.,  which  by  Table  IX  is  the  value  of  2\  for 
/=  21°.  Set  transit  at  F,  deflect  21°,  and  measure  FG  =  265.5  ft. 


21 
L  =  —=5.25  chains; 


hence  G  will  fall  at  141.25  -f  5.25  =  sta.  146  +  50.  Move  to  G 
and  run  the  curve  both  ways. 

THIRD  METHOD. — In  Fig.  28  let  the  inaccessible  P.  C.  be  at  B, 
and  let  it  be  required  to  reach  E  from  a  point  G  on  the  curve 
prolonged  backwards  from  B. 

At  a  given  point  A  on  tangent  cal- 
culate the  tangent  offset  by  (36)  or 
the  methods  of  95,  then  set  this  off  at 
right  angles  to  AB  ;  set  the  transit  at 
C  and  turn  off  ACL  =  90°  -  COB, 
when  the  telescope  will  be  in  tangent 
at  C.  COB  may  be  found  from  Table 
IX  by  multiplying  AC  by  the  degree 
of  curve  and  taking  half  the  intersec- 
tion-angle corresponding  to  the  mid- 

ordiuate  that  equals  this  product.  Now  deflect  and  measure 
ECL,  then  by  (16)  or  (16«)  calculate  GE,  which  measure.  Move 
to  E  and  deflect  LEG  =  ECL  and  the  telescope  will  be  in 
tangent.  The  central  angle  BOE  =  2LEC  -  BOG,  from  which 
the  arc  BE  &ud  number  of  sta.  E  may  be  found. 

EXAMPLE. — Take  the  same  example  as  in  the  last  two  cases. 
A  is  at  sta.  139,  B  at  141  -f  25;  hence  AB  =  2.25  stations. 


By  (36),        z  =  AC=  •  X  (3.35)»  X  4  =  17.72  ft. 


LOCATION. 


67 


Or  by  Table  IX  the  angle  corresponding  to  the  long  chord 
(2  X  2.25)  X  4  —  1800  ft.  is  18°  4',  for  which  the  mid-ordinate  is 

71.06  ft.     For  our  4°  curve  the  mid-ordiuate  will  be  — '-—  •=.  17.77 

4 

ft.,  which  equals  AC  and  agrees  closely  enough  with  the  value 
for  z  above. 

Make  angle  BAG  =  9Q\  and  measure  AC  =  17.72  ft.  Move 
to  C  and  sight  to  A,  then  make  angle  ACL  =  90°  —  (9°  2')  = 
80°  58'.  Suppose  an  angle  LCE  =  16°  1'  to  clear  the  obstacle. 
By  formula  (16), 

CE  =  2R  sin  (16°  1')  =  2  X  1432.7  X  0.27592  =  790.6  ft. 

Measure  along  CE  790.6  ft.  and  set  a  hub;  move  to  E  and  run 
the  curve. 

CE  might  have  been  found  by  means  of  Table  IX,  for  the  long 
chord  of  a  1°  curve  having  1  =  2LCE  =  32°  2'  is  3162.0  ft.; 
divide  this  by  4  and  there  results  CE  =  790.5  ft. 

104.  To  Pass  to  Tangent  when  the  P.T.  is  Inaccessible. 

This  is  just  the  reverse  of  the  preceding  problem,  and  may  be 
accomplished  by  reversing  the  processes  described  above. 

When  the  P.T.,  however,  falls  in  or  beyond  a  river  or  lake 
obstructing  the  ordinary  methods  of  indirect  measurement,  the 
ease  merits  a  special  solution. 

FIRST  METHOD.— In  Fig.  29  let  the  transit  be  at  A,  and  B  the 
P.T.      From    the    known   station 
numbers  of  A  and  B  the  length  of 
curve  and  angle  /  may  be  found; 
then,  by  (14),  AC  =  11  tan  |/,  or,  V  \  ,r 


by(14a),  AC=. 

Move  to  C  and  deflect  the  angle 
/;  set  a  stake  F,  and  one  at  some 
other  accessible  point  E\  measure 
angle  ECF  '=  c.  Move  to  F  and 
measure  the  angle  EFC  and  the 
side  EF;  then  in  triangle  ECF 
angle  e  =  180°  —  (c  -(-/);  by  trigo- 
nometry 


FIG.  29. 


. 
sm  c 


(42) 


68        A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 


Since  BC  =  AC,  there  results  BF  =  CF  —  AC;  and  as  the  sta- 
tion number  ut  B  is  known,  that  at  F  becomes  known,  and  the  liue 
may  be  continued. 

If  B  is  not  the  P.T.,  measure  back  the  distance  FB,  set  transit 
at  B,  and  continue  the  curve. 

EXAMPLE.—  Let  the  P.T.  of  a  2°  C.L.  fall  at  sta.  205  -f  50—  an 
inaccessible  point;  suppose  A  at  sta.  200,  angle  c  =  40°,  /=  80°, 
JSF=310ft. 


Here 


',     and      e  =  60°. 


T  = 


=_  375.37  ft. 


From  (42),  applying  logarithms, 


log  CF=  2.49136  -f  9.93753  -  9.80807  =  2.6082. 


Whence  CF=  417.7  ft.     Then  BF—  417.7  -  275.87  -  141.8  ft.; 

therefore  the  number  of  F  \vi\l  be  206  +  91.8. 

SECOND  METHOD.  —  In  Fig.  30,  with  the  transit  at  any  point  A 
on  the  curve,  assume  a  long  chord  AB 
and  calculate  the  angle  CAB;  deflect 
this  angle  from  the  tangent  AC,  and  set 
a  point  E  beyond  obstruction  ;  set  also 
a  stake  at  C  in  tangent. 

Move  to  E  and  measure  A  EC  and 
side  EC.  Compute  AE  from  the  trian- 
gle AEG.  If  this  is  greater  or  less 
than  the  length  of  the  long  chord  AB, 
take  their  difference  BE  and  set  a  hub 
at  B.  With  the  transit  at  B  trace  out 
the  curve. 

EXAMPLE.  —  Given  A  at  sta.  210  of  a 
3°  C.  L.,  angle  a  =  12°,  b  =  92°,  EC 
=  181  ft.  Then  c  =  76°,  and  by  solving 

the  triangle  AEG,  AE-  844.7  ft.    By  Table  IX  the  long  chord  of 

OOQO  ft 

a  1°  curve  for  /=  24°  is  2382.6  ft.  ;  therefore  AB  =         ' 


FIG.  30. 


o 

ft.     Now  will  .##  =  844.7  —  794.2  =  60.5  ft,,  which  is 
tance  along  EA  that  transit  must  be  moved  back  from  E. 


=  794.2 
the  dis- 


LOCATION. 


69 


105.  Given  the  Perpendicular  p  from  a  Point  to  a  Tangent, 
to  Find  the  Point  on  Tangent  at  which  to  Begin  a  Curve  of 
Given  Radius  which  will  Pass  through  the  Given  Point. 

FIRST  SOLUTION. — In  Fig.  31  let  P  be  the  point,  BP  the  per- 
pendicular.     We    have    to    find          , 
BA  =  x.  A[< 

From  P  draw  PC  parallel  to 
AB ;  then  in  triangle  OPG 

K*  =  a?  +  CR  -  p)*. 
From  which 


x  =  \/2Rp  -  p\     .     (43) 

SECOND  SOLUTION. — Consider 
p  —  AC  as  the  mid-ordiuate  for 
a  long  chord  =  2x  ;  then  p  X  D 
=  the  mid-ordinate  for  a  1°  curve 
for  a  central  angle  equal  2a. 
The  corresponding  long  chord  may  be  taken  from  Table  IX. 
Then 


FIG.  31. 


IL.C. 


(43«) 


EXAMPLE.— Given  p  =  30  ft.,  D  =  4°  (E  =  1432.7),  to  find  x. 


By  (43),         x  =  V85.962  -  900  =  291.65  feet. 
By  the  second  method, 

30  X  4  =  120, 

the  mid-ordinate  for  a  1°  curve  corresponding  to  an  angle  of 
23°  29',  for  which  the  long  chord  is  2332.6.     Now,  by  (43a), 


=  291.6  feet. 


106.  In  Fig.   31,  Given  x  and  p  to  Find  the  Radius   of  a 
Curve  Tangent  to  AB  at  A  and  Passing  through  P. 


From  (43), 


2P 


(44) 


70        A   FIELD-MANUAL   FOR   RAILROAD   ENGINEERS. 

107.  Given  the  Location  of  a  Point  P  referred  to  the  P.  1. 
to  Find  the  Radius  of  a  Curve  through  P  which  will  Unite 
the  Given  Tangents. 


B 


FIG.  32. 


In  Fig.  32  suppose  BC  —  I,  BP  =  m  known,  and  angle  a  cal- 
culated ;  or  PC  and  a  may  be  measured  on  the  field. 
From  triangle  CAO, 


b  =  90°  -  (a  + 
Now  from  triangle  PCO, 


and     CO  =  R  sec 


CO    . 

sm  y  =  po  sm 


Inserting  values  of  PO  and  CO, 

R  sec  \I 

y  —  -          .  sin  b  =  sec  \l  .  sin  5  = 


sin 


sin  b 

-  —  , 


an  equation  from  which  the  unknown  11  has  disappeared. 
from  the  same  triangle,  since  x  =  180°  —  (b  -f-  y}, 


sm 


When  I  =  90°,  it  can  easily  be  shown  that 


•     (45) 

Next, 

.     (46) 
(47) 


LOCATION.  71 

108.  To   Locate   a  Tangent   to    a    Curve   from   an  Outside 
Point. 
FIRST  METHOD.— In  Fig.  33  let  P  be  the  point  and  AHB  the 


.,    R/ 


/o 

Fia.  33. 

curve.  Run  a  trial-line  PA  cutting  the  curve  in  A  and  B. 
Measure  PA  and  AB ;  or  measure  PA  and  angle  a  between  the 
chord  AB  and  tangent  AL.  Then 

AB  —  2AC  =  2R  sin  a, 
00  =  R  cos  a. 

By  geometry,  PE  =  VPA  X  PB,  PE  being  the  required  tan- 
gent.    From  the  figure, 

CO 


tan  m  = 


_ 
PE' 


At  P  deflect  the  angle  I  =  m—  n  from  PA  and  run  the  tangent. 
SECOND  METHOD. — In  Table  IX  find  the  long  chord  for  a 
central  angle  2a  ;  then 


AB  =  2A  C  = 


L.O. 


~D> 

and  CO  =  R  —  CH. 

"We  may  now  proceed  as  before. 


72        A    FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 

109.  To  Run  a  Tangent  to  Two  Located  Curves  of  Contrary 
Flexure. 

FIRST  CASE.— In  Fig.  34  let  FK  and  LE  be  the  curves,  and 
KL  —  p  measured  on  the  ground. 


FIG.  34. 


Let  F1S—  t  be  the  required  tangent. 

Draw  OiH  parallel  and  0*H  perpendicular  ioFE;  from  the 
triangle  OJIO*  ,  since  FH  =  R,  , 


(JB, 


whence 


t= 


.    .     .     .     (48) 


Also, 


cos  a  — 


(49) 


The  arcs  FK  and  LE  may  be  found  from  the  angle  a  and  the 
known  curvatures,  after  which  the  points  .F  and  .E'may  be  set. 

If  t  is  given  and  p  required,  it  may  easily  be  found  from  (48). 

SECOND  CASE,    p  not  known. 

Set  the  transit  at  a  point  A  on  one  curve. and  note  the  bearing 
of  tbe  tangent  to  the  curve  at  that  point  (see  Fig.  34);  the  bearing 
of  the  radius  0?A  differs  from  this  by  90°.  Run  a  line  ABC  of 
one  or  more  courses  to  intersect  the  oilier  curve  at  C.  Note  the 
bearings  and  lengths  of  these  courses  and  the  bearing  in  tangent 
at  C,  from  which  calculate  the  bearing  of  CO^  Rl  and  7?2  being 
known,  the  latitudes  and  departures  are  next  calculated.  Let  02A 


LOCATION. 


73 


be  the  sum  of  the  northings  or  southings,  01^  the  sum  of  the 
eastings  or  westings  ;  from  the  triangle  0i  022V, 

tan  b  =  -=^-T, 


and 


As  before,  FE  is  the  required  tangent  and  02£T  perpendicular, 
while  OiH is  parallel  thereto. 


coa  a  — 


0,0, 


Angle  F0itf  =  b  -  a  is  the  bearing  of  0*F,  while  AO*F  = 
c  —  b -\-  a  is  the  angle  of  retreat  from  the  known  point  A  to  F, 
where  the  tangent  may  be  run.  The  length  of  t  = 

t  =  00,  sin  a. 


D.   Change  of  Location. 

110.  To  Locate  a  Curve  Parallel  to  a  Given  Curve. 

Let  p  be  the  perpendicular  between  parallel  tangents,  and  sup- 
pose ABC  located  (see  Fig.  35). 
If  there  are  no  restrictions  as  to  the 
position  of  the  points  E,  F,  and  Q 
on  the  second  curve,  we  may  cal- 
culate the  new  degree  of  curve  Di 
for  a  radius  Ri  =  R  -f  p,  by  (13), 
and  trace  the  curve  from  any 
point,  as  E.  Thus 


50 


50 


If,  however,  points  on  the  radii 
through  A,  B,  and  G  are  wanted, 

they  are  gotten  by  using  the  same  degree  of  curve  D  and  com- 
puting the  length  of  chord  FE.     From  similar  triangles, 


EF 


AB 
R 


100 


74        A    FIELD-MANUAL    FOR   RAILROAD    ENGINEERS. 
whence 


EF  =  100  ?!  =  100  ?4r^  =  100  (l  -f  |  ).  .         (50) 
ri  H  >          .a* 


Had  .SFY?  been  the  located  curve,  with  radius  R,  we  should 
have  had 


(51) 


111.  To  Change  the  P.O.  of  a  Located  Curve  so  that  P.T. 
will  Fall  in  a  Given  Tangent  Parallel  to  Terminal  Tangent  of 

Located  Curve. 

Let  AB,  Fig.  36,  be  the  lo- 
cated curve  ;  FE,  the  tangent 
in  which  the  P.I.  must  fall. 

Let  the  distance  between  tan- 
gents be  HE  =  p. 

Draw  BE  and  00'  parallel  to 
AF ;  evidently  AC  =  00' =BE, 
O'  being  the  new  position  of 
center. 


In  triangle  BEH, 


BE  =  AC  =  ~-j.  =  p  cosec  /. 


(52) 


Set  the  new  P.  C.  by  measurement  from  A,  and  run  the  curve 
CE.  Any  system  of  straight  lines  and  curves  may  be  treated  as 
above,  provided  1  is  the  angle  between  initial  and  terminal 
tangents  and  p  as  before. 

EXAMPLE. — A  located  2°  30'  curve,  having  /  =  25°,  ends  in  a 
tangent  25  ft.  outside  of  desired  tangent.  Find  the  change  in 
position  of  P.  C. 


By  (52), 


AC  =  25  X  2.36620  =  59.16  ft. 


LOCATION. 


75 


C     K 


112.  To  Find  the  Change  in  Radius  and  Position  of  P. G.  if 
P.T.  is  Required  to  fall  on  the  same  Radial  Line  but  on  a 
Tangent  distant  p  from,  and  parallel  to,  Terminal  Tangent  to 
Located  Curve. 

In  Fig.  37  let  AB  be  the  located  and  CE  the  required  curve. 
Draw  the  parallel  chords  AB  and 
GE.  Draw  CHaud  BF perpendicular    _A_ 
to  AB.  The  angles  FBE=  CAH—\If 

From  the  figure, 

CH—  AC  sin  |7, 
BF  —  BE  cos  |7  =  p  cos  |7. 
Equating,  p 

A  G  sin  \I  =  p  cos  ^7,  Q 

whence 


FIG.  37. 


(53) 


In  the  triangle  OPOt,  0,P  =  AC,  OP  -  R  -  7?,,  and 

(R  —  R,)  tan  /  =  AC  =  p  cot  \I, 
or  R  -  R,  =  AC  cot  /  =  p  cot  \I  '.  cot  /. 

Therefore 

7?,  =  R  —  AC  cot  I  =  R  —  p  cot  4/.  cot  7.  . 

From  trigonometry, 

* 


(54) 


coti/= 


1  —  cos  1 
Inserting  these  values  in  (54)  gives 


and    cot  7= 


—  H  —  p 


sin  7        cos  7 


cos  7 


cos  7 


.  -  --  -  .  —  - 
1  -  cos  7    sin  7 


From  trigonometry, 


ex  sec  7  = 


T  —   72  ll =. 

1  —  cos  7  *  vers  7 


vers  7 
cos  7* 


?!  =72- 


ex  sec  7' 


(54') 


EXAMPLE. — A  2°  30'  curve  strikes  25  ft.  inside  a  tangent  in 
which  the  P.  T.  must  fall.  Find  the  necessary  change  in  radius 
and  position  of  P.C.  when  /  =  25°. 

By  (53)  the  change  in  P.  C.  is 


By  (54'), 


AC  =  25  X  4.51071  =  112.77  ft. 
25 


,  =  2292.01  - 


=  2050.38  ft. 


.10338 
By  Table  I  we  find  this  to  be  the  radius  of  a  2°  47'  41"  curve. 

113.  Given    a  Located    Curve  uniting    Two   Tangents  to 
Find  the  Change  in  Position  of  P.  C.  or  in  Radius  for  a  Given 
Change  in  the  Intersection-angle. 
FIRST  CASE. — Radius  unchanged. 

In  Fig.  38  let  BCE  =  /be  the  origi- 
nal intersection-angle,  FCE  =  I'  the 
new  angle.     From  the  figure, 
AG  =  AC-  GC, 

AG  -  R  (tan  \I  ~  tan  \1'\    (55) 

BY  TABLE  IX.— From  the  table,  for 
angle  /, 


Then 

SECOND  CASE. — P.O.  unchanged. 

Here  the  tangent  T  for  the   two  curves  is  the  same,  and 
therefore 

Ri  tan^/'  =  .Rtan^/; 

(56) 


Whence 


i  =  Jltanf/.cotfr. 


LOCATION. 

BY  TABLE  IX, 

y,  41*     Ti4r° 
D  D, 


114.  To  Find  the  Change  in  R  and  P.  C.  for  a  Given  Change 
in  /,  the  P.T.  remaining  unchanged 


'O, 
FIG.  39. 
In  Fig.  39,  from  the  triangles  OBG  and  OiBH, 

OG  =  R  cos  / 
and  01H=RlcosI1. 

Now  GA  —  HF;  hence 

Ri  —  Ri  cos  /i  =  R  —  R  cos  /. 
Whence 

...         (57) 


vers  li 

Also,  FA  =  HG  =  BH  -  BG. 

Inserting  values  of  BH  and  BG,  there  results 

FA  =  R,  sin  I,  -  R  sin  /. (58) 

115.  Given  a  Located  Curve  to  Find  the  Change  in  R  for 
a  Given  Change  in  T,  I  remaining  unchanged. 

In  Fig.  40,  from  the  triaugles  OAC  and  0,EC}  since 
EA  =  EC  -  AC, 


78        A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 


R!  tan  ±1  -  R  tan  |J  =  EA  =  T'  -  T. 
Whence  R,  =  R-\  -  (T1  -  -  T)  cot  {1 (59) 

_ .  E         A  c 


FIG.  40. 
BY  TABLE  IX.—  EA  being  known,  T7'  =  T+  EA-.    Then,  by 


If  the  change  in  vertex  of  curve  is  wanted,  there  results,  from 
(25), 

E  =  CO  =  T  tan  i/,       E'  =  GH  =  T'  tan  J/. 
Therefore         OH  =  E'  -  E  =  (T'  -  T)  tan  */,..,     (60) 

GHc&n  be  found  from  Table  IX  after  finding  Dl  as  above. 
If  Ri  is  given  and  EA  wanted,  (59)  yields 

EA  =  T'  -  T  =  (R1  -  R)  tan  %I. 

116.  To  Find  the  Radius  of  a  Curve  having  the  Same  P.G. 
as  a  Given  Curve,  but  ending  in 
a  Parallel  Tangent. 

In  Fig.  41  let  the  perpendicular 
distance  between  tangents  be  p,  and 
AB  be  the  located  curve;  A0t  =  R! 
is  required. 

FIRST  METHOD.  —  Draw  OH  at 
right  angles  to  OiE;  then 

OiE  =  dll  +  NO  +  OE, 
or 

Ri  =  (Ri  -  R)  cos  I  -  j-  7?  +  p. 


FIG.  41. 
From  which    Ri 


=  .R  + 


P         _ 
1  —  cos  / 


p 


vers  / ' 


(61) 


LOCATION.  79 

SECOND  METHOD.—  A,  B,  and  E  lie  on  the  same  straight  line, 
since  /  is  the  same  for  both  curves.  In  triangle  BOE  angle 
EBG  =  7,  and 


From  Table  IX,      AB  = 


AE  =  AB  +  BE  is  the  long  chord  for  curve  of  degree 
therefore 


If  desired,  JR  may  be  found  by  (12')  or  Table  I. 
THIRD  METHOD. — Draw  FL  parallel  to  0\E\  then 


CF  =  — — -  =  p  cosec  /. 
sm  /      L 


From  Table  IX,       AC  =  ~fj—. 

AF=  AC-}-  CF,  the  tangent  distance  for  second  curve  ;  hence 


D,  = 


AF 


REMARK. — If  transit  is  set  up  at  B,  it  will  be  well  to  set  E 
by  measurement  from  B,  to  serve  as  a  check  when  the  curve  is 
run  in  from  A. 


80        A   FIELD-MANUAL    FOR    RAILROAD    ENGINEERS. 


ARTICLE  9.     COMPOUND  CURVES, 
A.  Location  Prob ferns. 

117.  Given  Two  Unequal  Tangents,  their  Intersection-angle, 
and  One  Radius,  to  Find  the  Other  Radius  of  a  Compound 
Curve  uniting  Tangents. 

In  Fig.  42,  AH  =  T!  and  BE  =  T2  are  the  known  tangents, 
AOi  =  Ei  the  known  radius.  BOi  =  R2  and  the  angles  /i  and  J2 
must  be  found  before  curve  can  be  located. 


Extend  first  branch  to  F,  so  that  tangent  FL  is  parallel  to  BIT. 

Draw  HK  and  BG  perpendicular  to  FL  ;  draw  FB  and  extend 
to  E\  it  will  pass  through  the  P.C.C.,  because  the  central  angles 
EO,F  and  EO*B  are  equal.  Then 

To  =  AL  =  Hi  tan  ^7. 
In  triangle  LHK,  since  LH  =  T0  —  T!  , 


p  =  HK=  BG  =  (T0-  T7,)  sin  Z 
Now  in  triangle  BGF  angle  BFG  =  i/a,  and 


LOCATION.  81 

tanifi  =  f  ......     ...     (62) 

Draw  0a  17  parallel  to  FL  •  then 

CRi  -  J?2)  sin  72  =  J, 
whence 

7?2  _  7?!  -  i—  =  =  &-1  cosec  72.      .     .     (63) 
sin  /2 

Had  2?j  been  required,  the  equation  would  have  been 

J?!  =  #2  -\-l  cosec  72. 
Evidently,  I,  =  I  —  72. 

In  the  field  the  points  77  and  .#  may  be  located  by  running  in 
the  curve  from  A  as  starting-point,  or  run  the  chord 

AF=2Rl  sin  |7 

from  A,  arid  at  T7  deflect  angle1  AFB  —  \I  —  i/2  =  |/i  ,  measure 
FB  —  I  sec  |72  and  BE  —  2,ff2  sin  i/2. 

EXAMPLE.—  A  2°  curve  has  the  P.O.  at  sta.  110,  Ti  =  590  ft., 
T2  =  511.8  ft.,  I  =  30°  50'.     Locate  the  curve. 

By  Table  IX,  T0  =  1580/2  =  790  ft. 

By  formulas  above, 

s  =  200  X  0.85866  =  171.73  ft., 
p  =  200  X  0.51254  =  102.51  ft., 
I  =  790  +  171.73  -  511.8  = 


1QO   51 

tan  7'  =          =  °"  23778  =  tan  25°  40/' 


Then  7,  =  30°  50'  -  25°  40'  =  5°  10'. 

440  97 
7i>2  =  2864.93  -  ~      -'  =  1833  feet. 


82        A    FIELD-MANUAL    FOR    RAIL  HO  AD    ENGINEERS. 

By  Table  1  this  is  seen  to  be  the  radius  of  a  3°  7-J'  curve. 

The  length  of  first  branch  is  258.3  feet,  and  of  the  second  821.3 
feet;  hence  the  P.C.C.  falls  at  112  +  58.3,  while  the  P.T.  is  at 
sta.  120  +  79.6. 

118.  Given  the  Long  Chord  from  P.O.  to  P.T.  of  a  Com- 
pound Curve,  the  Angles  it  makes  with  the  Tangents  and 
One  Radius,  to  Find  the  Other  Radius  and  the  Central  Angles. 

In  Fig.  42  AB  is  known,  as  also  the  angles  HAB  =  a  and 
HBA  =  b.  Two  angles  and  one  side  of  the  triangle  HAB  are 
known,  and  the  sides  HA  =  Ti  and  HB  —  T*  may  be  found, 
after  which  the  solution  is  the  same  as  in  the  last  problem. 

A  solution  may  be  reached  in  a  different  manner.  I  =  a  +  b, 
RAF  =  \I  =  \(a  +  b),  and  BAF  =  $(a  +  b)  -  a  =  \(b  -  a), 
AF  =  2#!  sin  i/.  In  triangle  BAF  two  sides  and  the  included 
angle  are  now  known,  so  AF  and  angle  BFA  may  be  found; 
GFB  =  i/2  =  K  -  BFA> 

Then  EF  =  2Z?j  sin  £/„  , 

and  EB  =  EF  —  BF  becomes  known. 

Then  EB  =  2#2  sin  £/3  =  %&  sin  £/2  -  BF, 

7?  T/* 

Whence  fi,  =  A  _  __     .......    (64) 


Evidently  Ji  =  /  —  J 


119.  Given  the  Radii  and  Central  Angles  of  a  Compound 
Curve  to  Find  the  Tangent  Lengths,  the  Long  Chord  from 
P.C.  to  P.T.,  and  the  Angles  it  makes  with  Tangents. 

In  Fig.  43  draw  AE  and  BE  from  the 
P.C.  and    P.T.    to    the    P.C.C.  ,   then 
calculate  AE  and  BE  by  (16)  or  by 
Table   IX.      In    triangle    AEB   angle 
,          _         AEB  =  180  -  £(/,  +  /„).      Two  sides 
^          ^s      and  the   included   angle  being  known, 
the  triangle  AEB  may  be  solved  for 
AB  and   the  angles  ABE  and  BAE\ 
then 


BAF  = 

FIG.  43.  ABF  —  ABE  +  ^72. 

The  angle  AFB  of  triangle  ABF  now  becomes  known  and,  as 


LOCATION.  83 

AB  is  known,  the  sides  AF  =  2\  and  BF  =  T*  may  be  com- 
puted. 

120.  Given  the  Long  Chord  from  P.C.  to  P.  T.  of  a  Com- 
pound Curve  and  the  Angles  it  makes  with  Tangents  to 
Find  the  Radii  when  the  Common  Tangent  is  Parallel  to  Long 
Chord. 

In  Fig.  43  let  GHl>G  parallel  to  AB,  and  GAB  =  a,  HE  A  =  b 
known.  Then 

BAE  =  EAG  =  GEA  =  \a, 
and  ABE  =  EBH  =  IIEB  =  \b. 

Also,  AEB  =  180°  -  |(a  +  b). 

In  triangle  AEB,  remembering  that 
sin  [180  —  •!(« 


AE= 


. 

sin  i(a  -f-  6) 

and 

^4  #  sin  ^a 


~DTJ1 

JJJL  — 


sin     a 


Since  J.0i  J£  =  a  and  EO*B  =  b,  the  radii  JKi   and  7?2  may  be 
found  from  formula  (16),  or  (16«). 


7?      - 

~  sin  ^6  ~  2  sin  $6  .  sin  £(a  +  6)' 

EXAMPLE.  —  Required  7?i  and  -K2  ,  or  DI  and  J)a  ,  when  AB  = 
900  feet,  a  =  12°,  6  =  15°. 

By  (65),  .K,  =  2407.0  ft. 

By  (66),  R*  =  1543.7  ft. 

From  Table  I,     Z>,  =  2°  22'  50"    and    D9  =  3°  42'  44". 


84        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

B.   Obstacles. 

121.  To  Locate  a  Point  on  uie  Second  Branch  of  a  Com- 
pound Curve  when  the  P.C.G.  is  Inaccessible. 

Ordinarily  the  second  branch  is  located  by  setting  transit  at  the 
P.  G.  C.  and  running  the  curve  from  that  point.  An  obstacle  on 
either  curve  may  then  be  passed  by  the  methods  given  for  simple 
curves. 

When  the  P.C.C.  is  inaccessible, 

,Ap  locate  the  first  branch  from  iheP.C. 

and  the  second  branch  from  the 
P.  T.,  if  this  latter  point  is  known. 
When  this  is  not  the  case  proceed 
by  one  of  the  following  methods: 
FIRST.  By  means  of  a  long 
chord. 

In  Fig.  44  let  E  be  the  P. C. C., 
A  some  known  point  on  first 
branch,  EF  a  tangent  at  E,  and 
AB  parallel  to  FE.  The  station 
numbers  of  A  and  E  being 
known,  the  arc  AE  and  angle  a 


are  readily  found  ;  then 

EL  =  .Ra  vers  b  = 

whence 

vers  a 


vers  a, 


vers  b  = 


(67) 


next, 


AB  —  .#,  sin  ol-f  #2  sin  b  ......    (68) 

Deflect  FAB  -  a  from  tangent  at  A  ;  measure  out  AB  ;  set  the 
transit  at  B  and  locate  the  second  branch. 
BY  TA*BLE  IX.—  Take  the  mid-ordinate  in  table  for  an  inter- 

section-angle 2a  ;  then 


Then  EL  X  D*  is  the  mid-ordinate  for  a  1°  curve  having 
I  —  2b,  from  which  b  becomes  known.  From  the  table  now  find 
AL  and  LB,  the  half-chords  for  angles  2a  and  2b,  and  proceed  as 
before. 

SECOND  METHOD.—  By  means  of  tangents. 
From  Fig.  44,         AF  —  FE  =  Jti  tan  \a. 


LOCATION. 


85 


Set  transit  at  F,  deflect  GFE  =  a,  and  by  some  indirect  method 
measure  to  an  accessible  point  H. 

EH=  FH-  FE, 
and 


tan 


=  ——,  from  formula  (14). 


Angle  b  is  now  known  and  equals  GHE,  which  deflect  from 
EH;  then  measure  HB  =  EH,  and  with  transit  at  B  locate  the 
second  branch  of  curve. 

OR  BY  TABLE  IX.  —  Find  AF  =  FE,  the  tangent  distance  for 
I  —  a;-  then  having  EH  measured,  take  Ti  =  EH  X  Di  and  find 
the  corresponding  angle,  which  equals  b  ;  then  proceed  to  locate 
curve  as  above. 

EXAMPLE.—  Let  A  be  at  sta.  126,  P.  C.  C.  at  128  -f  25;  the  degree 
of  first  branch  4°,  and  of  second  6°. 

By  the  first  method  EL  =  17.635  for  a  =  9°,  and  b  =  11°  2', 
nearly.  AL  =  224.1  ft.,  BL  —  182.75  ft.,  and  therefore  AB  = 
406.85  ft.  Angle  b  =  11°  2'  corresponds  to  183.9  ft.  around  6° 
curve;  hence  the  P.T.  number  is  130  -+-  08.9. 

By  the  second  method  AF  =  112.74  ft.  Suppose  FH  =  264  ft., 
then  EH=  151.26  ft.,  which  multiplied  by  6  gives  907.56  ft., 
corresponding  to  /  =  18°.  The  arc  EB  is  now  300  ft.,  making 
B  fall  at  sta.  131  +  25. 


C.     Change  of  Location. 

122.  Having  a  Simple  Curve  Located  to  Find  the  P.  C.  C.  so 
that  a  Curve  of  Given  Radius  shall  connect  with  a  Given 
Tangent    Parallel     to    Tangent     to 
Located  Curve. 

Let  NAB,  Fig.  45,  be  the  located 
curve,  HF  the  tangent  in  which  the 
second  branch  must  end.  The  dis- 
tance BG  =  p  between  tangents  is 
known  from  measurement.  If  angle 
a  can  be  found,  the  arc  BA  becomes 
known  and  the  point  A  can  be  located 
from  B.  Draw  0*L  from  the  center 
of  second  branch  perpendicular  to 
0|jB>  Iu  trjang]e  Q^L,  0,0,= 
-f  p)  ;  therefore 


Rl  - 


-  R1  - 


86        A    FIELD-MANUAL   FOR   HAILROAD    ENGINEERS. 


cos  a  = 


R\  — 


Then  a  divided  by  Di  gives  arc  1L4. 

If  desired,  BH  may  be  found  from  the  right  triangle  BHO,  in 
which  the  side  BG  =  p  and  angle  OHB  =  ^a  are  known— - 
A,  H,  and  B  lying  in  the  same  straight  line  ;  then 


BH  =    .    ,     =  p  cosec  la. 
sin  Aa 


(70) 


Or  BA  and  #J.  may  be  found  from  Table  IX,  after  which 
BH=BA-  HA. 

EXAMPLE. — A  3°  curve  ends  in  a  tangent  at  sta.  160  -f-  50, 
35  ft.  outside  of  desired  tangent.  Find  the  point  of  compound- 
ing with  a  4°  50'  curve. 

From  Table  I,  R  for  3°  curve  equals  1910.08  ft.,  and  for 
4°  50'  curve  1185.78  ft. 


Then,  by  (69),   cos  a  =  1  - 


35 

7243 


=  0.95168. 


From  table  of  cosines  angle  a  is  found  to  be  17°  53'.  Dividing 
this  by  3  gives  5.961  stations  for  the  arc  BA.  Hence  the  P.C.C. 
number  is  160.50  -  5.961  =  sta.  1 54  -f  53.9,  and  the  new  P.T.  is 
at  sta.  158  +  23.9. 

123.    Given    a    Located    Compound    Curve    ending    in  a 
Tangent  Parallel  to,  and  a  Given  Distance  from,  a  Tangent 
in  which  the  Curve  is  required  to  end.     To  Find  the  Neces- 
sary Change  in  P.  C.  C. 
FIRST  CASE. — Terminal  branch  having  shorter  radius. 

In  Fig.  46  let  ABC  be  the  located 
curve,  AEF  the  one  required  ;  angle 
BOiC  =  a  known,  and  also  MN  =  p. 

If  angle  EOM =  b  can  be  found,  the 
angle  of  retreat  from  B  to  E  will  equal 
b  -  a. 

Draw  O/7f  and  OiL  perpendicular 
to  ON,  which  is  parallel  to  0,C. 


N 


FIG.  46. 


Then     OK  =  (R  —  R,}  cos  b, 
OL  —  (R  —  lit)  cos  a. 


LOCATION. 

Now  LM  =  Rt  -  KL  -  R,  -  MN,  from  which  KL  =  MN  =  p. 
Hence 

(E  —  Ri)  cos  b  =  (R  —  Ri)  cos  a  —  p. 
From  which 

cos  b  =  cos  a  —  —  -  —  ......     (71) 

It  —  H\ 

Divide  b  —  a  by  D,  the  curvature  of  first  branch,  and  move 
back  that  number  of  stations  from  B  to  the  new  P.  C.C.  at  E. 

Join  0,0,';  evidently  FC  =  O.O/,  and  angle  JiO.'O,  =  CFG  ; 
00,'  0,  =  90°  -  $(b  -  a),  00,'  K  =  90°  -  b.  Hence 

CFG  =  #0/0!  =  [90  -  i(b  -  a)]  -  (90  -  6)  =  i(b  +  a).     (72) 
From  triangle  CGF, 

8  +  a>-    '   '   (73) 


Or,  from  triangle  00/0,  , 

^(7  =  0/0,  =  2(R  -  R,)  sin  ±(b  -  a). 


Had  J.^F  been  the  original  curve,  b  would  have  been  known 
and  a  required. 

From  (71),  cos  a  =  cos  b  -f  _    P  _  .  .  (74) 

.a  —  it, 


angle  CFIfnte  given  by  formulas  (73)  and  (72). 
EXAMPLE.— A  2°  curve  compounds  with  a  4°  curve  at  sta. 
82  -f  30;  a  =  20°  30',  p  =  40  feet.     Find  number  of  new  P.C.C. 
and  distance  between  P.2\s. 

40 
From  (71),    cos  b  =  0.93667  -  2864  9  _  1433  7  =  0'90874- 

This  yields  b  =  24°  20',  and  b  -  a  =  3°  50'. 
The  change    in  P.C.C.  is  ^-8  =  1-917  stations;    the  P.C.C. 
number  is  therefore  82.30  -  1.917  =  sta.  80  -f  38.3. 


88        A   FIELD-MANUAL   FOR   RAILROAD   ENGINEERS. 


By  (72),  CFG  =  |(24°  20'  +  20°  30')  =  22°  25'. 

By  (73),  FC  =  40  X  2.62234  =  104.9  feet. 

SECOND  CASE. — The  terminal  branch  having  longer  radius. 
Let  CAB,  Fig.  47,  be  the  located 
curve  with  P.C.C.  at  At  and  let 
FK  be  the  tangent  in  which  the 
curve  is  required  to  end. 

The  distance  BK  =  p,  the  radii 
OA  =  R,  0,A  =  R, ,  and  angle 
AO,B  =  a  being  known,  it  will 
be  sufficient  to  find  angle  EO,'F 
in  order  to  get  the  angle  of  ad- 
vance, AOE  —  a-  b.  Draw  OL 


Fra.  47. 
Oi'OM and  0>OL, 


and   OiN  perpendicular    to  -Oi'F 
and    0,B.      From    the    triangles 


(R,  -  R)  cos  b  =  0/.ZV-J-  (Rl  -  R)  cos  a. 
But  Oi'N  =  KB  =  p ;  therefore 

(R!  —  R)  cos  b  =  p  -\-  (R,  —  R}  cos  a. 
P 


Whence 


cos  b  =  cos  a  -f- 


(75) 


Then  — =—  will  be  length  of  curve  from  A  to  E. 


Angle  KFB  =  N0,0,'  =  00,0,'  -  N0,0. 
But   00, 0,'  -  90°  -  l(a  -  b)    and    N0,0  =  90  -  a. 

'.    KFB  =  [90°  -  l(a  -  b)]  -  [90  -  a]  =  K«  +  ft)- 
From  triangle  KFB, 

FB  =  siu  i(a  i   ft)  =  p  •  cosec  *(a  +  &)'   '     '    •     (76) 

Or,  from  triangle  0,00,',  since  0,0,'  =  FB, 
FB  =  2(R,  -  72)  sin  |(o  -  b). 


LOCATION. 


89 


If  AEF\\n<\  been  the  located  curve,  b  would  have  been  given 
and  a  required.     From  formula  (75), 


cos  a  =  cos  6  —  TT- 


P 


It,  -  R' 


(77) 


EXAMPLE. — A  5°  curve  compounds  at  sta.  60  with  a  2°  curve, 
and  the  P.T.  is  at  sta.  80.  What  will  be  the  number  of  P.C.C. 
if  the  P.T.  fall  in  a  tangent  81  feet  inside  of  terminal  tangent? 
Here  a  =  40°. 


81 


By  (75),        cos  b  =  0.76604  +  -^  =  0.81316. 


1719 


Hence  b  =  35°  36'  and  a  —  b  =  4°  24',  corresponding  to  220 
feet  around  the  2°  curve.  The  number  of  the  new  P.C.C.  is 
therefore  62  +  20, 

angle  KFB  =  £(40°  0'  +  35°  36')  =  37°  48', 


and 


FB  =  Sl  X  1.63157  =  132.16  feet. 


124.  Given  a  Located  Compound  Curve  to  Find  Necessary 
Change  in  P.  C.  C.  and  Radius  of  Second  Branch  to  make  the 
P.T.  fall  in  a  Tangent  Parallel  to  First  Terminal  Tangent 
and  in  a  Point  on  the  Same  Radial  Line. 

FIRST  CASE.— Second  branch  having  shorter  radius. 

In  Fig.  48,  OB=R,  01B=R,  angle 
a  and  HO  =  p  are  known.  O^E=R^ 
and  angle  b  must  be  found  ;  then 

— —  =  BE  will  be  the  change  in 

P.C.C. 

Produce  first  branch  to  K,  where 
OK  is  parallel  to  0,  C.  Since  BOK 
=  BO,  C,  B,  K,  and  C  lie  in  the  same 
straight  line;  and  since  EO^F  — 
EOK,  E,  F,  and  K  lie  in  the  same 
straight  line.  Therefore 

{a,     and    KFH=$b. 


FIG.  48. 


90        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

From  triangles  KFH and  KCG, 

HK       OK       OH  p 


But  FH=  0i  Z  =  (B-Bi)  sin  a. 


.'.     tan  ^b=  tan  \a 


P 


(R-  A)  sin  a' 
From  triangles  00,  L  and  002 M, 

(R  —  Rz)  sin  b  =  (R  -  Ri)  sin  a. 


When 


(78) 


(79) 


Had  ^l^F  been   the  first  curve  located,  5  and  ^?2  would  be 
known,  a  aud  J?i  required. 
From  the  figure,  reasoning  as  before, 


tan  \a  — 


P 


i (80) 


and 


SECOND  CASE.—  Second  branch  having  longer  radius. 


FIG 


(81) 


In  Fig.  49  let  AB  be  the  located  curve,  JS'jP'the  curve  required, 
OA  =  R,  0,A  -  Rlt  0*E  =  A,  FB  =  p. 


LOCATION.  91 

7?a  and  angle  b  are  wanted,  angle  a  being  known. 
We  can  show,  as  in  first  case,  that 

HFK  =  lb,     HBL  =  \a, 

OM  =  KF  =  LB  =  (/?,  -  E)  sin  a; 
and  hence 

HL     HK  .    p 
t™y>=Bl=j£+2L. 

Or  inserting  values, 

tan  Ib  =  tan  \a  -f  — ——} — (82) 

(#1  —  E]  sin  a 

Angle  b  now  becomes  known  and  — ~ —  =  -A-Z?  in  chains,  which 

is  the  change  in  position  of  P.C.C. 
From  triangles  OOiJl/aud  002Jf, 

(JS2  -  R)  sin  6  =  (^  -  7?)  sin  a 


Had  the  new  tangent  fallen  outside  the  old  one,  we  should  have 
had 

.     .     .     (84) 


VC*M     Tk  \M     — —      Ul*«-l     -K1S  /    •»•»  T»  •  »» 

(#2  —  .R)  sin  6 
and 


(85) 


125.  Having  a  Located  Compound  Curve,  to  Find  the 
Change  in  P.C.C.  and  Radius  of  Second  Branch  in  order  to 
Cause  P.  T.  to  Fall  at  a  New  Point  in  Terminal  Tangent. 

FIKST  CASE. — Second  branch  having  shorter  radius. 


92        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

In  Fig.  50  let  NAB  be  the  located  curve,  and  C  the  point  where 
P.T.  is  required  to  fall.  Let  BG  =  k,  OA  =  R,  0,B  -  JR,,  and 
angle  0\ OH  =  a  be  known;  angle  b  and  R?  are  required. 


Extend  first  branch  to  F,  making  OF  parallel  to  OiB.  A,  B, 
and  Flie  on  a  straight  line,  for  angles  AOiB and  AOF&re  equal; 
likewise  E,  C,  and  F  lie  on  the  same  straight  line. 

From  triangles  GBFznd  OOF, 

OB      CB  k 


But      OF  -  HM  =  (R- 


. :  cot  46  =  cot  \a  — 


cos  a)  =  (R  —  Rt)  vers  a. 
k 


(R— Hi)  vers  a 
From  triangles  OOiH  and  00*L,  since  0,P  =  k, 
(R  -  /?,)  sin  b  =  (R-  -K,)  sin  a  -  A:. 

Whence 

A;  -  (R  -  Ri)  sin  o 


(86) 


(87) 


Then  b  —  a  divided  by  D  gives  arc  A  K    With  radius  R?  locate 
the  curve  EC  from  C  or  JK 


LOCATION. 


93 


Had  NEC  been  the  located  curve,  R,  _Z?2 ,  and  6  would  have 
been  known,  Ri  and  a  required.     In  this  case 


cot  \a  =  cot  \b  — 


,      ....     (88) 


(R  —  Rt)  sin  & 


(89) 


SECOND  CASE. — Terminal  branch  liamng  longer  radius 

In  Fig.  51  let  NAB  be  the  located  and  NEC  ike  required  curve. 


Fia,  51. 


Let  CB  —  k  be  known.     Then,  as  in  the  first  case, 


GC  _QB        k 
-~-_  —  _— . 


Ri  -  R)  versa 
and  (Rt  -  R)  sin  a  =  (R*  -  R)  sin  b  -f  k  ; 


whence 


(Rl  —  R)  sin  a  —  k 
sind        ~~* 


.      90) 


(91) 


94        A    FIELD-MANUAL    FOR   RAILROAD    ENGINEERS. 

Had  NECbuen  located  and  NAB  required,  the  equations  would 
have  been 


and 


cot  \a  =  cot  |6  + 

in. 
&  = 


#a  -  R)  vers  b  ' 
-  R)  sin  b  +  k 


sin  a 


(92) 
(93) 


In  either  of  these  two  cases  if  k  is  unknown  and  the  new  radius 
given  or  assumed,  the  desired  angle  and  the  value  of  k  may  be 
found  from  the  foregoing  equations.  Or,  knowing  the  new  angle, 
the  new  radius  and  value  of  k  may  be  found  from  the  same 
equations. 

126.  To  Replace  a  Curve  of  Given  Radius,  which  unites 
Two  Tangents  with  Known  Intersection-angle,  by  a  Three- 
centered  Compound  Curve. 

In  Fig.  52    let  OA  =  R   be   the   radius  of    located  curve, 


02  (7=  Oi'A  =  Rv  the  radius  of  terminal  portions  of  the  three- 
centered  curve,  and  the  other  notation  as  shown  in  the  figure. 

Draw  0202',  and  draw  FOH perpendicular  thereto.     From  tri- 
angles O^H  and  0*OH, 

0*H  =  (R,  -  R,)  sin  i/t  =  (R*  -  R)  sin  |I.  .    .    .     (a) 

Suppose  It*  and  Ri  to  be  assumed  ;  then  equation  (a)  yields 


'     (94) 


LOCATION.  95 

Then  AO*E  =  CO*G  =  \(I  -  /,).      .     .     .     (95) 

Suppose  AOi'E,  CO^G,  and  7?2  to  have  been  assumed.     From 
(95)  find  /i  ;  then,  from  equation  (a), 


(96) 


EXAMPLE.  —  Given  a  4°  curve,  /  =  38°,  and  the  terminal 
brunches  composed  of  a  2°  curve  for  two  stations,  to  find  Ri  and 
Di  for  the  central  portion. 

Here  L  =  38°  -  2(2  X  2)°  =  30°. 

From  Table  I,  R*  =  2865  ft.,     R  =  1432.7  ft. 
Whence  Ri-R=  1432.3  ft. 

Log  1432.3       =  3.15603 
"    sin  19°  0'  =  9.51264 


2.66867 
sin  15°  (X  =  9.41300 


.-.     log  1801. 1  =  3.25567 

Therefore  R,  =  2865  -  1801.7  =  1063.3  ft.,  and,  by  Table  I, 
Dl  =  5°  23'. 4,  nearly  enough. 

127.  To  Substitute  a  Curve  of  Given  Radius  for  a  Tangent 
uniting  Two  Curves. 

In  Fig.  53  let  the  tangent  BC  =  t,  OB  =  R,  01C=R1,  and 
0-iA  —  Ri  be  known. 

Angles  a,  I,  and  c  must  be  found  in  order  to  substitute  curve 
AE  for  the  system  ABCE. 

Draw  OF  parallel  to  BC,  then  O^F=  Rt  —  R,  and,  from  triangle 
OOtF, 


00,  =  -.-   -, ;  =  t.  cosec  d  =  \/(R,  -  R)*  -f  <».      .     (98) 
sin  fl{ 


96        A   FIELD-MANUAL   FOR   RAILROAD    ENGINEERS. 

Now  in  triangle  00\0<i  three  sides  are  known  aiid  the  angles 
c  and  e  may  be  computed.    Thus  if  s  is  the  half-sum  of  the  sides, 


Angle  e  may  be  found  in  like  manner,  then  b  =  180°  —  (e  ~\-  d), 
and  a  =  c  —  b. 

Points  A  and  JSTmay  now  be  located  and  the  curve  traced. 

EXAMPLE. — A  3°  and  a  5°  curve  are  united  by  a  tangent  500 
feet  long.  Replace  by  a  2°  curve. 

Here         K,  -  R  -  1910  -  1146  =  764  feet. 

500 
By  (97),        tan  d  =  —  =  0.65444  =  tan  33°  12' 

By  (98),          00,  =  913.1  feet. 

In  triangle  OOiO^,  00l  =  913.1,  OiOa  =  954.9,  and  00a  = 
1718.7  feet.  Solving  for  e  and  c, 

e  =  133°  36',     c  =  23°  0'.     Then     &  =  13°  12',     a  =  »°  56'. 
ARTICLE  10.    TRACK  PROBLEMS. 

128.  Reversed  Curves  should  never  be  employed  on  main 
lines  because  of  the  shock  due  to  sudden  reversal  of  curvature 
and  superelevation  of  outside  rail.  A  short  tangent  should  be 
interposed  between  the  two  curves,  which  may  ordinarily  be 
done  by  changing  the  end-points  of  the  curve,  or  slightly  altering 
the  radius.  If,  however,  transition  curves  are  employed  to  ease 


LOCATION. 


97 


off  both  curves,  there  would  seem  to  be  no  objection  to  the  use  of 
curves  of  contrary  flexure,  provided  the  track  may  be  kept 
always  iii  perfect  condition.  In  yards,  crossovers,  and  where 
connection  is  made  with  existing  track,  reversed  curves  may  be 
employed,  and  are  often  imperative. 

129.  Having  a  Located  Curve  Intersected  by  a  Straight 
Line,  to  Connect  them  by  Another  Curve. 

Either  the  radius  of  the  joining  curve  may  be  given,  or  else  the 
point  on  first  curve  at  which  the  junction  must  be  made.  The 
angle  between  a  tangent  to  located  curve  at  the  point  of  meeting 
and  the  straight  line  must  be  measured.  Four  possible  cases 
occur. 

FIRST  CASE. — Joining  curve  tangent  to  located  curve  internally 
and  on  same  side  of  cutting  line  as  center. 

In  Fig.  54  let  GF  be  joining  curve,  with  center  Oi  and  radius 
EL  Let  radius  of  located  curve  OF  =  E.  Draw  O^G  and  OH 
perpendicular  to  the  cutting  line  produced,  and  O^K  parallel  to 
AH.  If  Ri  is  known,  we  must  determine  angle  b,  a  having  been 


FIG.  54. 


measured;  then  b  —  a  gives  the  length  of  arc  from  A  to  F where 
the  P.C.C.  is  to  be  located.     In  the  triangle  KOOi  we  have 

OK  =  OH  -  R,    and     00,  =  R  -  R,. 


Then 


cos  b  = 
b-  a 


R  cos  a  —  Rl 


R-Rl 

=  arc  AF. 


(99) 


Had  Fbeen  given,  we  should  have  b  —  a -\-AOF,  and,  from  (99), 
R  (cos  a  —  cos  b}      R  (cos  a  —  cos  b)       . 

Si  i  J==    — =: __„„ .       (1UU) 

1  ,—  cos  b  vers  b 


98        A    FIELD-MANUAL   FOE   RAILROAD    ENGINEERS. 


EXAMPLE. — A  1°  curve  is  cut  by  atangcut  that  makes  au  angle 
of  64°  32'  with  tangent  to  curve.  Unite  by  means  of  a  4°  curve. 

By  (99),  cos  b  =  0.24000  =  cos  76°  07',  and  therefore  b  -  a  = 
11°  35',  making  AF,  of  figure,  11.58  stations. 

SECOND  CASE.  —  Joining  curve  tangent  internally  to  located 
curve  but  on  opposite  side  of  cutting  line  from  center  of  located 
curve. 

In  Fig.  54  let  arc  ME,  with  center  02  and  radius  1?2 ,  be  the 
joining  curve.  From  the  figure, 


cos  d  = 


H  cos  a  -\-  J?2 
R-R* 


(101) 


Then  arc  AE  =  a  -  d  divided  by  D,  and  c  =  180°  -  d. 
Had  the  point  E  been  given   and  JR3  required,  it  would  have 
been,  from  (101) 

7?(cos  d  —  cos  a) 


It*  = 


(102) 


1  -j-  cos  d 

EXAMPLE. — Take  the  same  example  as  in  first  case.     Here, 
By  (101),        cos  d  =  0.9068  =  cos  24°  56'. 
Then  64°  32'  -  24°  56'  =  39°  36', 

equivalent  to  39.600  stations  around  curve  from  A  to  E. 

THIRD  CASE. — Joining  curve  tangent  externally  to  located  curve, 
with  center  on  same  side  of  cutting  line. 

Lr 


FIG.  55. 


In  Fig.  55  let  arc  5(7,with  center  0,  and  radius  Ri ,  be  the  join- 
ing curve.  Draw  0,E  parallel  to  CF,  aud  OjCand  OF  perpen- 
dicular thereto. 


LOCATION.  99 


From  the  figure, 

(R  +  RJ  cos  b  =  R  cos  a  - 
R  cos  a  — 


(103) 


Then  d  =  180  —  b,  and  AOB  =  b  —  a.     The  curve  may  now  be 
traced  on  the  ground. 

If  AC  is  wanted,  we  have  AC  =  (R  +  R\)  sin  b  —  R  sin  a. 

If  the  point  B  is  fixed  and  R!  required,  there  results,  from  (103), 

=  B  (cos  »-  cos  » 
1  +  cos  6 

EXAMPLE.  —  Take  the  example  given  for  the  first  and  second 
cases 
By  (103), 

5730x0.43-1432.5 
COS  b  ^   —5780  +  1488.6         =  °'144  =  «»  81    ^ 

b  -  a  =  81°  44'  -  64°  32'  =  17°  12',  equivalent  to  17.2 
stations  on  located  curve  from  A  to  B.   Angle  d  =  180°  —  81°  44' 
=  98°  16',    equivalent   to  24.567  stations  from  B  to  C  on  the 
4°  curve. 

FOURTH  CASE.  —  Joining  curve  tangent  externally  to  located  curve, 
with  center  on  opposite  side  of  cutting  line. 

Let  0a,  Fig    55,  be  center  of  joining  curve,  R*  its   radius. 
From  the  figure, 

(R  +  /?„)  cos  c  =  R  cos  a  +  R2. 
R  cos  a  +  7?2 

•••cosc=     U  +  K     ......   •   •  •  •   (105> 

If  Mis  fixed  and  R2  required,  (105)  yields 

„        .K(cos  c  —  cos  a)       7?(cos  c  —  cos  a) 

J-12  =  -  ;  -  .  .       (1UO) 

1  —  cos  c  versm  c 

EXAMPLE.  —  Take  same  example  as  in  preceding  cases. 
By  (105),  cos  c  =  0.54403  =  cos  57°  02'. 

Then  a  -  c  =  64°  32'  -  57°  2'  =  7°  30', 


100     A    FIELD-MANUAL   FOR    RAILROAD    ENGINEERS. 


calling   for   a  distance   of   7.50  stations  from  A  to  M  around 
1°  curve.     From  Mto  H  011  4°  curve  is  14.258  stations. 

130.   To  Locate  a  Y 

A  Y  is  made  up  of  a  system  of  tracks  so  arranged  as  to  admit 
of  turning  an  entire  train.  Three  of  the  most  used  arrangements 
are  given  below. 

FIRST  CASE. — One  branch  of  Y  a  straight  line. 

This  is  only  the  special  case  of  the  last  problem  in  which  the 
cutting  line  becomes  tangent  to  both  curves.  In  Fig.  56,  if  any 


FIG.  56. 


one  of  the  points  A,  B,  or  G  is  given,  the  others  may  be  located 
by  finding  the  angles  c  and  6.  Draw  O^E  parallel  to  CA  ;  then 
in  triangle  OOiE 

RJcosb  =  R  -  EL 


.  •.  cos  b  = 


R- 


(107) 


This  follows  at  once  from  (103)  by  making  angle  a  —  0.  Then 
angle  c  =  180  —  b.  If  AB  were  a  located  curve  and  the  point 
B  given,  formula  (107)  would  furnish  us  a  value  for  Rt. 

Another  solution  is  to  produce  the  tangent  at  B  to  cut  AC  at  F; 
then  AF  =  FG  =  BF.  Join  F  with  0  and  0,  ;  it  can  easily  be 
seen  that  angle  OFOi  =  90°,  and,  by  geometry, 


BF= 


Therefore 


BF 

— 


R, 


(108) 
(109) 


and 


=  "Jr~4/£ (HO) 


LOCATION. 


101 


EXAMPLE.— Let  AB  be  a  3°  curve,  BC  a  6°  curve,  the  point  A 
at  station  180. 
Tty  (107), 


The  number  of  B  is  180  +  23.511  =  203  +  51.1.     Angle  e  = 
109°  28',  equivalent  to  18.244  stations  on  the  6°  curve. 

SECOND  CASE.  —  The  three  Ranches  curved  and  convex  towards 
each  other. 

Given^the  three  radii  and  any 
one  of  the  points  A,  B,  or  0, 
Fig.  57,  we  have  only  to  find  the 
angles  at  the  center,  then  divide 
these  angles  by  the  degrees  of 
the  respective  curves  to  get  their 
lengths  and  locate  the  three 
branches. 

In  the  triangle  00i02,  letting 
00,  =  I,  0,0a  =  m,  002  =  n, 


FIG.  57. 


we  shall  have,  by  trigonometry, 


cos  ia  = 


+  R,  + 


(111) 


Angles  b  and  c  may  be  found  in  like  manner. 

The  angles  may  be  found  otherwise  by  letting  fall  a  perpen- 
dicular from  one  vertex  upon  the  opposite  side,  
…[truncated]